Official Quant thread for CAT 2013

MBA CAT 2024
18486
@saurabhlumarrai said:
In a test in which 250 students appeared.180 passed in mathematics,100 passed in english, and 130 passed in economics,75 passed in only one subject and 160 passed in only two.10 students didn't passed in any subject.Find the number of students who passed in all three subjects?a)2b)5c)8d)75e)Data Insufficient
b- 5..


18487
@saurabhlumarrai said:
In a test in which 250 students appeared.180 passed in mathematics,100 passed in english, and 130 passed in economics,75 passed in only one subject and 160 passed in only two.10 students didn't passed in any subject.Find the number of students who passed in all three subjects?a)2b)5c)8d)75e)Data Insufficient
Total = 250 Students.
M = 180
Eng = 100
Eco = 130
Only 1 = 75
Only 2 = 160
None = 10.

Now, Only One + Only Two + All Three = 250 - 10 = 240
And, M + Eng + Eco = 180 + 100 + 130 = 410.

Thus, (Only Two) + 2*(All Three) = 410 - 240 = 170.
=> 2*All Three = 170 - 160 = 10.

So, All Three = 5.
18488
@saurabhlumarrai said:
In a test in which 250 students appeared.180 passed in mathematics,100 passed in english, and 130 passed in economics,75 passed in only one subject and 160 passed in only two.10 students didn't passed in any subject.Find the number of students who passed in all three subjects?a)2b)5c)8d)75e)Data Insufficient
5?
d + e + f = 160
n = 10
a + b + c + d + e + f + g + n = 250
a + b + c + 2(d + e + f) + 3g = 410
d + e + f + 2g = 410 - (250 - 10)
160 + 2g = 170
g = 5
18489
@meenu05 said:
The prime cost of an article was 3 time the value of materials used . The cost of raw materials in the ratio 3:7 and that of productive wages in the ratio 4:9 . Find the prime cost of an article which was formerly made for 41 ?
Cost = 41 = 3*Cost of RM
=> Cost of RM = 41/3
Thus, Cost of PW = 41*(2/3)

Increase RW by 7/3 and PW by 9/4 and add to get the new cost. !!
18490
@saurabhlumarrai said:
In a test in which 250 students appeared.180 passed in mathematics,100 passed in english, and 130 passed in economics,75 passed in only one subject and 160 passed in only two.10 students didn't passed in any subject.Find the number of students who passed in all three subjects?a)2b)5c)8d)75e)Data Insufficient
I+II+III+null = 250
75+60+III+10=250
III=5...
18491

P and Q are filling pipes which can fill a tank in 15 and 20 minutes respectivley. R is an emptying pipe which can empty the full in 30 minutes. THe 3 pipes are opertaed continously one after the other in the order of P Q R each being kept opened for 2 minutes until the tank is filled. After how much time will the tank be full?

18492
@vbhvgupta said:
P and Q are filling pipes which can fill a tank in 15 and 20 minutes respectivley. R is an emptying pipe which can empty the full in 30 minutes. THe 3 pipes are opertaed continously one after the other in the order of P Q R each being kept opened for 2 minutes until the tank is filled. After how much time will the tank be full?
P = 2/15
Q = 2/20 = 1/10
R = - 2/30 = - 1/15.

Now, [ 2/15 + 1/10 - 1/15 ] = 1/15 + 1/10 = (2 +3)/30 = 5/30 = 1/6.
Five Rounds => 5/6 Filled.

Sixth Round = 5/6 + 2/15 = (25+5)/30 = 29/30 Filled.
Now, 1/30 will be filled by Pipe Q in 2/3 minute.

