@Cat.Aspirant123
monday
@The_Loser said:ab no one is posting any ques, so take an easy one.dre are 100 articles n1, n2, n3... n100.They are arranged in all possible order.hw many arrangements wud be dre in which n28 wud always be before n29.
total ways/2 => in half the cases 28 will be before 29 and vice versa in the other half..
so its 100!/2
so its 100!/2
@ravi.theja
Shld be 0...
Let P= x-d, Q= x n R = x+d..
Given, 1/(x-d)^2 - 1/x^2 = 1/x^2 - 1/(x+d)^2
=>x^2(x^2 +d^2) = (x^2 - d^2)^2
=>3x^2 = d^2..
Nw, 2Q^2 + PR = 2x^2 + (x^2 - d^2), or, 2/3*d^2 + (d^2/3 -d^2)= 0..
@The_Loser said:ab no one is posting any ques, so take an easy one.dre are 100 articles n1, n2, n3... n100.They are arranged in all possible order.hw many arrangements wud be dre in which n28 wud always be before n29.
Just half of the Total Cases will have n28 before n29 and rest half after n29.
So, 100!/2 it will be. :)
@Cat.Aspirant123
i march 1987 ti 1 march 1988 there are 366 days as 1988 is a leap year so 2 odd days
thn frm march to august no of days are march april may june july aug
30 30 31 30 31 17
and their respective odd days 2 2 3 2 3 3
so total no of odd days are 17 whc means 3 odd days so friday +3 odd days = monday
i march 1987 ti 1 march 1988 there are 366 days as 1988 is a leap year so 2 odd days
thn frm march to august no of days are march april may june july aug
30 30 31 30 31 17
and their respective odd days 2 2 3 2 3 3
so total no of odd days are 17 whc means 3 odd days so friday +3 odd days = monday
@ravi.theja said:P, Q and R are in arithmetic progression but not in geometric progression. Their squares are in harmonic progression. 2Q^2 + PR equal ??@Estallar12 bhai solve dis
Is it 0??
let the terms be -> (a-d),a,(a+d)
2/a^2 = 1/(a-d)^2 + 1/(a+d)^2
this gives -> d = a*rt(3)
put a=1 then d=rt(3)
so, 2q^2+pr = 2+(1-sqrt(3))(1+sqrt(3)) = 0
@Cat.Aspirant123 said:suppose 1st march 1987 ko friday hai.... ko 17th august 1988 ko kya hoga(day)
monday
@Cat.Aspirant123 said:suppose 1st march 1987 ko friday hai.... ko 17th august 1988 ko kya hoga(day)
monday
@ravi.theja said:P, Q and R are in arithmetic progression but not in geometric progression. Their squares are in harmonic progression. 2Q^2 + PR equal ??@Estallar12 bhai solve dis
Suppose the numbers are (a-d), a, (a+d) which are P, Q and R resp.
As squares are in Harmonic Prog.
=> 2/a^2 = 1/(a-d)^2 + 1/(a+d)^2
Solve for d fastly.
=> d = a*root(3)
Now, If a = 1 => d = root(3)
So, 2Q^2 + PR = 2 + (1+ root 3)(1 - root 3) = 2 + 1 - 3 = 0. (ZERO)
answer is zero..
@Cat.Aspirant123 said:suppose 1st march 1987 ko friday hai.... ko 17th august 1988 ko kya hoga(day)
1988 is a Leap Year. So, 1st March '87 to 1st March '88 => 2 Odd Days.
Now, Odd days in March, April, May, June and July = 3 + 2 + 3 + 2 + 3 = 13
So, Total Odd Days = 2 + 13 + 17 = 32 mod 7 = 4.
So, Friday, Sat, Sun and Monday it will be. :)
@Cat.Aspirant123 said:suppose 1st march 1987 ko friday hai.... ko 17th august 1988 ko kya hoga(day)
Monday ?
@Cat.Aspirant123 said:suppose 1st march 1987 ko friday hai.... ko 17th august 1988 ko kya hoga(day)
mon ?
@Cat.Aspirant123 said:suppose 1st march 1987 ko friday hai.... ko 17th august 1988 ko kya hoga(day)
mon ?
@Cat.Aspirant123 said:suppose 1st march 1987 ko friday hai.... ko 17th august 1988 ko kya hoga(day)
2+2+2+3+2+3+3=17=3 odd days..Monday
if p,q,r are in ap then 1/p,1/q,1/r are in H.P.
If the squares of p,q,r are in hp then the terms are 1/p^2,1/q^2 & 1/r^2 which implies p^2,Q^2 & r^2 are in a.p. Am I interpreting the question wrong??