@mailtoankit said:0.4...iift ka Q hai
pata hai yaar...wahi se daal rhi hun..mujhse nahi hua tha inna lallu qs 
@sonamaries7 said:zinda hai yeh thread..testing ho gyi chalo 1 aur The probablity that in a household LPG will last 60 days or more is 0.8 and that it will last at most 90 days is 0.6. THe prob that the LPG will last 60 to 90 is:0.40.50.75none
.4 fluke :D
@Estallar12: _/\_ welcome. Aap jaison ki kaafi jarurat h yahan ๐
Jan najar nahi aa rahi thread mai :splat:
@sonamaries7 said:pata hai yaar...wahi se daal rhi hun..mujhse nahi hua tha inna lallu qs
mujhse bhi nahi hua tha yaar...tukka maara tha..
If An belongs to integer
A0 = p, where p > 0 is a prime number,
An+1 = 2An + 1, for n = 0, 1, 2, .....
How many values of p exist such that sequence consists entirely of prime numbers?
0
1
8
more than 8
A0 = p, where p > 0 is a prime number,
An+1 = 2An + 1, for n = 0, 1, 2, .....
How many values of p exist such that sequence consists entirely of prime numbers?
0
1
8
more than 8
Chalo 1 aur,
Ashish opens his mother's cupboard without switching on the lights, knowing that his mother has kept 10 packs of chips and biscuits in the cupboard. He pulls out 3 packs and all 3 turn out to be chips. What is the prob that the snack cupboard contains 1 pack of biscuits and 9 packs of chips?
@vijay_chandola : dekha, mein @Estallar12 ko le ayyi yaha ๐
@vijay_chandola , @mailtoankit : yaar tum log tukke bade maarte ho..next time maine bhi maarne hai
Find the greatest term in the expansion of โ3(1 + (1/โ3))^20
@sonamaries7 said:zinda hai yeh thread..testing ho gyi chalo 1 aur The probablity that in a household LPG will last 60 days or more is 0.8 and that it will last at most 90 days is 0.6. THe prob that the LPG will last 60 to 90 is:0.40.50.75none
60 days or less =0.2
More than 90 days=0.4
60-90 days= 1-0.2-0.4= 0.4
@Torque024 said:If An belongs to integerA0 = p, where p > 0 is a prime number,An+1 = 2An + 1, for n = 0, 1, 2, .....How many values of p exist such that sequence consists entirely of prime numbers?018more than 8
Only ONE when p = 2. ? 
@sonamaries7 said:Chalo 1 aur,Ashish opens his mother's cupboard without switching on the lights, knowing that his mother has kept 10 packs of chips and biscuits in the cupboard. He pulls out 3 packs and all 3 turn out to be chips. What is the prob that the snack cupboard contains 1 pack of biscuits and 9 packs of chips?@vijay_chandola : dekha, mein @Estallar12 ko le ayyi yaha @vijay_chandola , @mailtoankit : yaar tum log tukke bade maarte ho..next time maine bhi maarne hai
10 chips, 0 biscuits P(3 chips) = 120/120
9 chips, 1 biscuit P(3 chips) = 9C3/10C3 = 84/120
8 chips, 2 biscuit P(3 chips) = 8C3/10C3 = 56/120
.
.
.
P(E) = 84/(120 + 84 + 56 + 35 + 20 + 10 + 4 + 1) = 14/55
9 chips, 1 biscuit P(3 chips) = 9C3/10C3 = 84/120
8 chips, 2 biscuit P(3 chips) = 8C3/10C3 = 56/120
.
.
.
P(E) = 84/(120 + 84 + 56 + 35 + 20 + 10 + 4 + 1) = 14/55
@Torque024 said:If An belongs to integerA0 = p, where p > 0 is a prime number,An+1 = 2An + 1, for n = 0, 1, 2, .....How many values of p exist such that sequence consists entirely of prime numbers?018more than 8
p=2..??
@Torque024 said:10 chips, 0 biscuits P(3 chips) = 120/1209 chips, 1 biscuit P(3 chips) = 9C3/10C3 = 84/1208 chips, 2 biscuit P(3 chips) = 8C3/10C3 = 56/120...P(E) = 84/(120 + 84 + 56 + 35 + 20 + 10 + 4 + 1) = 14/55
Seems familiar :mg:
@Torque024 said:If An belongs to integerA0 = p, where p > 0 is a prime number,An+1 = 2An + 1, for n = 0, 1, 2, .....How many values of p exist such that sequence consists entirely of prime numbers?018more than 8
0 
:embarrassed:
:embarrassed:What's going on here ppl.
@Torque024 said:If An belongs to integerA0 = p, where p > 0 is a prime number,An+1 = 2An + 1, for n = 0, 1, 2, .....How many values of p exist such that sequence consists entirely of prime numbers?018more than 8
if, a0=6k+1
a2=12k+3 = 3(m) = so nt prime
if,a0=6k-1
a2=12k -1
a3=24k-1
a2=12k+3 = 3(m) = so nt prime
if,a0=6k-1
a2=12k -1
a3=24k-1
48k-1
96k-1
192k-1
384k-1
now,k=1, will nt satisfy..as we have 96k-1 which giv unit digit 5..
k=2, will nt satisfy..aas 48k-1 gives unit digit 5
k=3,a2 will fail
k=4,a3 ..
k=5,15,20,30.... looks fine looks l ike more than 8..
@sujamait said:if, a0=6k+1a2=12k+3 = 3(m) = so nt primeif,a0=6k-1a2=12k -1 a3=24k-148k-196k-1192k-1386k-1now,k=1, will nt satisfy..as we have 96k-1 which giv unit digit 5..k=2, will nt satisfy..aas 48k-1 gives unit digit 5k=3,a2 will failk=4,a3 ..k=5,15,20,30.... looks fine looks l ike more than 8..
@Gaul said:Find the greatest term in the expansion of หลก3(1 + (1/ หลก3))^20
N = Numerator/ Denominator
Now, Deno = 3^(10 - 1/2) = 3^(19/2)
Num = ( 1 + 3^(1/2) )^20
General term T(r) = 20C(r) *(3^(r/2))
Now, T(r + 1)/T(r) = (20-r)*(3^(1/2))/ (r+1) = A
Now, A >1 => r
=> T(13) should be the highest
=> Greatest term = 20C13/27 ?