Official Quant thread for CAT 2013

@pyashraj said:
@LogrhythmI strongly feel 143 shld be the answer..Bt then.. I cud be wrng.. I suppose 29 will be the answer..Its the OA..
Yes. OA is 29. it is pigeon hole problem........

Find the unit digit of 7^23 x 4^21
@sails said:
yes but how..? accordin to unitart method im gettin 19.25 can you please tell me why that is incorrect
bhai 12th wali strike ko consider ni karenge na....x-1 hota hai hamesha...
@pyashraj said:
@sailsLogarthymic Scale of tym..PHYSICS.. At 4 o'clock, there are 4 stikes n 3 quite..Thus, at 11 o'clock there wud b 10 quite n 11 stikes..Nw, 7 sec= 4 stikes + 3 quite, thus, 1 strike + 1quite = 7/3 sec.., or, 7/3 sec is the time in btwn each strke..=>Thus, 10 quite + 11 strike = 70/3, or, 23.33 sec..
7sec=4strikes+3quiet okay..then next equation 1 strike+1 quiet...can yu explain this..
@bs0409 said:
Yes. OA is 29. it is pigeon hole problem........Find the unit digit of 7^23 x 4^21
7^3*4 = 2
@bs0409

2..
@bs0409 said:
Yes. OA is 29. it is pigeon hole problem........Find the unit digit of 7^23 x 4^21
2
@bs0409 said:
Yes. OA is 29. it is pigeon hole problem........Find the unit digit of 7^23 x 4^21
Unit digit is 2
@sails

3 gaps are covered in 7 secs, so,

10 gaps would be covered in 70/3 sec=23.33sec.. Ab clear hai bhai ..
@sails said:
7sec=4strikes+3quiet okay..then next equation 1 strike+1 quiet...can yu explain this..
ya i got it..thanks mate..:)
@bs0409 said:
Yes. OA is 29. it is pigeon hole problem........Find the unit digit of 7^23 x 4^21
2?
@sails said:
A pendulum strikes 4 "o"clock in 7 seconds,how much time does it take to strike 11 "o"clock?a)18secondsb)20secondsc)19.25secondsd)23.33 seconds
23.33 secs?
3 gaps---->7 secs
10 gaps---->7*10/3=23.33 secs

Just a Thought: Srry 4 spamming..


Black holes result from God dividing the universe by zero..

Gud N8..
@pyashraj said:
Just a Thought: Srry 4 spamming..Black holes result from God dividing the universe by zero.. Gud N8..
Only quant gods are allowed to spam here..
And they dont waste time in such random divisions..
pls dont spam here..(will delete this post soon)
@shinoda said:
find the no of ways in which 8 diffrnt flowers can be strung to form a garland when 4 particlar flowers are always 2gethr ??
total flowers = 8 - 4 + 1 [consider 4 flwers which are to be together as single flower ]

5 flowers can be arranged in a garland in 4!/2 ways..internally the 4 flowers which must be together need to be arranged in 4! ways...

total no.of ways = 4!/2 * 4! = 288 ways
@pyashraj said:
@shinodaSolve this:Hw many ways can 6 beads of different colors be arranged to form a necklace?
5!??
@bs0409 said:
Yes. OA is 29. it is pigeon hole problem........Find the unit digit of 7^23 x 4^21
3* 4 = 12
@pyashraj said:
@shinodaSolve this:Hw many ways can 6 beads of different colors be arranged to form a necklace?
6!/2 ??
@viewpt said:
buddy are u the same ravi teja who gat 100%ile??
nope man !!!
@krum :
for Q1: answer will be 6.
for Q2: answer will be 10
@ravi.theja said:
total flowers = 8 - 4 + 1 [consider 4 flwers which are to be together as single flower ]5 flowers can be arranged in a garland in 4!/2 ways..internally the 4 flowers which must be together need to be arranged in 4! ways...total no.of ways = 4!/2 * 4! = 288 ways
the OA is other way round..
4!*4!
had a lot of discussion yesterday with fellow puys..go through some previous post and check if we are right or not !!