see i don't understand the permutation & combination by its formulae
.. so i count all the tym. i counted wrong in the first tym
@jaituteja no man .. its 13 .. check again .. i found my mistake .. there are 2 different paths to reach C from the right upper diagonal of the restricted zone D. and there are 6 unique routes to reach the right upper diagonal of the restricted zone D from B. thus 6*2=12 ways + 1 outer route = 13 ways ..
see i don't understand the permutation & combination by its formulae .. so i count all the tym. i counted wrong in the first tym
see i don't understand the permutation & combination by its formulae
.. so i count all the tym. i counted wrong in the first tym
Q2
1) Mr. X has to build a wall 1000 m long in 50 days. He employs 56 men but at the end of 27 days finds that only 448 m is built. How many more men must be employed so that work may be finished in time ?
2) Johny is 33% more efficient than tony and his hourly wages are 20 % more. If johny is paid 480 , how much tony will receive for the same work ?
(1/x) + (1/y) = 1/2 ; x and y are positive integers, What is the maximum value of x+y?
Please post the approach
Please post the approach
@dhwanibhatt6 said:1) Mr. X has to build a wall 1000 m long in 50 days. He employs 56 men but at the end of 27 days finds that only 448 m is built. How many more men must be employed so that work may be finished in time ?2) Johny is 33% more efficient than tony and his hourly wages are 20 % more. If johny is paid 480 , how much tony will receive for the same work ?
448/1000
-----------
56*27 =
552/1000
------------
(56+x)*23
Solving x=25, 25 more men are required
@nramachandran
Should be 9..
1/x + 1/y = 1/2..Here, x=3, y = 6.. Mostly it seems 8 to be the answer[x=4, y=4]... 
@pyashraj said:@nramachandranShould be 9..1/x + 1/y = 1/2..Here, x=3, y = 6.. Mostly it seems 8 to be the answer[x=4, y=4]...
how did u solve it ? Trial and error ?
@nramachandran said:(1/x) + (1/y) = 1/2 ; x and y are positive integers, What is the maximum value of x+y? Please post the approach
It will be 8. Use AM>=GM.
@dhwanibhatt6 said:2) Johny is 33% more efficient than tony and his hourly wages are 20 % more. If johny is paid 480 , how much tony will receive for the same work ?
480/1.2*1.33 = 532
@nramachandran said:448/1000-----------56*27 =552/1000------------(56+x)*23Solving x=25, 25 more men are required
If i go by the equation you provided, i am getting the following:
(56+x)= 69*27/28.
I don't know how yu getting 25 , though your answer is correct.
(56+x)= 69*27/28.
I don't know how yu getting 25 , though your answer is correct.
@somnathbhatta said:Suppose, the seed of any positive integer n is defined as follows:seed(n) = n, if n = seed(s(n)), otherwise,where s(n) indicates the sum of digits of n. For example,seed(7) = 7, seed(248) = seed(2 + 4 + 8) = seed(14) = seed(1 + 4) = seed(5) = 5 etc.How many positive integers n, such that n 1)39 2)72 3)81 4)108 5)55 please share the approach too
55
@Pratishruti said:x=5 or -3?
No try again!!
Find the sum of all 4 digit numbers formed by digits 1,2,3 and 4 when repetitions of digits is allowed??
@krum said:480/1.2*1.33 = 532
dude.. answer is correct.
Please explain too,,direct formula se nai samaj aa rha !
Please explain too,,direct formula se nai samaj aa rha !
@Cat.Aspirant123 said:P can do in 10 days, P n Q in 5 days, PQR in 2 days, P n R ?342.53.5
10/4 equals to 2.5
@dhwanibhatt6 said:If i go by the equation you provided, i am getting the following:(56+x)= 69*27/28.I don't know how yu getting 25 , though your answer is correct.
Guess you might have got the eqn wrong. Please find the attachment
Solving it you will get
56+x = 81
Funda is we are equating,
work done / number of men * number of days
Solving it you will get
56+x = 81
Funda is we are equating,
work done / number of men * number of days