if p,q,r are in ap then 1/p,1/q,1/r are in H.P.If the squares of p,q,r are in hp then the terms are 1/p^2,1/q^2 & 1/r^2 which implies p^2,Q^2 & r^2 are in a.p. Am I interpreting the question wrong??
if p,q,r are in ap then 1/p,1/q,1/r are in H.P.If the squares of p,q,r are in hp then the terms are 1/p^2,1/q^2 & 1/r^2 which implies p^2,Q^2 & r^2 are in a.p. Am I interpreting the question wrong??
buddy, its not sayngi that the inverse of thethe square of the nos are in hp. it says their squares are in hp so, 1/p^2 , 1/q^2 and 1/r^2 are in ap
A set of data consists of the following 5 numbers: 0,2,4,6, and 8. Which two numbers, if added to create a set of 7 numbers, will result in a new standard deviation that is close to the standard deviation for the original 5 numbers? (A) -1 and 9 (B) 4 and 4 (C) 3 and 5 (D) 2 and 6 (E) 0 and 8
I took k = 1 LHS represents sum of 25 terms of the AP Since the average of 24 numbers is 775/24 the sum of 24 numbers is 775 (assuming k = 1) and the sum of 25 number is greater than 775.
q(x) is aquadratic eqn in x . it has a min. value of -28 when x=-3 . it has avalue of -10 when x=0 . find its value when x=4.a) 55b) 60c)65d)70
Let f(x)=ax^2+bx+c Now at x=0 value is 10 so c=-10 Minimum value occurs at x= -b/2a = -3 => b=6a And f(-3)=-28=> 9a-3b-10=-28=>b-3a=6 SOlve the 2 equations and get a=2 and b=12 Now f(4) = 70
@Cat.Aspirant123 If i take secnd statement where both are positive sum of roots is -b and product of roots is c so here we can sum of roots can never be grtr than product of roots so we can answer here no
x^2 + bx + c =0 is Sum of roots is greater den product of roots ?a) b is not greater den cb) b & c are positive integerseither/neither/1st/2nd/bothcan u tell me dis one sir ?
both the statements together....coz from (1) we can get prod=sum. eg- (x-2)^2