@ravi.theja said:PQ is a chord of 6cm of a circle of radius of 5cm.Tangents to circle at P and Q meet at T..find lenght of TP
Is it 60/16???
Is it 60/16???
@codecatcher said:@bs0409 can u plzz explain the logic behind the formula u used ...???
I dont know the logic.
Got it from Varun Sir.....(i.e. @varun.tyagi )
Give all your respects to him...:D
In the xy-plane, if points (5, 2), (2, 5), and (-2, -5) are the vertex of a parallelogram, how many such parallelograms are possible?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 6
@bs0409 said:I dont know the logic.Got it from Varun Sir.....(i.e. @varun.tyagi )Give all your respects to him...In the xy-plane, if points (5, 2), (2, 5), and (-2, -5) are the vertex of a parallelogram, how many such parallelograms are possible?(A) 1(B) 2(C) 3(D) 4(E) 6
3??
@bs0409 said:I dont know the logic.Got it from Varun Sir.....(i.e. @varun.tyagi )Give all your respects to him...In the xy-plane, if points (5, 2), (2, 5), and (-2, -5) are the vertex of a parallelogram, how many such parallelograms are possible?(A) 1(B) 2(C) 3(D) 4(E) 6
3??
u don't need to know co-ordinate geometry ke formulae for this (as i don't remember any as of now)....observation se kara...
@bs0409 said:I dont know the logic.Got it from Varun Sir.....(i.e. @varun.tyagi )Give all your respects to him...In the xy-plane, if points (5, 2), (2, 5), and (-2, -5) are the vertex of a parallelogram, how many such parallelograms are possible?(A) 1(B) 2(C) 3(D) 4(E) 6
3??
u don't need to know co-ordinate geometry ke formulae for this (as i don't remember any as of now)....observation se kara...
u don't need to know co-ordinate geometry ke formulae for this (as i don't remember any as of now)....observation se kara...
@bs0409 said:I dont know the logic.Got it from Varun Sir.....(i.e. @varun.tyagi )Give all your respects to him...In the xy-plane, if points (5, 2), (2, 5), and (-2, -5) are the vertex of a parallelogram, how many such parallelograms are possible?(A) 1(B) 2(C) 3(D) 4(E) 6
3??
u don't need to know co-ordinate geometry ke formulae for this (as i don't remember any as of now)....observation se kara...
@bs0409 said:I dont know the logic.Got it from Varun Sir.....(i.e. @varun.tyagi )Give all your respects to him...In the xy-plane, if points (5, 2), (2, 5), and (-2, -5) are the vertex of a parallelogram, how many such parallelograms are possible?(A) 1(B) 2(C) 3(D) 4(E) 6
3?
@ChirpiBird said:3??
@Logrhythm said:3??u don't need to know co-ordinate geometry ke formulae for this (as i don't remember any as of now)....observation se kara...
Right .It is 3....
Find the sum of the all the numbers which are coprime to 300 and less than 300.
@bs0409 said:Is it 60/16???
If O is center of the circle and X is mid point of the chord PQ, then triangles PTX and OPX are similar
PT/PX = OP/OX
PT = PX*OP/OX = 3*5/4 = 3.75
PT/PX = OP/OX
PT = PX*OP/OX = 3*5/4 = 3.75
@bs0409 said:Right .It is 3....Find the sum of the all the numbers which are coprime to 300 and less than 300.
300/2 * 80 = 12000
@bs0409 said:Right .It is 3....Find the sum of the all the numbers which are coprime to 300 and less than 300.
it is given by (N/2)*Euler's of that number...
150*300(2/3)(1/2)(4/5) = 12000...
@bs0409 said:80 is the count of such numbers.I want the sum.......
answered wid out reading whole qstn..edited
In a plane There are 37 straight Lines, Of which 13 pass through the point A and 11 pass through the point B . Besides , No three lines pass through both points A and B, No two are parallel then the number of intersection points the lines have is equal to??
@bs0409 said:Right .It is 3....Find the sum of the all the numbers which are coprime to 300 and less than 300.
300/2*300(1/2)(2/3)(4/5) = 12000
@bs0409 said:Right .It is 3....Find the sum of the all the numbers which are coprime to 300 and less than 300.
If there is a number 'x' that is coprime to 300 then there also exists a number (300-x) that is also coprime to 300. Since there are 80 such numbers which are co prime to 300.
The sum = 80 * (300 -x + x)/2 = 80*150
Or in short = (N/2)*Euler number
@bs0409 said:In a plane There are 37 straight Lines, Of which 13 pass through the point A and 11 pass through the point B . Besides , No three lines pass through both points A and B, No two are parallel then the number of intersection points the lines have is equal to??
37c2 - (13c2 + 11c2) ??
@ravi.theja said:square of 5 ends with 25..square of 25 ends with 625..so here qr = 25 then p = 6 ==> pqr = 625 ==> (625)^2 = 390625 ..i=3 j=9 k =0.....product = 0
Like someone mentioned before, 376 ^ 2 =141376 too !!