Official Quant thread for CAT 2013

@paridhi11890 said:
Please solve this...
3. (n(4n^2 - 1)c^2)/3

a + a+d = 4c
a + a+d + a+2d = 9c
a + a+d + a+2d + a+3d = 16c

a + 2d = 5c
a + 3d = 7c
d = 2c
a = c

n = 2
a^2 + (a+d)^2 = 10c^2
Option 3 satisfies.
@Tiws said:
Let X = {a, b, c} and Y = {l, m}. Consider the following four subsets of X — Y. F1 = {(a, l), (a, m), (b, l), (c, m)} F2 = {(a, l), (b, l), (c, l)} F3 = {(a, l), (b, m), (c, m)} F4 = {(a, l), (b, m)} Which one, amongst the choices given below, is a representation of functions from X to Y? (A) F1, F2 and F3 (B) F2, F3 and F4 (C) F2 and F3 (D) F3 and F4 (E) None of the above
isko bhi koi solve karo...

meko C lag raha..F2 and F3...
@Cat.Aspirant123 said:
explain ?
Both the sticks burn at different rate but they burn for exactly 30 minutes . If we burn first stick from both the ends it will take 15 minutes and if we burn 2nd stick from one end first of all and when 15 minutes are over we will burn it from other side also ......second stick is already burned for 15 min, 15 min are more left, so when we burn it from other side it will be 15/2=7.5 min . i think i am correct
@shattereddream said:
Both the sticks burn at different rate but they burn for exactly 30 minutes . If we burn first stick from both the ends it will take 15 minutes and if we burn 2nd stick from one end first of all and when 15 minutes are over we will burn it from other side also ......second stick is already burned for 15 min, 15 min are more left, so when we burn it from other side it will be 15/2=7.5 min . i think i am correct
well done.. :)
@rhinorocks said:
isko bhi koi solve karo...

meko C lag raha..F2 and F3...
C hi hai...baki are relations not functions
@Tiws said:
Let X = {a, b, c} and Y = {l, m}. Consider the following four subsets of X — Y. F1 = {(a, l), (a, m), (b, l), (c, m)} F2 = {(a, l), (b, l), (c, l)} F3 = {(a, l), (b, m), (c, m)} F4 = {(a, l), (b, m)} Which one, amongst the choices given below, is a representation of functions from X to Y? (A) F1, F2 and F3 (B) F2, F3 and F4 (C) F2 and F3 (D) F3 and F4 (E) None of the above


A & C me confusion hai but will go with A
@shattereddream
@Abhilash09
@rhinorocks
Its B

http://en.wikipedia.org/wiki/Function_%28mathematics%29

@Tiws said:
bhai..F4 mein gadbad hai..
wo function mein aayega hi nahin...
X---->Y meab every element of X shld be mapped to elements of Y in either one to one r many to one..element in X cant be unmapped....F4 mein ek element unmapped hai..
@Tiws said:
Do u have the solution ? if yes then post it everything will be cleared.
@shattereddream said:
Do u have the solution ? if yes then post it everything will be cleared.
mere solution pe trust nahin hai kissi ko...:splat:
@Tiws wats d correct oA..i wont go with B..as F4 wont be a fucntion...:)

@grkkrg said:
3. (n(4n^2 - 1)c^2)/3a + a+d = 4ca + a+d + a+2d = 9ca + a+d + a+2d + a+3d = 16ca + 2d = 5ca + 3d = 7cd = 2ca = cn = 2a^2 + (a+d)^2 = 10c^2Option 3 satisfies.
bhai _/\_
ur solution is correct...

lekin pata hai..when i take 1,2 as 2 numbers..
4c=3;
c=3/4
and then take option 3..
as 2*15/3=30/3=10*9/16...yahan se 5 nahin aa raha...:banghead:
@rhinorocks said:
mere solution pe trust nahin hai kissi ko...@Tiws wats d correct oA..i wont go with B..as F4 wont be a fucntion...
Its not that aapka solution sahi hai isliye like kiya but the answer is B but how mujhe nahi samajh aaya aur office me baithke i am not going to read wikipedia theory

i think its A


@rhinorocks said:
bhai _/\_ur solution is correct...lekin pata hai..when i take 1,2 as 2 numbers..4c=3;c=3/4and then take option 3..as 2*15/3=30/3=10*9/16...yahan se 5 nahin aa raha...
arre you cannot take 1,2 as 2 numbers
1 + 2 + 3 = 6
But 9c = 9 * 3/4 = 27/4 which is not the same as above.

Koi doosri AP hai yeh
@shattereddream said:
Its not that aapka solution sahi hai isliye like kiya but the answer is B but how mujhe nahi samajh aaya aur office me baithke i am not going to read wikipedia theory
yaar B possible nain lag raha..if we go by definition of function...
F4 mein set X mein C ka koi mapping hi nahin hai naa Y mein...to ye fuction hi nahin hoga..
@rhinorocks
@shattereddream
isn't F4 an one to one ?
Given that F4 is a subset of X*Y

@grkkrg said:
arre you cannot take 1,2 as 2 numbers1 + 2 + 3 = 6But 9c = 9 * 3/4 = 27/4 which is not the same as above.Koi doosri AP hai yeh
hmmm...main to value put karke banane laga.....:banghead:
phir jab usual process se gaya tab ans aaya...
@Tiws said:
@rhinorocks@shattereddreamisn't F4 an one to one ?Given that F4 is a subset of X*Y
how can F4 will be one to one bhai...
X mein 3 element hain..(a,b,c)
Y mein (l,m) hai..
F4 mein c se mapping hi nahin hai...
@shattereddream
@rhinorocks
yeah its C.
initially i thought F4 is also one to one.
but its not covering all the elements of X.
you are right. C is OA.
Four fair dice D1, D2, D3and D4 each having six faces numbered 1,2,3,4,5 and 6 are rolled simultaneously. The probability that D4 shows a number appearing on one of D1 , D2and D3 is
(A)91/216
(B)108/216
(C)125/216
(D)
127/216