Let X = {a, b, c} and Y = {l, m}. Consider the following four subsets of X — Y. F1 = {(a, l), (a, m), (b, l), (c, m)} F2 = {(a, l), (b, l), (c, l)} F3 = {(a, l), (b, m), (c, m)} F4 = {(a, l), (b, m)} Which one, amongst the choices given below, is a representation of functions from X to Y? (A) F1, F2 and F3 (B) F2, F3 and F4 (C) F2 and F3 (D) F3 and F4 (E) None of the above
Both the sticks burn at different rate but they burn for exactly 30 minutes . If we burn first stick from both the ends it will take 15 minutes and if we burn 2nd stick from one end first of all and when 15 minutes are over we will burn it from other side also ......second stick is already burned for 15 min, 15 min are more left, so when we burn it from other side it will be 15/2=7.5 min . i think i am correct
Both the sticks burn at different rate but they burn for exactly 30 minutes . If we burn first stick from both the ends it will take 15 minutes and if we burn 2nd stick from one end first of all and when 15 minutes are over we will burn it from other side also ......second stick is already burned for 15 min, 15 min are more left, so when we burn it from other side it will be 15/2=7.5 min . i think i am correct
Let X = {a, b, c} and Y = {l, m}. Consider the following four subsets of X — Y. F1 = {(a, l), (a, m), (b, l), (c, m)} F2 = {(a, l), (b, l), (c, l)} F3 = {(a, l), (b, m), (c, m)} F4 = {(a, l), (b, m)} Which one, amongst the choices given below, is a representation of functions from X to Y? (A) F1, F2 and F3 (B) F2, F3 and F4 (C) F2 and F3 (D) F3 and F4 (E) None of the above
bhai..F4 mein gadbad hai.. wo function mein aayega hi nahin... X---->Y meab every element of X shld be mapped to elements of Y in either one to one r many to one..element in X cant be unmapped....F4 mein ek element unmapped hai..
mere solution pe trust nahin hai kissi ko...@Tiws wats d correct oA..i wont go with B..as F4 wont be a fucntion...
Its not that aapka solution sahi hai isliye like kiya but the answer is B but how mujhe nahi samajh aaya aur office me baithke i am not going to read wikipedia theory
bhai _/\_ur solution is correct...lekin pata hai..when i take 1,2 as 2 numbers..4c=3;c=3/4and then take option 3..as 2*15/3=30/3=10*9/16...yahan se 5 nahin aa raha...
arre you cannot take 1,2 as 2 numbers 1 + 2 + 3 = 6 But 9c = 9 * 3/4 = 27/4 which is not the same as above.
Its not that aapka solution sahi hai isliye like kiya but the answer is B but how mujhe nahi samajh aaya aur office me baithke i am not going to read wikipedia theory
yaar B possible nain lag raha..if we go by definition of function... F4 mein set X mein C ka koi mapping hi nahin hai naa Y mein...to ye fuction hi nahin hoga..
Four fair dice D1, D2, D3and D4 each having six faces numbered 1,2,3,4,5 and 6 are rolled simultaneously. The probability that D4 shows a number appearing on one of D1 , D2and D3 is (A)91/216 (B)108/216