Official Quant thread for CAT 2013

@gautam22 said:
Dragons have to meet for a brainstorm in a convention center. The delegates have to be selected to provide the maximum efficiency of the brainstorm session. A dragon has any amount of heads, and for any N, any amount of N-headed dragons is available if needed. The problem is that the size of the convention center is limited so no more than 1000 heads can fit into the assembly hall. The intellectual power of a dragon pack is the product of head numbers of dragons in the pack. How should an optimum pack look like (the total number of dragons, the head number distribution)?
2*a+3*b=1000
we have to maximize b's

=> b=332, a=2

~courtesy @chillfactor Sir. :D
@vijay_chandola said:
Weights of the 5 boxes are positive integers and their mean as well as median is 6. If the only mod is 8, then find the sum of weights of heaviest box and lightest box.
11

Suppose five boxes be,

__ __ __ __ __
x1 x2 x3 x4 x5

here X3= 6
X4 = X5= 8

mean=6
sum= 6*5=30
X1+x2=8
lightest box can only be 3

hence, sum= 3+8=11
@kleptomaniac_20 1000 is the total no of heads of dragon. u r getting it incorrect.
@maddy2807 Thats what I said bro : If no. of dragons are n each with x heads then nx
@gautam22 You are spot on
@gautam22
Bhai aisa lag raha hai ki that u r preparing for IIT-JEE. it all seems like Physics question with equations that were nightmare for me.
@maddy2807 said:
@gautam22Bhai aisa lag raha hai ki that u r preparing for IIT-JEE. it all seems like Physics question with equations that were nightmare for me.
+1 to the post.
Even XAT wouldn't consider questions with this kind of tone :O

@gautam22 : 11 is correct :thumbsup:
@anytomdickandhary said:
chance of any two of them being born on same day is =1- chance of all of them being born on different days.total number of possible ways = 7^7now first person can be born on any of the 7 days, next person can be born on any of the 6 days, next person can be born on any of remaining 5 days....and so on.So possible no. of ways in which all are born on different days = 7*6*5..*2*1 = 7!hence chance that at least 2 of them are born on same day = 1- 7!/7^7 = 1 - 6!/7^6 ATDH.
Can you check my method?
Out of 7 persons i selected 2 persons in 7C2 ways
Out of 7 days i selected 1 day in 7C1
Total ways 7^7

chance =7C2*7C1/7^7

In a room there are 7 persons. The chance that 2 of them were born on the same day of the week is?

@gautam22 said:
On the surface of the planet lives a vampire , that can move with the speed not greater than u. A vampire slayer spaceship approaches to the planet with its speed v. As soon as the spaceship sees the vampire it shots a silver bullet - the vampire is dead. Prove that if v/u > 10 , the vampire slayer can accomplish his mission, even the vampire is trying to hide.
pls provide options 😉
Let X be a four-digit positive integer such that the unit digit of X is prime and the product of all digits of X is also prime. How many such integers are possible?
@gnehagarg 2160/7^5
@sauravd2001 said:
Let X be a four-digit positive integer such that the unit digit of X is prime and the product of all digits of X is also prime. How many such integers are possible?
number can be
1111 total case= 1
1112 total cases= 4
1113 total cases= 4
1115 total cases= 4
1117 total cases= 4

total= 17?
x,y and z are positive integers such that x
,y and z are positive integers such that
x What is the maximum value of x+y+z?
@hedonistajay said:
x,y and z are positive integers such that x
such that x?
@sauravd2001 said:
Let X be a four-digit positive integer such that the unit digit of X is prime and the product of all digits of X is also prime. How many such integers are possible?
Product is prime. so three numbers will be 1, 1, 1
also, unit digit is prime.

So, possible numbers=1112, 1113, 1115, 1117= 4
@maddy2807 said:
number can be1111 total case= 11112 total cases= 41113 total cases= 41115 total cases= 41117 total cases= 4total= 17?
1 is not a prime number right? :neutral:
@vijay_chandola said:
1 is not a prime number right?
mr cooper. no it is not
@maddy2807 said:
such that x?


x,y and z are positive integers such that x ,y and z are positive integers such that
x

@gautam22
@vijay_chandola
i m always confused on 1 is a prime or not.
in that case we can filter out the cases and mark ans as 4.
1112
1113
1115
1117
@maddy2807 bhai 4 hi hai answere
@vijay_chandola correct