@ScareCrow28 said:a, b, c, d are integers such that:a 1. Prime2. Perfect square3. Not a perfect square4. CBD
It seems only series such as this satisfies: 1,2,2,4 / 4 6 6 9 / 9 12 12 16 / and so on
so, a is a perfect square ?
@Cat.Aspirant123 said:Five years ago, the average age of a family consisting five members was 40 years. Four years ago, a child was born. If a year ago, a man aged 60 years died, what is the present average age (in years) of the family? 42.533.666.577.5
45*5+4-61/5=168/5=33.6
@chandrakant.k said:Three VP's regularly visit the plant on different days. Due to labour unrest, VP(HR) regularly visits the plant after a gap of 2 days . VP(operations) regularly visits the plant after a gap of 3 days. VP(sales) regularly visits the plant after a gap of 5 days. The VP's dont devaiate from their individual scheules. The CEO of the comapny meets them when all the three VPs meet. CEO is on leave from Jan 5 2012 to Jan 28 2012. Last time CEO met them was on Jan 3 2012. When is the next time CEO meet all the Vp's (1mark) (XAT 2012)Options : 1) Feb 2 2012 2)Feb 7 2012 3) Feb 8 2012 4) Feb 3 2012 5) None of these
LCM of 2,3,5 is 30
Difference between 3 and 31 jan is 28
Upto 2 difference becomes 30
2nd feburary
@gautam22 said:6,12,36,?,144.....find d term? EDIT
Itni der bad edit kiaNahi nikal raha Are you sure 4th term he nikalna hai? ..
Are you sure 4th term he nikalna hai? ..@gautam22 said:96 nahi tha 90 tha.....60,70,80,the baki options....ek paper mein aaya tha
kaise?? :(
@grkkrg said:not able to solve this answer?
Options 60,70,80 and 90 hain 😞 saala koi pattern he ni banra
ABC is an obtuse angled triangle whose sides are 7 cm, 16 cm and y cm where y is an integer. Find the number of possible values of y.
@bullseyes said:ABC is an obtuse angled triangle whose sides are 7 cm, 16 cm and y cm where y is an integer. Find the number of possible values of y.
For an obtuse traingle,
c^2 > a^2 + b^2
where c is the largest side
i) let y be largest, then
y^2 > 16^2+7^2 = 305
y > 17
also y
so 18,19,20,21,22
ii) let 16 be largest side:
256 - 49 > y^2
y^2 y
also y + 7 > 16
y > 9
so y = 10,11,12,13,14
c^2 > a^2 + b^2
where c is the largest side
i) let y be largest, then
y^2 > 16^2+7^2 = 305
y > 17
also y
so 18,19,20,21,22
ii) let 16 be largest side:
256 - 49 > y^2
y^2 y
also y + 7 > 16
y > 9
so y = 10,11,12,13,14
@gnehagarg said:45*5+4-61/5=168/5=33.6LCM of 2,3,5 is 30Difference between 3 and 31 jan is 28Upto 2 difference becomes 302nd feburary
No madam. Answer is 8th feb. It is not LCM of 2 3 5
as they visit after a gap of 2 3 and 5. so they every 3rd 4th and 6th day
@ScareCrow28 said:Options 60,70,80 and 90 hain saala koi pattern he ni banrash
dhimak kharab hogaya koi tho solve karo
koi tho solve karo @chandrakant.k said:dhimak kharab hogaya koi tho solve karo
I tried it for almost 15 mins..had this question in my NMAT on 8th dec..the last number in the series was 150 though
Did not get it even then..marked 80
@bullseyes said:ABC is an obtuse angled triangle whose sides are 7 cm, 16 cm and y cm where y is an integer. Find the number of possible values of y.
7^2+16^
y>rt305
y>17._
y
y>9
y=18,19,20,21,22
16^2+y^2
No solution
7^2+y^2
y
y
y
y>9
10,11,12,13,14
@soumitrabengeri said:I tried it for almost 15 mins..had this question in my NMAT on 8th dec..the last number in the series was 150 though Did not get it even then..marked 80
@YouMadFellow aa chuke hai, fir kya ghabrana .. :)
@rachit_28 said:@YouMadFellow aa chuke hai, fir kya ghabrana ..
.. chillfactor Sir ke rehte yeh kaise bol sakte ho Anyways, maine bhi try kiya tha nahi hua, maine yeh dekha
6, 12, 36, _ , 144
6 = 1*6
12 = 2*6
36 = 6*6
_ = _*6
144 = 24*6
I see that every number is divisible by 6, now 1,2,6,_, 24 is the issue
The differences seem to be perfect squares 1,4, and so on.. but 24 doesn't fit in.. 
The sum of two three digit numbers is divisible by 504. One of the two numbers is 6 times the other. What is the absolute difference between the two numbers?
629
456
720
360
629
456
720
360
@Cat.Aspirant123 said:The sum of two three digit numbers is divisible by 504. One of the two numbers is 6 times the other. What is the absolute difference between the two numbers?629456720360
720?
Let the 2 numbers be x and 6x
Since both are 3 digit numbers, the addition cannot be 504
Consider the addition to be the next multiple of 504 i.e. 1008
7x = 1008
x = 144
144+144*6 = 1008 (divisible by 504)
@Cat.Aspirant123 said:The sum of two three digit numbers is divisible by 504. One of the two numbers is 6 times the other. What is the absolute difference between the two numbers?
629
456
720
360
maximum possible number 999
maximum sum = 999+999 = 1998
maximum sum which is divisble by 504 is 504*3 = 1512
7X = 1512
x = 216
6x = 1296
So not possible
Now next highest number = 1008
7x = 1008 => x = 144
6x = 864
absolute difference = 720
@Cat.Aspirant123 said:The sum of two three digit numbers is divisible by 504. One of the two numbers is 6 times the other. What is the absolute difference between the two numbers?629456720360
720?
@Cat.Aspirant123 said:The sum of two three digit numbers is divisible by 504. One of the two numbers is 6 times the other. What is the absolute difference between the two numbers?629456720360
720??
A square field of size 72 — 72 is to be covered by rectangular tiles (with integral edges) having a length to breadth ratio of 3 : 2. What is the difference between the minimum and the maximum number of tiles that can be used?
860
895
858
843
860
895
858
843