@pyashraj said:@shinodaSolve this:Hw many ways can 6 beads of different colors be arranged to form a necklace?
5!/2
Find the Highest Power of 3 in expression N= 1! x 2! x 3! x .... x 99! x 100!
@Logrhythm said:Find the Highest Power of 3 in expression N= 1! x 2! x 3! x .... x 99! x 100!
Is it 2238 ???
@Logrhythm said:Find the Highest Power of 3 in expression N= 1! x 2! x 3! x .... x 99! x 100!
is it 2328 bro ?
@shattereddream said:
Is it 2238 ???
@Budokai001 said:is it 2328 bro ?
U Guys had the guts n glory to count so many 3's.. 
Arigato Master's of the Universe..
Arigato Master's of the Universe..@Logrhythm said:Find the Highest Power of 3 in expression N= 1! x 2! x 3! x .... x 99! x 100!
It will be
(98+95+92+...........2)+(92+83+74+......2)+(74+47+20)+(20)
=2328
(98+95+92+...........2)+(92+83+74+......2)+(74+47+20)+(20)
=2328
@shinoda said:find the no of ways in which 8 diffrnt flowers can be strung to form a garland when 4 particlar flowers are always 2gethr ??
Its circular arrangement. (5-1)! * 4!=4! * 4! =576
A set consists of 143 natural numbers each of them is a perfect cube. If they are divided by 13, how many maximum numbers within the set are possible, such that one will get the same reminder in each case.
(a)11, (b)31, (c)33, (d)36, (e)29
A set consists of 143 natural numbers each of them is a perfect cube. If they are divided by 13, how many maximum numbers within the set are possible, such that one will get the same reminder in each case.
(a)11, (b)31, (c)33, (d)36, (e)29
@bs0409 said:Its circular arrangement. (5-1)! * 4!=4! * 4! =576A set consists of 143 natural numbers each of them is a perfect cube. If they are divided by 13, how many maximum numbers within the set are possible, such that one will get the same reminder in each case.(a)11, (b)31, (c)33, (d)36, (e)29
Is it 29??
There are 5 possible remainders that one can get while dividing perfect cubes by 13...0,1,8,5 and 12
so total = 29 such numbers..
@pyashraj said:@bs0409Cant it be 143 only?? When all the number under the desired set have (13n + x)^3 form..
I thought the exact same thing....what if all numbers are xk^3....but then 143 was not in the optons...
@Logrhythm
I strongly feel 143 shld be the answer..Bt then.. I cud be wrng.. 
I suppose 29 will be the answer..Its the OA..
I suppose 29 will be the answer..Its the OA..
A pendulum strikes 4 "o"clock in 7 seconds,how much time does it take to strike 11 "o"clock?
a)18seconds
b)20seconds
c)19.25seconds
d)23.33 seconds
a)18seconds
b)20seconds
c)19.25seconds
d)23.33 seconds
@pyashraj han bhai....kabhi kabhi options dekh kar bhi answer modulate karna padta hai...agar options nahi hote toh main bhi 143 bolta... :D
@sails said:A pendulum strikes 4 "o"clock in 7 seconds,how much time does it take to strike 11 "o"clock?a)18secondsb)20secondsc)19.25secondsd)23.33 seconds
Is it 70/3 = 23.33 seconds??
@Logrhythm said:Is it 70/3 = 23.33 seconds??
yes but how..? accordin to unitart method im gettin 19.25 can you please tell me why that is incorrect
@sails said:A pendulum strikes 4 "o"clock in 7 seconds,how much time does it take to strike 11 "o"clock?a)18secondsb)20secondsc)19.25secondsd)23.33 seconds
23.33 seconds
(11-1)*(7/(4-1))
(11-1)*(7/(4-1))
@sails
Logarthymic Scale of tym..PHYSICS.. At 4 o'clock, there are 4 stikes n 3 quite..Thus, at 11 o'clock there wud b 10 quite n 11 stikes..
At 4 o'clock, there are 4 stikes n 3 quite..Thus, at 11 o'clock there wud b 10 quite n 11 stikes..Nw, 7 sec= 4 stikes + 3 quite, thus, 1 strike + 1quite = 7/3 sec.., or, 7/3 sec is the time in btwn each strke..
=>Thus, 10 quite + 11 strike = 70/3, or, 23.33 sec..
@sails said:A pendulum strikes 4 "o"clock in 7 seconds,how much time does it take to strike 11 "o"clock?a)18secondsb)20secondsc)19.25secondsd)23.33 seconds
C- 19.25 seconds