Official Quant thread for CAT 2013

@nramachandran said:
Guess you might have got the eqn wrong. Please find the attachmentSolving it you will get56+x = 81Funda is we are equating,work done / number of men * number of days
done...actually i made a calculation mistake. thanks
@pirateiim478 said:
Solve |2x-1|+|3x-4|=20
x=5,-3 :D
@krum said:
480/1.2*1.33 = 532
formula nai bhai

say johny needed x days, so tony will take 1.33x

if tony is paid y/hr, johny will get 1.2y

so 1.2y*x=480

we need 1.33x*y = 480/1.2 * 1.33
@dhwanibhatt6 said:
dude.. answer is correct.Please explain too,,direct formula se nai samaj aa rha !
formula nai bhai

say johny needed x days, so tony will take 1.33x

if tony is paid y/hr, johny will get 1.2y

so 1.2y*x=480

we need 1.33x*y = 480/1.2 * 1.33

Define a no K such that it is the sum of the squares of the first M natural numbers ( k = 1^2 + 2^2 +3^2+...+ M) where M

How many pairs of positive integers m, n satisfy 1/m + 4/n = 1/12 where n is an
odd integer less than 60?
@dhwanibhatt6 said:
1) Mr. X has to build a wall 1000 m long in 50 days. He employs 56 men but at the end of 27 days finds that only 448 m is built. How many more men must be employed so that work may be finished in time ?



25
@nramachandran said:
How many pairs of positive integers m, n satisfy 1/m + 4/n = 1/12 where n is anodd integer less than 60?
12n+48m=mn

==> (m-12)(n-48)= 576

n=49,51,57

3?

Q3

@pirateiim478 said:
@Pratishruti said:x=5 or -3?No try again!!Find the sum of all 4 digit numbers formed by digits 1,2,3 and 4 when repetitions of digits is allowed??
711040
@nramachandran said:
How many pairs of positive integers m, n satisfy 1/m + 4/n = 1/12 where n is anodd integer less than 60?
3
@pirateiim478 said:
@Pratishruti said:x=5 or -3?No try again!!Find the sum of all 4 digit numbers formed by digits 1,2,3 and 4 when repetitions of digits is allowed??
64*10*11=711040
@pirateiim478 said:
Yes it is 900Solve |2x-1|+|3x-4|=20
15/4 , -3??

28383th termof the series 1234567891011121314151617181920.............

@nramachandran said:
How many pairs of positive integers m, n satisfy 1/m + 4/n = 1/12 where n is anodd integer less than 60?
1/m=1/12 -4/n
m=12n/n-48 ..so uv to basically try for numbers 49,51,53,55,57,59 as per given conditions...if yu try..ul get only 3 cases...n=49,51,57 which satisfy..:)
@dhwanibhatt6 said:
1) Mr. X has to build a wall 1000 m long in 50 days. He employs 56 men but at the end of 27 days finds that only 448 m is built. How many more men must be employed so that work may be finished in time ?2) Johny is 33% more efficient than tony and his hourly wages are 20 % more. If johny is paid 480 , how much tony will receive for the same work ?
1. (M1 * D1)/ W1 = (M2 * D2) / W2


56 * 27 /448 = 23 * (56 +X )/ 552 ===> X = 25

2. J = 4/3 T ; T ( 1 hour ) = X rupees J ( 1 hour ) = 1.2 X if J =480 => T =400 ; since J=1.33T T = 400 * 3/4 = 300
@vbhvgupta said:
28383th termof the series 1234567891011121314151617181920.............
3
@allan89 said:
3
Explain?
@nramachandran

Given, 1/m = 1/12 - 4/n

Since m is positive,n must be greater than 48.

Possible odd values of n such that 48

So,there are 3 solutions

@vbhvgupta said:
28383th termof the series 1234567891011121314151617181920.............
9?