typo ...
@gs4890 @sujamait
Have you guys assumed that she has only one child that day? She can even have twins/triplets/quadruplets
@adwaitjw said:13.33Average age of all children on that day is between 4-4.3 years.Means total of there ages is 16-17.2 yearsOf which avg of two oldest is 8.Means total for two oldest is 16.So third child should be of 1 year.----------- To make total 17N fourth child 0 year (just born).So total age of four children 17, father 33, mother 30Total= 80Total members=6 (Father, mother, 4 children)So avg family age = 80/6 =13.33 years
i got d same bt thr is no option more then 13:)
Plz explain Find the no of zeros in product
1. 1^1 * 2^2 * 3^3 * 4^4 * 5^5 *.......*49^49
2. 100^1 * 99^2 * 98^3 * 97^4 *..........* 1^100
3. 1^1! * 2^2! *3^3! * 4^4! * 5^5!*......10^10!
@soumitrabengeri said:@gs4890@sujamaitHave you guys assumed that she has only one child that day? She can even have twins/triplets/quadruplets
thn accrding to u?????
a question i found in this very thread......a lengthy one i feel...give it a try :)
2222^3333^4444^....... div 9999 R=?
2222^3333^4444^....... div 9999 R=?
@PGrulz said:Three truck drivers, Amar, Akbar and Anthony stop at a road side eating joint. Amar orders 10 rotis, 4 plates of tadka, and a cup of tea. Akbar orders 7 rotis, 3 plates of tadka, and a cup of tea, Amar pays ` 80 for the meal and Akbar pays ` 60. Meanwhile, Anthony orders 5 rotis, 5 plaes of tadka and 5 cups of tea. How much (in `) will Anthony pay?A.75B.80C.95D.100E.None of the above.Please share short-cut.if possible, share some similar type of question
100 ,,,
@soumitrabengeri said:@gs4890@sujamaitHave you guys assumed that she has only one child that day? She can even have twins/triplets/quadruplets
yeah may be..god only knows...
@hari_bang said:i got d same bt thr is no option more then 13
thats y I asked for options :P
@hari_bang said:thn accrding to u?????
She has twins..so in total she has 5 kids on that day :)
What's the OA?
@sujamait said:yeah may be..god only knows... thats y I asked for options
Even i dunno..i'm just guessing the answer as 12
@soumitrabengeri said:@gs4890@sujamaitHave you guys assumed that she has only one child that day? She can even have twins/triplets/quadruplets
I think range of kids she can have is 1 /2/3. not getting unique solution.
@emanresu said:I think range of kids she can have is 1 /2/3. not getting unique solution.
Yes agreed..i just went for 2 kids since i was getting an integer value..that's all
@soumitrabengeri said:@gs4890@sujamaitHave you guys assumed that she has only one child that day? She can even have twins/triplets/quadruplets
Then we cannot determine a Unique Solution in that case.. 
Either the question is 2 gud or i have thought 2 much over it.. 
Either the question is 2 gud or i have thought 2 much over it.. @shadowwarrior said:a question i found in this very thread......a lengthy one i feel...give it a try 2222^3333^4444^....... div 9999 R=?
bhai...power up to infinity hai kya ?
@soumitrabengeri said:She has twins..so in total she has 5 kids on that day What's the OA?Even i dunno..i'm just guessing the answer as 12
11.5,
10.5,
12,
12.33,
13
@vbhvgupta said:Plz explain Find the no of zeros in product1. 1^1 * 2^2 * 3^3 * 4^4 * 5^5 *.......*49^492. 100^1 * 99^2 * 98^3 * 97^4 *..........* 1^1003. 1^1! * 2^2! *3^3! * 4^4! * 5^5!*......10^10!
1)250 zeroes
2)1124 zeroes
3)3628920 zeroes.....
are these correct....?
in all the cases, it was only the 5 power that was guiding...
2)1124 zeroes
3)3628920 zeroes.....
are these correct....?
in all the cases, it was only the 5 power that was guiding...
Find max value of n such that
570*60*30*90*100*500*700*343*720*81 is perfectly divisible by 30^n
Bhai please solve the following question...and post ur solutions...and do tag me...
thanks in advance..
XAT 2005 question
@shadowwarrior said:1)250 zeroes2)1124 zeroes3)3628920 zeroes.....are these correct....?in all the cases, it was only the 5 power that was guiding...
yes...can you explain any one of these?