d) the second equation is the equ of a circle with centre at (3,-20 ) and radius 3......at one of the points on the circle(3,1) ( at angle- 90 degrees) the expression 3x+4y gives 13.......so option d.....looking for a better soln
2) by applying the logic that the farthest point from the circle is that point where the tangent touches it... (by this method we get both, the max and the min value)
(x-3)^2 + (y+2)^2 = 3^2 is our equation of the circle with center at (3,-2) and radius = 3
I feel relieved to be on this thread again.....every other place seems to be full of irrelevant noise......this place is the most engaging yet the most tranquil place on pg...........keep the questions coming folks...........
yes answer is 16...there are 2 ways of doing it...1) by cauchy inequality..we have (x-3)^2 + (y+2)^2 = 9{(x-3)^2 + (y+2)^2}(3^2+4^2) >= (3(x-3) + 4(y+2))^225(x^2+y^2-(6x-4y-4)+9) >= (3x+4y-17)^225(x^2+y^2-(x^2+y^2)+9) >= (3x+4y-1)^225*9 >= (3x+4y-1)^23x+4y-1 =3x+4y =2) by applying the logic that the farthest point from the circle is that point where the tangent touches it... (by this method we get both, the max and the min value)(x-3)^2 + (y+2)^2 = 3^2 is our equation of the circle with center at (3,-2) and radius = 3using distance from center = radius|{3*3 + 4*(-2) - k}|/rt(3^2+4^2) = 3+/- (1-k) = 1514 =hence max is 16....
if four examiners can examine a certain number of answer books in 8 days by working 5 hrs a day, for how many hours a day would 2 examiners have to work in order to examine twice the number of books in 20 days?
A undertook a work to complete in 60 days. but just after 20 days he observed that only 1/5 of the project had been completed. to complete the work in the rest days min how many workers he had to increase if there were initially 75 workers were deployed for the work?
plz helpif four examiners can examine a certain number of answer books in 8 days by working 5 hrs a day, for how many hours a day would 2 examiners have to work in order to examine twice the number of books in 20 days?
plz helpif four examiners can examine a certain number of answer books in 8 days by working 5 hrs a day, for how many hours a day would 2 examiners have to work in order to examine twice the number of books in 20 days?
@Logrhythm xif the ratio of sines of angles of a triangle is 1:1:sqrt(2) then the ratio of square of the greatest side to sum of of the squares of the other two side is??
if the ratio of sines of angles of a triangle is 1:1:sqrt(2) then the ratio of square of the greatest side to sum of of the squares of the other two side is??
Q. A and B start moving towards each other simultaneously on a straight line from cities P and Q respectively. After travelling some distance, B takes a 30째 turn to his left with respect to his original direction. 2 hour after B turns, A takes a 90째 turn to his right. A travels 60 km after turning, before meeting B. They meet 10 hour after starting their journey. A and B together travel 170 km with time ratio 8:9 respectively before turning and arrive at the meeting point simultaneously. If A and B had not turned, after how many hours would they have met?
a) 34 +(12root3)/7 b)34+ (8root3)/7 c)34+ (16root3)/7 D)34 + (12root3)/5
plz helpif the ratio of sines of angles of a triangle is 1:1:sqrt(2) then the ratio of square of the greatest side to sum of of the squares of the other two side is??
same as the angles...this is a triangle with angles 45,45 and 90 and sides are in the ration 1:1:rt2
this is a standard result waise u shud remember this one..
36!-24!=24!(25*26*.............36 - 1)last 2 non zero digits of 24! are 36.last 2 digits of the term within brackets are 99(WHY????)So multiply to get last 2 digits which will be 64
How did u get last two digits of 24!...Can u pls explain..??
@Logrhythm xif the ratio of sines of angles of a triangle is 1:1:sqrt(2) then the ratio of square of the greatest side to sum of of the squares of the other two side is??
since the ratio of sines of angles is1:1:sqrt2..therfore it is a isoceles right angled triangle so d sides willl be x,x,sqrt2 x.. so the ratio of square of the greatest side to sum of of the squares of the other two side is 1:1
There are 3 lights which are switched on at interval of 54 seconds,48 seconds and 36 seconds respectively.Each light is kept on only for 3 seconds after which it is switched off.If all the lights are switched on simaltaneously at 5:00 a.m, how many times will they be switched on together between 6:00 am and 7:00 am.
my doubt is what should add in the numbers +1 sec,+2 sec or +3 sec.
for eg 1st one would be on at 55,56 and 57 and second one at 49,50,51.. So for which numbers should i take lcm ?
A undertook a work to complete in 60 days. but just after 20 days he observed that only 1/5 of the project had been completed. to complete the work in the rest days min how many workers he had to increase if there were initially 75 workers were deployed for the work?
