Four fair dice D1, D2, D3and D4 each having six faces numbered 1,2,3,4,5 and 6 are rolled simultaneously. The probability that D4 shows a number appearing on one of D1 , D2and D3 is(A)91/216(B)108/216 (C)125/216(D)127/216
Four fair dice D1, D2, D3and D4 each having six faces numbered 1,2,3,4,5 and 6 are rolled simultaneously. The probability that D4 shows a number appearing on one of D1 , D2and D3 is(A)91/216(B)108/216 (C)125/216(D)127/216
(A) 91/216?
All 3 same numbers => 6 2 same numbers => 3 * 6 * 5 = 90 3 different numbers => 6 * 5 * 4 = 120 required probability = 6/216 * 1/6 + 90/216 * 2/6 + 120/216 * 3/6 = 91/216
Four fair dice D1, D2, D3and D4 each having six faces numbered 1,2,3,4,5 and 6 are rolled simultaneously. The probability that D4 shows a number appearing on one of D1 , D2and D3 is(A)91/216(B)108/216 (C)125/216(D)127/216
Four fair dice D1, D2, D3and D4 each having six faces numbered 1,2,3,4,5 and 6 are rolled simultaneously. The probability that D4 shows a number appearing on one of D1 , D2and D3 is(A)91/216(B)108/216 (C)125/216(D)127/216
Ten families, each comprising 4 members attend a church for Christmas celebrations. If each person exchanges a greeting card with every other person of a different family exactly once, then find the number of greeting cards exchanged.