@pavimai said:yes got it..but 430 not in options
sorry my bad :banghead:
number of laddu's = 400+10*30 = 700 😁 😁
anyways you can always use the options in this question
@pavimai said:there are three equal containers that are completely filled with different water-alcohol mixtures with water and alcohol in the ratio 2:3,3:4,4:5 respectively,they are emptied into a bigger container .what fraction of the mixture in the bigger container should be replaced by water so that the resulting mixture has equal quantities of water and alcohol ??
first find the ratio of w:a in bigger container..
w/a = (2/5 + 3/7 + 4/9) / (3/5+ 4/7+ 5/9)
= 401/544
say k litres is replaced.
so, (401 + k)/544=1/1
k=143
fraction that should be replaced = 143/ (401+544)
= 143/945
@dream_IIMA : the first bracket is for number of laddus and the second one is for cost evaluation, both the brackets consider the entire box.
u can do it separately too.
like for 400 laddus.. 4000 is the constant amount.
for 410 laddus.. .. the price will be.. 410 *9.90 = 4059
for 420 laddus... the price will be 420* 9.80= 4116 .. n so on.
i just generalized it.
another way of doing this ques canbe. .. as u can see.. 410 and 9.90 ..
41, 99 sum upto 14. similarly for 420, it is 9.80, again 42+98 = 14, and so on..
(no rule it is, just looking at the numbers, i figured it out.)
u can check using options.. so for 600 it will be 8.00 or amount = 4800
for 500, it will be 9.00 amounts to 4500
for 700, it will be 7.00 amounts to 4900and lastly for 800, it will be 6.00, amount = 4800
so clearly, 700 maximises.
is it clear now?
w/a = (2/5 + 3/7 + 4/9) / (3/5+ 4/7+ 5/9)
= 401/544
say k litres is replaced.
so, (401 + k)/544=1/1
k=143
fraction that should be replaced = 143/ (401+544)
= 143/945
@dream_IIMA : the first bracket is for number of laddus and the second one is for cost evaluation, both the brackets consider the entire box.
u can do it separately too.
like for 400 laddus.. 4000 is the constant amount.
for 410 laddus.. .. the price will be.. 410 *9.90 = 4059
for 420 laddus... the price will be 420* 9.80= 4116 .. n so on.
i just generalized it.
another way of doing this ques canbe. .. as u can see.. 410 and 9.90 ..
41, 99 sum upto 14. similarly for 420, it is 9.80, again 42+98 = 14, and so on..
(no rule it is, just looking at the numbers, i figured it out.)
u can check using options.. so for 600 it will be 8.00 or amount = 4800
for 500, it will be 9.00 amounts to 4500
for 700, it will be 7.00 amounts to 4900and lastly for 800, it will be 6.00, amount = 4800
so clearly, 700 maximises.
is it clear now?
@chandrakant.k said:sorry my bad number of laddu's = 400+10*30 = 700 anyways you can always use the options in this question
now clear 
@ChirpiBird said:first find the ratio of w:a in bigger container..w/a = (2/5 + 3/7 + 4/9) / (3/5+ 4/7+ 5/9)= 401/544say k litres is replaced. so, (401 + k)/544=1/1k=143fraction that should be replaced = 143/ (401+544)= 143/945@dream_IIMA : the first bracket is for number of laddus and the second one is for cost evaluation, both the brackets consider the entire box. u can do it separately too. like for 400 laddus.. 4000 is the constant amount. for 410 laddus.. .. the price will be.. 410 *9.90 = 4059for 420 laddus... the price will be 420* 9.80= 4116 .. n so on.i just generalized it.another way of doing this ques canbe. .. as u can see.. 410 and 9.90 .. 41, 99 sum upto 14. similarly for 420, it is 9.80, again 42+98 = 14, and so on.. (no rule it is, just looking at the numbers, i figured it out.)u can check using options.. so for 600 it will be 8.00 or amount = 4800for 500, it will be 9.00 amounts to 4500for 700, it will be 7.00 amounts to 4900and lastly for 800, it will be 6.00, amount = 4800so clearly, 700 maximises.is it clear now?
thanks bhai :-)
@pavimai simple i got it nw
for first 400 price is 10
nw for nxt 100 9
nx 100 8
so on so ans is 7
7*700= 4900
@jain4444 said:6*10^3*BEL + 6*GIS = 10^3*GIS + BEL 5999*BEL = 994*GISBEL = 142 GIS = 857value = 75 + 142857 + 1425 + 47 + 2485 = 146889
ye thoda explain karo bhai
Find the no. of integral solution to lxl + lyl+ lzl = 15
@anuragu79 said:Find the no. of integeral solution to lxl + lyl+ lzl = 15
i have come across a simple funda to solve this equation..
|x|+|y|+|z|=a
4a^2 +2
so using this...ans will be 4*15^2+2=902
am i correct..if wrong correct me
@pavimai said:i have come across a simple funda to solve this equation..|x|+|y|+|z|=a4a^2 +2so using this...ans will be 4*15^2+2=902am i correct..if wrong correct me
Correct hai bhai...but what if there are 4 variables???
@anuragu79 said:Find the no. of integral solution to lxl + lyl+ lzl = 15
4*15^2 plus 2 equal to 902
find value of
1/ (3^2 - 2^2) + 1/ (7^2-2^2) +1/ (11^2 - 2^2).....................1/ (39^2 - 2^2)
5/41
31/41
18/37
10/41
@upudit0 said:Karan, the math wizard, writes all natural numbers in order which do not use any prime digit. His first few numbers are 1, 4, 6, 8, 9, 10, 11, 14,..etc. What will be the 100th number that Karan writes?(A) 144(B) 266(C) 488(D) 699(E) none of theseCAT :96.5solve more type but please stick to CAT level
is it 144
@pavimai said:is it 144
1 - 1 2 3
2 - 4 5
3- 6 7
4- 8
5- 9
6- 10
7-11 12 13
8-14 15
9-16 17
10-18
11-19
12-20
this pattern is repeating as 6 sets.. 100 modulo 6
remainder is 4.. the fourth number in the set.. ie 4..
so the number will have 4..
144
correct me if i am wrong..
or share any best approach
@upudit0 said:Karan, the math wizard, writes all natural numbers in order which do not use any prime digit. His first few numbers are 1, 4, 6, 8, 9, 10, 11, 14,..etc. What will be the 100th number that Karan writes?(A) 144(B) 266(C) 488(D) 699(E) none of theseCAT :96.5solve more type but please stick to CAT level
@upudit0 said:Karan, the math wizard, writes all natural numbers in order which do not use any prime digit. His first few numbers are 1, 4, 6, 8, 9, 10, 11, 14,..etc. What will be the 100th number that Karan writes?(A) 144(B) 266(C) 488(D) 699(E) none of theseCAT :96.5solve more type but please stick to CAT level
none of these hai kya ?
@pavimai said:1 - 1 2 3 2 - 4 5 3- 6 7 4- 8 5- 9 6- 10 7-11 12 13 8-14 15 9-16 17 10-18 11-19 12-20this pattern is repeating as 6 sets.. 100 modulo 6 remainder is 4.. the fourth number in the set.. ie 4..so the number will have 4..144 correct me if i am wrong..or share any best approach
good approach
but if the remainder is 4
then we should take the 4th term i.e 8
but if the remainder is 4
then we should take the 4th term i.e 8