@bhatkushal said:guys try doing it without the options and please do share the approach.......
only possible way is re 1*150=150..so it has to b 0..
or que has got smthng missing..
or que has got smthng missing..
Three truck drivers, Amar, Akbar and Anthony stop at a road side eating joint. Amar orders 10 rotis, 4 plates of tadka, and a cup of tea. Akbar orders 7 rotis, 3 plates of tadka, and a cup of tea, Amar pays ` 80 for the meal and Akbar pays ` 60. Meanwhile, Anthony orders
5 rotis, 5 plaes of tadka and 5 cups of tea. How much (in `) will Anthony pay?
A. 75
B. 80
C. 95
D. 100
E. None of the above.
Please share short-cut.if possible, share some similar type of question
@PGrulz said:Three truck drivers, Amar, Akbar and Anthony stop at a road side eating joint. Amar orders 10 rotis, 4 plates of tadka, and a cup of tea. Akbar orders 7 rotis, 3 plates of tadka, and a cup of tea, Amar pays ` 80 for the meal and Akbar pays ` 60. Meanwhile, Anthony orders 5 rotis, 5 plaes of tadka and 5 cups of tea. How much (in `) will Anthony pay?A.75B.80C.95D.100E.None of the above.Please share short-cut.if possible, share some similar type of question
100
10a+4b+c=80 - (i)
7a+3b+c=60 - (ii)
(i) - (ii) ==> 3a+b=20
10*(ii) - 7*(i) ==> 2b+3c=40
==> 3a+3b+3c=60
so 5a+5b+5c=20*5=100
10a+4b+c=80 - (i)
7a+3b+c=60 - (ii)
(i) - (ii) ==> 3a+b=20
10*(ii) - 7*(i) ==> 2b+3c=40
==> 3a+3b+3c=60
so 5a+5b+5c=20*5=100
@PGrulz said:Three truck drivers, Amar, Akbar and Anthony stop at a road side eating joint. Amar orders 10 rotis, 4 plates of tadka, and a cup of tea. Akbar orders 7 rotis, 3 plates of tadka, and a cup of tea, Amar pays ` 80 for the meal and Akbar pays ` 60. Meanwhile, Anthony orders 5 rotis, 5 plaes of tadka and 5 cups of tea. How much (in `) will Anthony pay?A.75B.80C.95D.100E.None of the above.Please share short-cut.if possible, share some similar type of question
100
3 times Akbar's order - 2 times Amar's order = Anthony's order/ 5 :)
3 times Akbar's order - 2 times Amar's order = Anthony's order/ 5 :)
@PGrulz said:Three truck drivers, Amar, Akbar and Anthony stop at a road side eating joint. Amar orders 10 rotis, 4 plates of tadka, and a cup of tea. Akbar orders 7 rotis, 3 plates of tadka, and a cup of tea, Amar pays ` 80 for the meal and Akbar pays ` 60. Meanwhile, Anthony orders 5 rotis, 5 plaes of tadka and 5 cups of tea. How much (in `) will Anthony pay?A.75B.80C.95D.100E.None of the above.Please share short-cut.if possible, share some similar type of question
100?
@PGrulz said:Three truck drivers, Amar, Akbar and Anthony stop at a road side eating joint. Amar orders 10 rotis, 4 plates of tadka, and a cup of tea. Akbar orders 7 rotis, 3 plates of tadka, and a cup of tea, Amar pays ` 80 for the meal and Akbar pays ` 60. Meanwhile, Anthony orders 5 rotis, 5 plaes of tadka and 5 cups of tea. How much (in `) will Anthony pay?
10roti+4tadka+tea=80.....(1)
7roti+3tadka+tea=60....(2)
(1)-(2)
3r+tadka=20..(3)
(1)-3*(3)
roti+tadka+tea=20
so, 5*(roti+tadka+tea)=100(edited)
PS: a bit time taking
plzz share d shortcut @PGrulz @krum
@adwaitjw said:3 times Akbar's order - 2 times Amar's order = Anthony's order/ 5
dats really very quick bro..thanks for sharing
would someone please solve this for me
what is the coefficient of x^10 in(x+1)(2x+1)(4x+1)(8x+1)............(1024x+1)?
a)2^55-2^45 b)2^56-2^45
c)2^55-2^44 d)2^56-2^44
@falcao said:would someone please solve this for mewhat is the coefficient of x^10 in(x+1)(2x+1)(4x+1)(8x+1)............(1024x+1)?a)2^55-2^45 b)2^56-2^45 c)2^55-2^44 d)2^56-2^44
2^(1+2+3...+9+10)+2^(0+2+3+...+10)+2^(0+1+3+..+10)...