So, Total Time = 5*6 + 2 + 2/3 = 32.667 minutes.
18493
@vbhvgupta said:
P and Q are filling pipes which can fill a tank in 15 and 20 minutes respectivley. R is an emptying pipe which can empty the full in 30 minutes. THe 3 pipes are opertaed continously one after the other in the order of P Q R each being kept opened for 2 minutes until the tank is filled. After how much time will the tank be full?
let the total capacity of the tank be 60lt
P = 8lt/2 min
Q = 6lt/2 min
R = -4lt/2min
so total = 8+6-4 = 10lt/6 mins
hence 6*6=36 mins mein full fill ho jyga...
18494
@Logrhythm said:
let the total capacity of the tank be 60ltP = 8lt/2 minQ = 6lt/2 minR = -4lt/2min so total = 8+6-4 = 10lt/6 minshence 6*6=36 mins mein full fill ho jyga...
It will be filled in the 33rd Minute itself. We don't need to go further.
18495

A Triswitch mixer grinder operates in 3 stages of speed in revolutions per min . The speed of the motor with some load in the second stage varies as a square of the speed in stage 1 and that in stage 3 varies as a cube of that in stage 2 . If the mixer motor makes 50 revolutions in 3 mins in stage 1and its speed in 2 and 3 with the same load is 2500 and 12500 revolutions per minute respectively . Et will be the speed of the motor that is revolutions per minute in stage 3 if at the sane load motors speed in revolutions per minute is 25 revolutions in 6 minutes in stage 1 ?

18496
@Estallar12 said:
It will be filled in the 33rd Minute itself. We don't need to go further.
ohhh...yes :)
18497
@meenu05 said:
A Triswitch mixer grinder operates in 3 stages of speed in revolutions per min . The speed of the motor with some load in the second stage varies as a square of the speed in stage 1 and that in stage 3 varies as a cube of that in stage 2 . If the mixer motor makes 50 revolutions in 3 mins in stage 1and its speed in 2 and 3 with the same load is 2500 and 12500 revolutions per minute respectively . Et will be the speed of the motor that is revolutions per minute in stage 3 if at the sane load motors speed in revolutions per minute is 25 revolutions in 6 minutes in stage 1 ?
Speed in Stage 2 = k*(50/3)^2 = 2500k/9
=> k = 9.

Speed in Stage 3 = n*(2500)^3
=> n = 12500/625*25*10^6 = 1/1250000.

For Stage 1 Speed = 25/6
Speed in Stage II = 9*(25/6)^2 = 625/4
Speed in Stage III = n*(625/4)^3 = 25^6/64*1250000.
18498
@DeAdLy ...its from one of my mocks..ment for CMAT...but you know how to solve this..pls let me know..its urgent
18499
@Logrhythm said:
let the total capacity of the tank be 60ltP = 8lt/2 minQ = 6lt/2 minR = -4lt/2min so total = 8+6-4 = 10lt/6 minshence 6*6=36 mins mein full fill ho jyga...
OA 32 2/3
18500
@Unternehmer said:
@DeAdLy ...its from one of my mocks..ment for CMAT...but you know how to solve this..pls let me know..its urgent
Which question ??
18501
@ishu1991 ..can you please tell me how did you get 9 diagonals..stepwise??
18502
@Unternehmer said:
@DeAdLy ...its from one of my mocks..ment for CMAT...but you know how to solve this..pls let me know..its urgent
yes i know but i tought they might have been solved by some one here uptill now

18503
@Estallar12
In a machine a series of words is fed in which then gives an output after following a certain number of steps.

Input: Sale Fake Hence Gate His

Step 1: Sale His Fake Hence Gate

Step 2: Sale His Hence Fake Gate

Step 3: Sale His Hence Gate Fake

Step 3 is the output.

What will be the second step if the input to the same machine is

Input: Play Hope Greece Soul Watch

a.Soul Watch Play Hope Greece
b.Watch Soul Play Hope Greece
c.Watch Play Hope Greece Soul
d.Watch Soul Play Greece Hope
18504
@Estallar12 said:
Which question ??
lo the quant king is himself here

refer to page 987 some post is there
18505
@Unternehmer said:
@Estallar12In a machine a series of words is fed in which then gives an output after following a certain number of steps.Input: Sale Fake Hence Gate HisStep 1: Sale His Fake Hence GateStep 2: Sale His Hence Fake GateStep 3: Sale His Hence Gate FakeStep 3 is the output.What will be the second step if the input to the same machine isInput: Play Hope Greece Soul Watcha.Soul Watch Play Hope Greeceb.Watch Soul Play Hope Greece c.Watch Play Hope Greece Sould.Watch Soul Play Greece Hope
b