Que:-One day I stared from A to B at exactly 12 noon.My friend started from B to A at exactly 2:00 pm.We met at 5 Past 4 and reached our destinations exactly at the same time.What time was it?Please explain the solution...
at 19:00 ??
Find total no. of possible outcomes for 4 identical fair dices
a 6-digit number. The sum of the digits is 43.And only two of the following three statements about the number are true:(1) it's a square number,(2) it's a cube number, and(3) the number is under 500000.ye nahi ho raha
A manufacturer of a certain item can sell all he can produce at the selling price of Rs 60 each. It costs him Rs 40 in materials and labour to produce each item and he has overhead expenses of Rs 3000 per week in order to operate that plant. The number of units he should produce and sell in order to make a profit of at least Rs 1 per week is??
There are one thousand lockers and one thousand students in the school. The principal asks the first student to go to every locker and open it. Then he has the second student go to every second locker and close it. The third goes to every third locker and, if it is closed, he opens it, and if it is open, he closes it. The fourth student does this to every fourth locker, and so on. After the process is completed with the thousandth student, how many lockers are open?
The numbers which have odd number of factors make lockers open.
A manufacturer of a certain item can sell all he can produce at the selling price of Rs 60 each. It costs him Rs 40 in materials and labour to produce each item and he has overhead expenses of Rs 3000 per week in order to operate that plant. The number of units he should produce and sell in order to make a profit of at least Rs 1 per week is??
A manufacturer of a certain item can sell all he can produce at the selling price of Rs 60 each. It costs him Rs 40 in materials and labour to produce each item and he has overhead expenses of Rs 3000 per week in order to operate that plant. The number of units he should produce and sell in order to make a profit of at least Rs 1 per week is??
Let the number of items be n
So, production cost=40*n+3000
Selling price of n items=n*60
profit =60*n-(40*n+3000)=20*n-3000
That should be greater that 1
==> 20*n-3000>1
=> n> 150
So he has to produce at-least 151 units to make 1 rupee profit.
A manufacturer of a certain item can sell all he can produce at the selling price of Rs 60 each. It costs him Rs 40 in materials and labour to produce each item and he has overhead expenses of Rs 3000 per week in order to operate that plant. The number of units he should produce and sell in order to make a profit of at least Rs 1 per week is??
151?
SP = 60 CP = 40 OH = 3000
P = 1 P = n(SP - CP) - 3000 = 20n - 3000 20n - 3000 >= 1 20n >= 3001 n >= 150.5 n = 151
a is the no of dices showing 1b is the no of dices showing 2c is the no of dices showing 3d is the no of dices showing 4e is the no of dices showing 5f is the no of dices showing 6a + b + c + d + e + f = 4So, 9C5 = 126 outcomes
A manufacturer of a certain item can sell all he can produce at the selling price of Rs 60 each. It costs him Rs 40 in materials and labour to produce each item and he has overhead expenses of Rs 3000 per week in order to operate that plant. The number of units he should produce and sell in order to make a profit of at least Rs 1 per week is??
Que:-One day I stared from A to B at exactly 12 noon.My friend started from B to A at exactly 2:00 pm.We met at 5 Past 4 and reached our destinations exactly at the same time.What time was it?Please explain the solution...
A _______x_______C_______y______B let C be their meeting point and AC=x,BC=y let speed of person starting from A and B be Sa and Sb respectively then,x/Sa=49/12..........I y/Sb=25/12...............II also x/Sb=y/Sa..........III using I,II,III........we get Sb/Sa=x/y=7/5...........IV now x/Sb=7y/5Sb=7 x 25/5x12......(using IV,II) =35/12 required time=12+49/12+35/12=12+7=19
A _______x_______C_______y______Blet C be their meeting point and AC=x,BC=ylet speed of person starting from A and B be Sa and Sb respectivelythen,x/Sa=49/12..........Iy/Sb=25/12...............IIalso x/Sb=y/Sa..........IIIusing I,II,III........we getSb/Sa=x/y=7/5...........IVnow x/Sb=7y/5Sb=7 x 25/5x12......(using IV,II)=35/12required time=12+49/12+35/12=12+7=19