= 2^55+2^54+2^53+2^52+..+2^45
=2^45*(1+2^1+..+2^10)
=2^45*(2^11-1)
=2^56-2^45
= 2^55+2^54+2^53+2^52+..+2^45
=2^45*(1+2^1+..+2^10)
=2^45*(2^11-1)
=2^56-2^45
@falcao said:would someone please solve this for mewhat is the coefficient of x^10 in(x+1)(2x+1)(4x+1)(8x+1)............(1024x+1)?a)2^55-2^45 b)2^56-2^45 c)2^55-2^44 d)2^56-2^44
watch pattern..take small terms..
Mr. Sharma has 3 children. The day on which his wife delivers the next time, the average age of all his children will be greater than 4 years and less than 4.3 years. The average age of the two oldest children on that day will be 8 years and Mr. Sharma and his wife will be 33 and 30 years old respectively. What will then be the average age of all the members of the family?
Solution Plzzz
@hari_bang said:Mr. Sharma has 3 children. The day on which his wife delivers the next time, the average age of all his children will be greater than 4 years and less than 4.3 years. The average age of the two oldest children on that day will be 8 years and Mr. Sharma and his wife will be 33 and 30 years old respectively. What will then be the average age of all the members of the family?Solution Plzzz
13.33
Average age of all children on that day is between 4-4.3 years.
Means total of there ages is 16-17.2 years
Of which avg of two oldest is 8.
Means total for two oldest is 16.
So third child should be of 1 year.----------- To make total 17
N fourth child 0 year (just born).
So total age of four children 17, father 33, mother 30
Total= 80
Total members=6 (Father, mother, 4 children)
So avg family age = 80/6 =13.33 years
Average age of all children on that day is between 4-4.3 years.
Means total of there ages is 16-17.2 years
Of which avg of two oldest is 8.
Means total for two oldest is 16.
So third child should be of 1 year.----------- To make total 17
N fourth child 0 year (just born).
So total age of four children 17, father 33, mother 30
Total= 80
Total members=6 (Father, mother, 4 children)
So avg family age = 80/6 =13.33 years
@hari_bang said:Mr. Sharma has 3 children. The day on which his wife delivers the next time, the average age of all his children will be greater than 4 years and less than 4.3 years. The average age of the two oldest children on that day will be 8 years and Mr. Sharma and his wife will be 33 and 30 years old respectively. What will then be the average age of all the members of the family?Solution Plzzz
12?
Since the average age of the kids is between 4 and 4.3, we have to find a value which when multiplied by an integer produces an integer
The value i assumed is 4.2..since 4.2*5 = 21..so she has twins on that day :)
Now the sums of the ages of the two elder kids is 16
So the 3rd eldest one has to be 21-16 = 5 years old (doesn't matter really)
Sum of ages of all members = 33+30+21/7 = 84/7 = 12
@hari_bang said:Mr. Sharma has 3 children. The day on which his wife delivers the next time, the average age of all his children will be greater than 4 years and less than 4.3 years. The average age of the two oldest children on that day will be 8 years and Mr. Sharma and his wife will be 33 and 30 years old respectively. What will then be the average age of all the members of the family?Solution Plzzz
Considering integer ages & 1 child birth
on birth there will be 4 kids. hence total age>16 &
hence 17
so 17+33+30/6=13.333.
@hari_bang said:Mr. Sharma has 3 children. The day on which his wife delivers the next time, the average age of all his children will be greater than 4 years and less than 4.3 years. The average age of the two oldest children on that day will be 8 years and Mr. Sharma and his wife will be 33 and 30 years old respectively. What will then be the average age of all the members of the family?Solution Plzzz
Let children be a,>=b,>=c,>d .. d being the latest..
so,d=0
16
a+b= 16
so,
0
avg = 80/6 = 13.3 i guess ? options ?
13.22 ?