@chandrakant.k said:
please post it in the way you post question. last time i had to tilt my head to understand the solution
bhai mafi...
@veertamizhan said:In triangle ABC, AB=6 and AC=9. AD is the internal angle bisector of angle A and D lies on BC such that BD=2, and CD=3. Find the length of AD.
4root3 ?
@vbhvgupta said:
lets say in normal case b1 does 24(1/3rd) units and in 2nd case 6 ubits of work is done by b2so he would do 18 units now as they have proved y=2
in tat case b1 would be doing 1/3 - (1/6) = 1/6
so 1/6th of 72 = 12
but i have taken that he does 18 units
in tat case b1 would be doing 1/3 - (1/6) = 1/6
so 1/6th of 72 = 12
but i have taken that he does 18 units
totally absurd
@veertamizhan said:@Pratishruti yes, kaisai?
Let AD=x and angle BAD=angle DAC=theta and AD=x
there are two triangles ABD and ADC
calculate cos theta for both triangles and equate
(6^2+x^2-2^2)/2*6*x = (x^2+9^2-3^2)/2*x*9
on solving this will give the value of x as root 48
@veertamizhan said:In triangle ABC, AB=6 and AC=9. AD is the internal angle bisector of angle A and D lies on BC such that BD=2, and CD=3. Find the length of AD.
Answer : 4root (3)
HINT: Using cosine law for triangle ABC and ABD.
HINT: Using cosine law for triangle ABC and ABD.
@veertamizhan said:@Pratishruti yes, kaisai?
Let AD=x apply COS C in ABC and ADC and equate
(81 + 25 -36) /2*9*5 =( 81 + 9-x^2) /2*9*3
x=4_/3
(81 + 25 -36) /2*9*5 =( 81 + 9-x^2) /2*9*3
x=4_/3
@chandrakant.k @vbhvgupta @DeAdLy
There are 3 white balls and 4 black balls in a bag, and a set S = {0, 1}. Now one ball is chosen from the bag and if it's white then the set S remains the same and if the ball chosen is black then the element '1' is replaced by '–1' in the set S. After choosing one ball and fixing the set S, three numbers α, β, γ (not necessarily distinct) are chosen from the set S. Then what is probability of having real and finite number of solutions of the equationxα + xβ + γ = 0
OPTIONS
1)
2)
3)
4) None of the above
OPTIONS
1)
2)
3)
4) None of the above
@saurav205 said:@chandrakant.k@vbhvgupta@DeAdLyThere are 3 white balls and 4 black balls in a bag, and a set S = {0, 1}. Now one ball is chosen from the bag and if it's white then the set S remains the same and if the ball chosen is black then the element '1' is replaced by '–1' in the set S. After choosing one ball and fixing the set S, three numbers α, β, γ (not necessarily distinct) are chosen from the set S. Then what is probability of having real and finite number of solutions of the equationxα + xβ + γ = 0OPTIONS1) 13/28 2) 1/2 3) 15/28 4) None of the above
Sorry about the options.
@saurav205 said:Sorry about the options.
kaisa mazzak hai bhai ye...ye mba ke students dhoond rahe hai ya aryabhatta ka successor 
@Logrhythm said:kaisa mazzak hai bhai ye...ye mba ke students dhoond rahe hai ya aryabhatta ka successor
S for white={0,1
. Prob of selecting white ball=3/7
Prob of favourable outcome=6/8
S for black={0,-1}
S for black={0,-1}
. Prob of selecting black ball=4/7;
Prob of favourable outcome=3/8
Required prob= (3/7)(6/8) + (4/7)(3/8)=15/28
Required prob= (3/7)(6/8) + (4/7)(3/8)=15/28
@veertamizhan said:@amresh_maverick aren't you the famous Maverick?
what is your matbal ? bouncer tha
In triangle ABC, sides AB, AC and BC are extended till Q,P and R such that AC=AP, BC=CR and AB=BQ. It is known that the area of triangle ABC is 10 sq. cm.
Find area of PQR.
a 40
b 70
c 80
d 90
(attached:figure)
please show your approach as well :D
a 40
b 70
c 80
d 90
(attached:figure)
please show your approach as well :D
@vbhvgupta
the guys V,R,B
Work is given in the ratio 2:3:5
Assume 30 units of work(For simplicity!
)
Now V would do 2/10 of 30 units in 12 days(6 units in 12 days!)
hence 6/12=0.5 units in one day!
Work rate of V,R,B=1:2:3
hence V:R:B=0.5units:1unit:1.5units(units per day of each individual)
Question demands work done after 8 days!
So 8*0.5+8*1+8*1.5=4+8+12=24units done!(in 8 days!)
Now finally the ratio=Work completed in 8 days/Total work
=24/30=4/5
the guys V,R,B
Work is given in the ratio 2:3:5
Assume 30 units of work(For simplicity!
)Now V would do 2/10 of 30 units in 12 days(6 units in 12 days!)
hence 6/12=0.5 units in one day!
Work rate of V,R,B=1:2:3
hence V:R:B=0.5units:1unit:1.5units(units per day of each individual)
Question demands work done after 8 days!
So 8*0.5+8*1+8*1.5=4+8+12=24units done!(in 8 days!)
Now finally the ratio=Work completed in 8 days/Total work
=24/30=4/5