Official Quant thread for CAT 2013

@ScareCrow28 said:
Since there is an addition of one extra digit : The number shown on the odometer is in the base 119δ5 --> Odometer Add 1 digit to every digit --> 1056Now, 1056 in base 11 = 10*121 + 5*11 + 6 = 1271 in base 10So , 1271 Sirjee?
why do we need to add 1 to every digit??
the step where u have converted the 1056 in decimal is not clear
@avaneeshvyas said:
why do we need to add 1 to every digit??the step where u have converted the 1056 in decimal is not clear
Because there was 1 digit more between the numbers 3 to 4. So, When the odometer was showing that weird symbol, it actually was the number 5.
So, first we cannot convert the number if it's in some weird synbol..We have to add 1 to every digit to take care of that interference
@ScareCrow28 said:
Because there was 1 digit more between the numbers 3 to 4. So, When the odometer was showing that weird symbol, it actually was the number 5.So, first we cannot convert the number if it's in some weird synbol..We have to add 1 to every digit to take care of that interference
so adding 1 to each digit of the number 9δ5.... what do we add to the symbol δ ? I mean we are not sure about the value are we
@avaneeshvyas said:
so adding 1 to each digit of the number 9δ5.... what do we add to the symbol δ ? I mean we are not sure about the value are we
Exactly..We just know that its value is "1" just like any other digit..in the number system
So, we add 1 to it such that If the odometer is showing δ that means it is in actual δ+1 = 5
Similarly for others
@ScareCrow28 said:
Exactly..We just know that its value is "1" just like any other digit..in the number systemSo, we add 1 to it such that If the odometer is showing δ that means it is in actual δ+1 = 5Similarly for others
got your point....one last question.......my understanding for numbers in different base systems is...that if the base is 2 there will be 2 numbers in the base system....similarly for decimal and whatever the base may be..... so my question is if a number is in base 10...then what are the digits that can be used to represent numbers in that base..... shouldn't it be 0-9 ? Please help me clear my doubt on this....
Twelve knights sit around a round table. Every knight hates the two
knights sitting next to him, but none of the other nine knights. A task group
of fve knights is to be sent to save a princess in trouble. No two knights who hate each other can be included in the group. In how many ways can
the group be selected?


x_x_x_x_x_
a+b+c+d+e = 2

=15

but it is wrong, can anybody explain why I am getting wrong??
Find the set of all positive integers n with the property that the set fn; n +
1; n + 2; n + 3; n + 4; n + 5g can be partitioned into two sets such that the
product of the numbers in one set equals the product of the numbers in the
other set.

@MANJULNEOGI said:
Two train A & B starts opposite each other, after meeting they reaches after 9 & 16 HOURS respectively. what is the ratio of their speeds?i know by shortcut formula ans is the square root of inverse ratio of their times.ans is 4/3but what is the logic?
look it this way:

A--------------------M-----------------------------------B

lets say speed of train A is a and that of B is b.
let M be the meeting point.--> the time taken by A and B to travel AM and BM respectively is same (say t)

now accordingly:
AM=a.t--------1
BM=b.t---------2

now given that they complete the remaining travel in 9 and 16 hrs respectively.

so,
BM/a=9--------3
AM/b=16------4

dividing 1 by 2 and 3 by 4 and using the result simultaneously
we get (a/b)^2= 16/9

or speed of A: speed of B= 4:3

@sujamait said:
Let ABCD be a cyclic quadrilateral such that one of its diagonals is a diameter of the circle. If AB = 72cm,find the measure of the diagonal which is not the diameter of the circle.I. Radius of the circle is 45 cm.II. Side opposite to AB is of length 45 rt 2 cm.
57.8 ??
Sixteen students took part in a math competition where every problem
was a multiple choice question with four choices. After the contest, it is found that any two
students had at most one answer in common. Determine the maximum number of questions.

@krum said:
@pavimai 16? n=3 to 18
ans is 10
@sparklingaubade said:
Twelve knights sit around a round table. Every knight hates the twoknights sitting next to him, but none of the other nine knights. A task groupof fve knights is to be sent to save a princess in trouble. No two knights who hate each other can be included in the group. In how many ways canthe group be selected?x_x_x_x_x_ a+b+c+d+e = 2=15but it is wrong, can anybody explain why I am getting wrong??
is it 36?
@sparklingaubade said:
Find the set of all positive integers n with the property that the set fn; n +1; n + 2; n + 3; n + 4; n + 5g can be partitioned into two sets such that theproduct of the numbers in one set equals the product of the numbers in theother set.
seems like no value possible as product of six consecutive numbers can't be perfect square(gut feeling :p)
AC is the Longest Chord of the circle with center O and Chord EF is parallel to AC. ADF=70* then what is EFA

FILE IS ATTACHED u can check
@Cat.Aspirant123 said:
AC is the Longest Chord of the circle with center O and Chord EF is parallel to AC. ADF=70* then what is EFAFILE IS ATTACHED u can check
Is the answer 20 degrees?
@Cat.Aspirant123 said:
AC is the Longest Chord of the circle with center O and Chord EF is parallel to AC. ADF=70* then what is EFAFILE IS ATTACHED u can check
20 deg?
@sparklingaubade said:
Twelve knights sit around a round table. Every knight hates the twoknights sitting next to him, but none of the other nine knights. A task groupof fve knights is to be sent to save a princess in trouble. No two knights who hate each other can be included in the group. In how many ways can the group be selected?
What exactly is the underlined part ??
@sparklingaubade said:
Find the set of all positive integers n with the property that the set fn; n +1; n + 2; n + 3; n + 4; n + 5g can be partitioned into two sets such that theproduct of the numbers in one set equals the product of the numbers in theother set.
Not possible

Product of 6 consecutive positive integers.
=> None of them can be a multiple of 7, as among 6 consecutive numbers we can have at most one number as multiple of 7 and if it is so, then only one set will have a number which is multiple of 7 (and in that case product of elements in both sets can not be equal)

Also, product of all elements has to be a perfect square

Since none of the 6 numbers will be a multiple of 7, we can say that n = 7k + 1
=> Product of the 6 numbers = (7k + 1)(7k + 2).....(7k + 6)
=> Product will be of form 7k + 720 or 7k + 6
But no perfect square can be of form 7k + 6

Hence, no such set can be possible
@Cat.Aspirant123 said:
AC is the Longest Chord of the circle with center O and Chord EF is parallel to AC. ADF=70* then what is EFAFILE IS ATTACHED u can check
As AC || EF, length of arc AE = Length of arc CF.
Hence angle EFA= angle FAC

Join DC.
angle FDC= angle FAC.................(angles contended by same arc)

angle ADC= ADF+FDC
but ADC= 90.............(angle contended by diameter)
& ADF= 70

So FDC= 20
So FDC=FAC= EFA = 20 degrees
@sparklingaubade said:
Sixteen students took part in a math competition where every problemwas a multiple choice question with four choices. After the contest, it is found that any twostudents had at most one answer in common. Determine the maximum number of questions.
was it compulsory to attempt each Q ? options hai toh dedo ?
@chillfactor said:
What exactly is the underlined part ??
i think its 5 sir

@gautam22 said:
can we draw a tangent parallel to AB in d attached figure,then d line joining the mid point of AB , centre of circle and point C all lie on d same straight line........can we do that....PFA the figure@chillfactor sir @krum sir
didn't get it

do we need to draw a tangent at C?