@sauravd2001 said:@chillfactor then with 3 fair dices it must be 84 i guess?
C(8, 5)=56
@bullseyes said:nice!!sir u have any other method besides this one??
All same - 6 ways
3 same, 1 different - C(6, 2)*2 = 30 ways
2 same, 2 same - C(6, 2) = 15 ways
2 same, 1 different, 1 different - C(6, 3)*3 = 60 ways
all different - C(6, 4) = 15 ways
Total = 126 ways
@sauravd2001 for 3 dices
a + b + c + d + e + f = 3
C(8, 5) = 56 ways
@gautam22 said:How it is that when I buy yellow bananas at three shillings a bunch and the same number of red ones at four shillings a bunch I would get two more bunches for the same amount if I divided the money evenly between the yellow and red bananas?
1 bunch=3 shilling
x bunch =3x shilling
1 bunch=4 shilling
x bunch=4x shilling
In case,he divides shilling evenly he get 2 more bunchs
7x/2*1/3+7x/2*1//4=2x+2
7x/2*7/12=2(x+1)
49x=48x+48
x=48
@chillfactor said:All same - 6 ways3 same, 1 different - C(6, 2)*2 = 30 ways2 same, 2 same - C(6, 2) = 15 ways2 same, 1 different, 1 different - C(6, 3)*3 = 60 waysall different - C(6, 4) = 15 waysTotal = 126 ways
i wanted u to write this one.. 😃
P,Q,R,S are non zero integers. is perfect square PQRS>2500??
1) PQ is a perfect square,
2) RS is a perfect square.
a) can be answered by one statement alone
b) can be answered by either alone
c) can be answered by using both
d) cannot be answered
@grkkrg said:151?SP = 60 CP = 40 OH = 3000P = 1 P = n(SP - CP) - 3000 = 20n - 3000 20n - 3000 >= 1 20n >= 3001 n >= 150.5 n = 151
Bro..Yar options diff diye huae hai..OA is 200..
@bullseyes said:i wanted u to write this one.. P,Q,R,S are non zero integers. is perfect square PQRS>2500??1) PQ is a perfect square,2) RS is a perfect square.a) can be answered by one statement aloneb) can be answered by either alonec) can be answered by using bothd) cannot be answered
Is it A??
@bhatkushal said:How is this X as 49 and y=25
I hav not written X=49 and Y =25 anywhere....where is the problem?
@vijay_chandola said:Let the number of items be nSo, production cost=40*n+3000Selling price of n items=n*60profit =60*n-(40*n+3000)=20*n-3000 That should be greater that 1==> 20*n-3000>1=> n> 150So he has to produce at-least 151 units to make 1 rupee profit.
@testBasu said:is the answer 151???
@mailtoankit said:151?
@sauravd2001 said:@Shray14 151 bhai 150 pe c.p=9000sp bhi 9000 no profit no loss 151 pe 2 rs profit
Bhai logo OA is 200..
I too got the same ans wid the same approaches..but 200
@grkkrg said:Rs.1 hai ya Rs.1000 hai?
Han yahi toh
if it is Rs 1 then it is 151..and if it is 1000 then it is 200..
statement mein Rs 1 hi hai bro..might be statement is wrong??
@bullseyes said:i wanted u to write this one.. P,Q,R,S are non zero integers. is perfect square PQRS>2500??1) PQ is a perfect square,2) RS is a perfect square.a) can be answered by one statement aloneb) can be answered by either alonec) can be answered by using bothd) cannot be answered
c) 1681 is the no
@Shray14 said:Bhai logo OA is 200..I too got the same ans wid the same approaches..but 200
If you have posted the correct question, then answer has to be 151 :angry:
Can you tell me the source, from you have taken the question?
@vijay_chandola said:If you have posted the correct question, then answer has to be 151 Can you tell me the source, from you have taken the question?
Its from TCYonline.
@bhatkushal said:then,x/Sa=49/12..........Iy/Sb=25/12...............IIplease xplain this stp....
AC=x(DISTANCE TRAVELED BY FIRST PERSON TO POINT C )
SPEED OF FIRST PERSON IS Sa
TIME TAKEN BY HIM TO TRAVEL FROM A TO C =x/Sa..............i
NOW WHEN HE WAS AT A TIME WAS 12 NOON AND WHEN HE REACHED C TIME WAS 5 PAST 4
THEN,TIME TAKEN BY HIM TO TRAVEL FROM A TO C =4+5/60=49/12...........ii
EQUATING i AND ii,WE GET x/Sa=49/12
SIMILARLY ,y/Sb=25/12...........HOPE YOU GOT IT
@bullseyes said:i wanted u to write this one.. P,Q,R,S are non zero integers. is perfect square PQRS>2500??1) PQ is a perfect square,2) RS is a perfect square.a) can be answered by one statement aloneb) can be answered by either alonec) can be answered by using bothd) cannot be answered
c) can be answered by both the statement together
PQ perfect square=16
RS perfect square=81
then perfect square PQRS ,i.e.,1681 not greater than 2500
PQ perfect square=16
RS perfect square=81
then perfect square PQRS ,i.e.,1681 not greater than 2500
The weights available with a shopkeeper are 1 kg, 2 kg, 4 kg, 8 kg, 16 kg, . . . . . . and so on. If the shopkeeper is to weigh 3240 kg, using not more than one weight of each kind and only one of the pans of the weighing scale to place the weights, find the total number of standard weights required.
a) 11
b) 5
6) 12
7) 6
@vijay_chandola said:The weights available with a shopkeeper are 1 kg, 2 kg, 4 kg, 8 kg, 16 kg, . . . . . . and so on. If the shopkeeper is to weigh 3240 kg, using not more than one weight of each kind and only one of the pans of the weighing scale to place the weights, find the total number of standard weights required.a) 11b) 56) 127) 6
5..
@vijay_chandola said:The weights available with a shopkeeper are 1 kg, 2 kg, 4 kg, 8 kg, 16 kg, . . . . . . and so on. If the shopkeeper is to weigh 3240 kg, using not more than one weight of each kind and only one of the pans of the weighing scale to place the weights, find the total number of standard weights required.a) 11b) 56) 127) 6
b)5?
3240 base 10 = 110010101000 base 2
3240 base 10 = 110010101000 base 2
@bullseyes said:at 19:00 ?? Find total no. of possible outcomes for 4 identical fair dices
number of 1's+number of 2's +number of 3's +number of 4's+number of 5's +number of 6's=4
a+b+c+d+e+f=4
9C5=126