Official Quant thread for CAT 2013

@deedeedudu said:
(x-18)(y-54)=18*54=2^2*3^5(x-18)=1,3,9,274 values

a, b, c, d, e, f are six positive integers such that :

b+c+d+e = 4a
c+f=3a
c+d+e=2f
f=2d
e+f=2c+1

"a" is a prime number between 12 and 20.

the value of f is_________?

@gautam22 said:
sir 81 kyun nahi liya?
Missed it edited and dont call me sir yaar
@Torque024 said:
@rubikmath@soham2208@gautam22First time I also got 5, but it ain't OA.
@Torque024 I don't understand, is only X less than 100, or even Y is less than 100 ? 😐

This is right => (X-18)*(Y-54) = (2^2)*(3^5)

Now, X - 18 is odd -> X - 18= 1/-1/3/-3/9/-9/27/81

So, X = 19/17/21/15/27/9/45/99
corresponding values of Y = 54*19/-ve/54*7/-ve/54*3/-ve/90/76

So, what is the flaw here ? If Y is not less than 100, there are 5 solutions, otherwise 2 ? :/
@gautam22 said:
OA kya hai?

2 dia hua hai, mera bhi 5 hi aa rha.

@kingsleyx said:
a, b, c, d, e, f are six positive integers such that :b+c+d+e = 4ac+f=3ac+d+e=2ff=2de+f=2c+1"a" is a prime number between 12 and 20.the value of f is_________?
28?
@kingsleyx said:
a, b, c, d, e, f are six positive integers such that :b+c+d+e = 4ac+f=3ac+d+e=2ff=2de+f=2c+1"a" is a prime number between 12 and 20.the value of f is_________?
28?
@kingsleyx said:
a, b, c, d, e, f are six positive integers such that :b+c+d+e = 4ac+f=3ac+d+e=2ff=2de+f=2c+1"a" is a prime number between 12 and 20.the value of f is_________?
28
@kingsleyx said:
a, b, c, d, e, f are six positive integers such that :b+c+d+e = 4ac+f=3ac+d+e=2ff=2de+f=2c+1"a" is a prime number between 12 and 20.the value of f is_________?
a=17 and f= 28 ?
If 'a' is one of the roots of x^5-1=0 and a not equals 1,then what is the value of a^15+a^16+a^17...+a^50?
@Torque024 said:
If 'a' is one of the roots of x^5-1=0 and a not equals 1,then what is the value of a^15+a^16+a^17...+a^50?
How many times do we solve this :/ ?

http://www.pagalguy.com/forums/quantitative-ability-and-di/official-quant-thread-cat-2011-part-3-t-69715/p-2841386/r-2854151
@soham2208 It was for practice

Alby, Benny, Cindy and Dan houses forms a square field ABCD. A cow, in a square field, is 13 meters from Benny's house, 17 meters from Dan's house, and 20 meters from Cindy's house. Find the area of the field. Assume house to be a point object and field to be flat.

@kingsleyx said:
a, b, c, d, e, f are six positive integers such that :b+c+d+e = 4ac+f=3ac+d+e=2ff=2de+f=2c+1"a" is a prime number between 12 and 20.the value of f is_________?
28?
The average weight of 8 people decreases by 2 kgs, when two new people are added to the
group. If the difference between the original weight and new weight is 36 kgs, find the new total
weight of the people.
@Torque024 said:
If 'a' is one of the roots of x^5-1=0 and a not equals 1,then what is the value of a^15+a^16+a^17...+a^50?

See in case of X^3 - 1 = 0 , the roots are cube roots of unity , i.e 1,w,w^2.

In it 1+w+w^2 = 0

and w^3 = 1 is applicable.

Now coming to this case: X^5 - 1 = 0 ;

Here 5th roots of unity is there so roots : 1,w,w^2,w^3,w^4

So, 1+w+w^2+w^3+w^4 = 0

and w^5 = 1;

Let a = w ;

w^15 ( 1 + w + w^2 + w^3 + w^4) +....+ w^45 ( 1 + w + w^2 + w^3 + w^4) + w^50

= w^50

= 1

Hello everyone..m stuck in ths ques..pls help ..
if a+b+c=8,then the value of (a-4)^3+(b-3)^3+(c-1)^3-3(a-4)(b-3)(c-1) is
a)2
b)4
c)1
d)0

@Cat.Aspirant123 said:
The average weight of 8 people decreases by 2 kgs, when two new people are added to thegroup. If the difference between the original weight and new weight is 36 kgs, find the new totalweight of the people.
260 kg?
@Cat.Aspirant123 said:
The average weight of 8 people decreases by 2 kgs, when two new people are added to thegroup. If the difference between the original weight and new weight is 36 kgs, find the new totalweight of the people.
260 ?
The distance between Shyam's house and Suman's house is 16 kms. Shyam left his house at 7
a.m. and headed towards Suman's house at the rate of 5 km per hour. Suman left her house at 8 a.m.
and headed towards Shyam's house at the rate of 6 km per hour. At what time will they meet?
a) 11 a.m. b) 2 p.m. c) 10 a.m. d) 9 a.m. e) 12.00 noon
@Cat.Aspirant123 said:
The average weight of 8 people decreases by 2 kgs, when two new people are added to thegroup. If the difference between the original weight and new weight is 36 kgs, find the new totalweight of the people.
260 ?