Official Quant thread for CAT 2013

@Cat.Aspirant123 said:
A square field of size 72 — 72 is to be covered by rectangular tiles (with integral edges) having a length to breadth ratio of 3 : 2. What is the difference between the minimum and the maximum number of tiles that can be used?860895858843
max no of tiles when rectangles are of size 3*2 = 24*36 = 864 (72*72/6)
min no of tiles when rectangles are of size 36*24 = 2*3 = 6
difference = 858
@Cat.Aspirant123 said:
A square field of size 72 — 72 is to be covered by rectangular tiles (with integral edges) having a length to breadth ratio of 3 : 2. What is the difference between the minimum and the maximum number of tiles that can be used?860895858843
24*36=864(length=3 breadth=2)
3*2=6(length=36 breadth=24)
864-6=858?
@Cat.Aspirant123 said:
The sum of two three digit numbers is divisible by 504. One of the two numbers is 6 times the other. What is the absolute difference between the two numbers?629456720360
x+6x is divisible by 504
7x is divisible by 504
x is three digit number
x=72
x=144
y=864
720
@soumitrabengeri said:
I tried it for almost 15 mins..had this question in my NMAT on 8th dec..the last number in the series was 150 though Did not get it even then..marked 80
In case of 150 to aa jayega.
But the series 6, 12, 36, ?, 144 doesn't make any pattern. Kuchh mistake h question mai,

in series 2, 6, 36, ?, 150,

First term=1^3+1=2
Second term=2^3+2^2=12
Third term=3^3+3^2=36
Fourth term=4^3+4^2=80
Fifth term=5^3+5^2=150
@vijay_chandola said:
In case of 150 to aa jayega.But the series 6, 12, 36, ?, 144 doesn't make any pattern. Kuchh mistake h question mai,in series 2, 6, 36, ?, 150,First term=1^3+1=2Second term=2^3+2^2=12Third term=3^3+3^2=36Fourth term=4^3+4^2=80Fifth term=5^3+5^2=150
Thanks a ton!!! Was worried about this since the day i gave my NMAT..marked 80 but thought that it was 90..thanks again

a fraction is such that of the double of the numerator and the triple of the denominator is changed by +10% and -30% resp. then we get 11% of 16/21. find the fraction.

a.4/25 b.2/25 c.3/25 d. none of these.

@vijay_chandola but y 2 in the beginning bhai?? 150 theek hai. wuestion me tho 6 12 36 ? 144(150) lelo.. but y 2 in the beginning??
@Cat.Aspirant123 said:
A square field of size 72 — 72 is to be covered by rectangular tiles (with integral edges) having a length to breadth ratio of 3 : 2. What is the difference between the minimum and the maximum number of tiles that can be used?860895858843
Maximum tiles =72*72/3*2=12*72=864
Minimum tiles=72*72/3*12*12*2=6

Maximum tiles-Minimum tiles=864-6=858
@IIM-A2013 said:
a fraction is such that of the double of the numerator and the triple of the denominator is changed by +10% and -30% resp. then we get 11% of 16/21. find the fraction.a.4/25 b.2/25 c.3/25 d. none of these.
2/25?
@IIM-A2013 said:
a fraction is such that of the double of the numerator and the triple of the denominator is changed by +10% and -30% resp. then we get 11% of 16/21. find the fraction.a.4/25 b.2/25 c.3/25 d. none of these.
(2x*110/100)/(3y*70/100) = 16/21 * 11/100

ratio = x : y = 2 : 25
@IIM-A2013 said:
a fraction is such that of the double of the numerator and the triple of the denominator is changed by +10% and -30% resp. then we get 11% of 16/21. find the fraction.a.4/25 b.2/25 c.3/25 d. none of these.
1.1*2*x/3*.7y=16/21*.11
x/y=2:25
@IIM-A2013 said:
a fraction is such that of the double of the numerator and the triple of the denominator is changed by +10% and -30% resp. then we get 11% of 16/21. find the fraction.a.4/25 b.2/25 c.3/25 d. none of these.
b. 2/25

(1.1*2x)/(0.7*3y) = (11*16)/(100*21)
x/y = 80/1000 = 2/25


@gautam22 said:
@chandrakant.k@vijay_chandola@ScareCrow28@grkkrgsir vo 6,12,36,?,144......vala ques maine post kara tha aur mera ye question bhi NMAT 8th dec vale mein aaya tha......to mere hisab se questin jo @soumitrabengeri sir ne post kara hai vo hoga ......so plz mere vale ques pe tym waste mat karo.....mereko lagta hai ki wat i hav posted is not rite
@gautam22 sir time toh bahut waste kara is question pe.. 😁 I'm not getting the answer even after replacing 144 by 150..
In the figure given below, what is the ratio of a to b?

(A) 2/1 (B) 4/1 (C) 1/4 (D) None

@ron123 said:
In the figure given below, what is the ratio of a to b?(A) 2/1 (B) 4/1 (C) 1/4 (D) None
D) none?
Three coins are tossed. Describe
(i) Two events which are mutually exclusive.
(ii) Three events which are mutually exclusive and exhaustive.
(iii) Two events, which are not mutually exclusive.
(iv) Two events which are mutually exclusive but not exhaustive.
(v) Three events which are mutually exclusive but not exhaustive.

Can anyone explain logic behind it with proper explanations?
@chandrakant.k said:
@vijay_chandola but y 2 in the beginning bhai?? 150 theek hai. wuestion me tho 6 12 36 ? 144(150) lelo.. but y 2 in the beginning??
Original question mai 2, 12, 36, ?, 144 thi series :neutral:

6 edit krne k baad aya :splat:

In a village consisting of p persons , x% can read and write. of the males alone y%,and of the females alone z% can read and write.find the number of males in the village in terms of p,x,y and z if z

a.p(x-z)/(y+x-z) b.p(x-z)/(y+x-2z) c.p(y-x)/(x-z) d. p(x-z)/(y-z).
tell me the approach how to solve this type of problems in exam?

@gnehagarg said:
Three coins are tossed. Describe(i) Two events which are mutually exclusive.(ii) Three events which are mutually exclusive and exhaustive.(iii) Two events, which are not mutually exclusive.(iv) Two events which are mutually exclusive but not exhaustive.(v) Three events which are mutually exclusive but not exhaustive.Can anyone explain logic behind it with proper explanations?
http://en.wikipedia.org/wiki/Mutually_exclusive_events
http://en.wikipedia.org/wiki/Collectively_exhaustive

The greatest number which will divide: 4003, 4136 and 4249:

a) 43
b) 41
c) 45
d) None of these
@IIM-A2013 said:
In a village consisting of p persons , x% can read and write. of the males alone y%,and of the females alone z% can read and write.find the number of males in the village in terms of p,x,y and z if za.p(x-z)/(y+x-z) b.p(x-z)/(y+x-2z) c.p(y-x)/(x-z) d. p(x-z)/(y-z).tell me the approach how to solve this type of problems in exam?
d. p(x-z)/(y-z)?

yM/100 + zF/100 = xp/100
yM/100 + z(p-M)/100 = xp/100

yM/100 + zp/100 - zM/100 = xp/100
M(y-z) = p(x-z)
M = p(x-z)/(y-z)