Farook marks up the price of an article by 50% and then offers a discount of 20% to Shahrukh. Shahrukh sells it for र20 more than the price at which he purchased it. If Shahrukh's selling price is 30% more than the original cost price of the article, then Shahrukh's profit percentage is 10%9%6.66%8.33% ANSfor farook let the cp = 100 mp = 150 so sp = 120for shahrukh cp = 120 sp = 120+20 = 140 profit = (20*100)120 = 16.66where I am doing mistake???
see friend...had the complete transaction be done in terms of percentage..your method would have hit the gold...but unfortunately, in this case, we have an absolute value (Rs. 20)..hence the basic assumption of CP being 100 won't take you on the correct path..(this method is useful only when we are talking in terms of percentage).
here to solve it, assume CP to be x (or 100x for convenience in calculations)and proceed accordingly, you will get the required ans.
The prices per litre of petrol, diesel and CNG are in the ratio 1 : 1/2 : 1/3 while the mileages (in km/litre) are in the ratio 2 : 1 : 3/2.If petrol, diesel and CNG that cost the same amount is filled in 3 similar cars respectively, the distance travelled by the vehicles on that fuel is in the ratio of 4 : 4 : 94 : 6 : 96 : 6 : 99 : 9 : 4
the prices are in the ratio 6:3:2..and the mileage is in the ratio 4:2:3
hence if they fill fuel for Rs. 60, the amount of each will be in the ratio of 10:20:30
hence they will run in the ratio 40:40:90 or 4:4:9
The prices per litre of petrol, diesel and CNG are in the ratio 1 : 1/2 : 1/3 while the mileages (in km/litre) are in the ratio 2 : 1 : 3/2.If petrol, diesel and CNG that cost the same amount is filled in 3 similar cars respectively, the distance travelled by the vehicles on that fuel is in the ratio of 4 : 4 : 94 : 6 : 96 : 6 : 99 : 9 : 4
Four pieces of cake A, B, C and D have weights 6 3/10 lbs, 11 1/5 lbs, 24 1/2 lbs, 15 3/4 lbs respectively. A and B have to be cut into parts of equal weights. C and D have to be cut into parts of equal weights. Furthermore, each part is cut in such a way that each piece is as large as possible. All the pieces of A and B are served to x guests-one piece per guest and all the pieces of C and D are served to y guests-one piece per guest. What is the value of x - y?
In the sequence 1,9,7,7,4,7,5,3,9,4,1, €Ś every digit from the fifth on is the sum of the preceding 4 digits mod 10.Does one of the following set ever occur in the sequence?
For a Fibonacci sequence, from the third term onwards, each term in the sequence is the sum of the previous two terms in that sequence. If the difference in squares of seventh and sixth terms of this sequence is 517, what is the tenth term of this sequence?
Four pieces of cake A, B, C and D have weights 6 3/10 lbs, 11 1/5 lbs, 24 1/2 lbs, 15 3/4 lbs respectively. A and B have to be cut into parts of equal weights. C and D have to be cut into parts of equal weights. Furthermore, each part is cut in such a way that each piece is as large as possible. All the pieces of A and B are served to x guests-one piece per guest and all the pieces of C and D are served to y guests-one piece per guest. What is the value of x - y?
HCF of A & B=7/10 HCF of C & D =7/4 Total pieces of A,B,C & D are 9,16,14 & 9 respectively x=25, y=23 x-y=2
1.For each natural number N, define S(N) be the sum of digits of N.For eg: If N = 9801, S(N) = 9 + 8 + 0 + 1 = 18 N = 25, S(N) = 2 + 5 = 7How many natural numbers, N, exist such thatS(N) + S(N^2) = 2011N+N^2 = 2011
For a Fibonacci sequence, from the third term onwards, each term in the sequence is the sum of the previous two terms in that sequence. If the difference in squares of seventh and sixth terms of this sequence is 517, what is the tenth term of this sequence?(a) 147 (b) 76 (c) 123 (d) Cannot be determined
@sparklingaubade -d??the whole sequence has 4odd numbers followed by even..in other words sequence mod 2 yields 11110..the 1st three options are not in sync with the sequence but the fourth one seems to be..just an observation..wats the OA
For a Fibonacci sequence, from the third term onwards, each term in the sequence is the sum of the previous two terms in that sequence. If the difference in squares of seventh and sixth terms of this sequence is 517, what is the tenth term of this sequence?(a) 147 (b) 76 (c) 123 (d) Cannot be determined
Difference between the squares of seventh and sixth term is 517 ( product of 2 primes 47 and 11) if a and b are the sixth and seventh term respectively then b^2 - a^2 = ( b + a) (b-a) = 47 * 11.. Solving b = 29 and a = 18...and now keep on calculating the further terms.. I think the answer ( 10th term) is 123
1.For each natural number N, define S(N) be the sum of digits of N.For eg: If N = 9801, S(N) = 9 + 8 + 0 + 1 = 18 N = 25, S(N) = 2 + 5 = 7How many natural numbers, N, exist such thatS(N) + S(N^2) = 2011N+N^2 = 2011
0 ?
N*(N+1) = 2011 , but N*(N + 1) is always even for N being a natural number
1.For each natural number N, define S(N) be the sum of digits of N.For eg: If N = 9801, S(N) = 9 + 8 + 0 + 1 = 18 N = 25, S(N) = 2 + 5 = 7How many natural numbers, N, exist such thatS(N) + S(N^2) = 2011N+N^2 = 2011
i don't think there exist any such (just a blind guess though have some clue)
see i got to this conclusion using this logic.
the sum of N and N^2 is 2011..so the number has to be less than 45..
secondly, since the sum of its digits is 2011, this implies that a number has to be numerous digits(dunno how many)
For a Fibonacci sequence, from the third term onwards, each term in the sequence is the sum of the previous two terms in that sequence. If the difference in squares of seventh and sixth terms of this sequence is 517, what is the tenth term of this sequence?(a) 147 (b) 76 (c) 123 (d) Cannot be determined
In the sequence 1,9,7,7,4,7,5,3,9,4,1, €Ś every digit from the fifth on is the sum of the preceding 4 digits mod 10.Does one of the following set ever occur in the sequence?a) 1,2,3,4 b) 3,2,6,9 c) 0,1,9,8 d) 7,9,5,3