Plz help....
What is the rate of simple interest for the first 4 years if the sum of rs 360 becomes rs 540 in 9 years and the rate of interest for the last 5 years is 6%?
@ani6 said:Plz help....What is the rate of simple interest for the first 4 years if the sum of rs 360 becomes rs 540 in 9 years and the rate of interest for the last 5 years is 6%?
i'm getting a negative rate of interest for the first 4 years.
i don't know if i'm doing a mistake. but i feel there is some error in the given data !
i don't know if i'm doing a mistake. but i feel there is some error in the given data ! @ani6 said:Plz help....What is the rate of simple interest for the first 4 years if the sum of rs 360 becomes rs 540 in 9 years and the rate of interest for the last 5 years is 6%?
is the answer 9.615% by any chance ?
The sum of the present ages of a father and his son is 99 years. When the father was as old as his
son is now, his age was four times the age of the son at that time. The ratio of the present ages of
the son and the father is???? @The_Loser ye bna do
son is now, his age was four times the age of the son at that time. The ratio of the present ages of
the son and the father is???? @The_Loser ye bna do
@TootaHuaDil said:The sum of the present ages of a father and his son is 99 years. When the father was as old as hisson is now, his age was four times the age of the son at that time. The ratio of the present ages ofthe son and the father is????
4 ?
@TootaHuaDil said:If K = 231 — 319, then how many positive divisors of K^2 are less then K but do not divide K?some one please elaborate the solution.
231 * 319 =3*7*11^2 * 29
no f factos ( f ) = 2 * 2 * 3 * 2 = 24
for its square (231 * 319)^2
no f factor ( F ) = 3^3 * 5 = 135
Some points.
1 ------------ N ----------------- N^2
DOTTED LINE REPRESENTS NO F FACTORS bw 1 to N to N^2
Also N is the middle factor of N^2 when all factors are arranged in increasing or decresing order.
so just find the
no f factors of N^2 less than N = (numbers of factors of N^2 - 1) / 2---------- EQ 1
factors of N less than N = N-1 ----- EQ 2
just subtract eq 1 - eq 2
here it is, (135 -1)/2 - (24-1)
= 67 - 23 = 44
no f factos ( f ) = 2 * 2 * 3 * 2 = 24
for its square (231 * 319)^2
no f factor ( F ) = 3^3 * 5 = 135
Some points.
1 ------------ N ----------------- N^2
DOTTED LINE REPRESENTS NO F FACTORS bw 1 to N to N^2
Also N is the middle factor of N^2 when all factors are arranged in increasing or decresing order.
so just find the
no f factors of N^2 less than N = (numbers of factors of N^2 - 1) / 2---------- EQ 1
factors of N less than N = N-1 ----- EQ 2
just subtract eq 1 - eq 2
here it is, (135 -1)/2 - (24-1)
= 67 - 23 = 44
@swapnil4ever2u said:bhai ye question mujhe kyun bta rha h.. maine nhi pucha.. maine wo area wala pucha tha..
sorry boss. wrong tag.
@TootaHuaDil said:The sum of the present ages of a father and his son is 99 years. When the father was as old as hisson is now, his age was four times the age of the son at that time. The ratio of the present ages ofthe son and the father is????
4:7
present ages: father = x , son = y
if the father was as old as his son is now , say a yrs ago .then ,
x-a=y ... (i) and x-a =4(y-a) ... (ii)
solving , we find a = 4y -x
put the value of a in eqn (i)
x/y=7/4 or in this case y/x = 4/7
x/y=7/4 or in this case y/x = 4/7
f-(f-s)=4(s-(f-s) )
s= 4(2s-f)
s=8s-4f
4f=7s
f/s=7/4 or s/f=4/7
guys a TSD problem...
A and B start at the same end of the pool which is 50m long.
The one who completes 20 laps is the winner.
The ratio of speed of A and B is 3:4.
How many times would they meet or cross each other by the time the faster one finishes the race..?....
p.s- whoever solves it please explain the solution too.