ravi.theja
(Rawii Teza)
13563
@joyjitpal said: how?
a^3 = abc + 2 ; b^3 = abc -3 ; c^3 = abc + 3 ==>on solving we get
a^3 - b^3 = 5; c^3 - a^3 = 1 ; c^3 - b^3 = 6 ;here i took a = 2 ==> c=9^1/3 ===> b= 3^1/3 😃 so min = 3^1/3
ravi.theja
(Rawii Teza)
13565
@vbhvgupta said: Q
52 :)
50,51 does nt satify condition 1 i.e., >= 7. 49 and 53 doesnt satisfy conition2 i.e., sum of squares
How many real roots does the equation
(x^4)+2(x^3)-10(x^2)-2x+1=0 have?..
In general, Could any one tell how to find number of real roots for equations having degree more than 2?
vbhvgupta
(Vaibhav Gupta)
13567
@ravi.theja said: 52 50,51 does nt satify condition 1 i.e., >= 7. 49 and 53 doesnt satisfy conition2 i.e., sum of squares
u have consider options i think, We have to find all those two digit no that satisfy these conditions.....
ravi.theja
(Rawii Teza)
13568
@vbhvgupta said: u have consider options i think, We have to find all those two digit no that satisfy these conditions.....
only 52 satisfies that condition bhai 😃 no other number satisfies 😃
vbhvgupta
(Vaibhav Gupta)
13569
@ravi.theja said: only 52 satisfies that condition bhai no other number satisfies
okk..52 i also got....but thn i thought it shd be 52 numbers....
vbhvgupta
(Vaibhav Gupta)
13570
Remainder 43^101 + 23^101 is divided by 66
budokai001
(Budokai 001)
13571
@vbhvgupta said: Remainder 43^101 + 23^101 is divided by 66
a^n+b^n is divisible by a+b when n=odd bro
So ans is zero..
allan89
(Koustav Pal)
13575
@Budokai001 said: For how many integral values of n is sqrt{4(n-3) / (n-48) } a positive integer ?
6=answer
n= 84, 63, 52, 51, 3, -12
budokai001
(Budokai 001)
13576
@allan89 Ans is 6 bro.. u missed one... possibly u ignored 0 as a perfect square ? I did 
53 is not possible .. Other 2 values of n will be 3 and -12
mailtoankit
(ankit gupta)
13577
@vbhvgupta said:Remainder 32^32^32/7 ???Approach?
4?
E(7)=6
32^6k+r mod 7=1
32^32 mod 6 = 4...so r = 4
so 32^4 mod 7 = 4?
krum
(kumar utsav)
13579
@vbhvgupta said:Remainder 32^32^32/7 ???Approach?
e(7)=6
32^32mod6
=2^32mod6
=(32)^6*4mod6
=2^10mod6
=4mod6
=4
32^4mod6
=16mod6
=4
ravi.theja
(Rawii Teza)
13580
@vbhvgupta said: Remainder 43^101 + 23^101 is divided by 66
a^n + b ^n will always be div by a+b wen n is odd...so rem =0
budokai001
(Budokai 001)
13581
For a trapezium , S1 denotes the sum of squares of of the sides and S2 denotes the sum of squares of the diagonals . S1-S2=576
If the longer parallel side is 50 cm,Find the shorter parallel side