Official Quant thread for CAT 2013

@sauravd2001 said:
Let
N
be the smallest positive integer with six positive odd integer divisors and twelve positive even integer divisors. Find the sum of the digits of
N
?
N =180
Sum = 9
@sauravd2001 said:
Let N be the smallest positive integer with six positive odd integer divisors and twelve positive even integer divisors. Find the sum of the digits of N?
18?
@sauravd2001 said:
Let N be the smallest positive integer with six positive odd integer divisors and twelve positive even integer divisors. Find the sum of the digits of N?
number is of the form 2*3^a*5^b...
smallest = 2^2*3^2*5 = 4*9*5=180

sum = 9


@krum said:
number is of the form 2*3^a*5^b...
smallest = 2*3^2*5 = 2*9*5=90

sum = 9

90 has 6 even factors
Let the roots of x3 + 3x2 + 4x €“ 11 = 0 be a, b, c and the roots of x3 + rx2 + sx + t = 0 are a + b, b + c, c + a the find the value of t?
@sauravd2001 said:
Let N be the smallest positive integer with six positive odd integer divisors and twelve positive even integer divisors. Find the sum of the digits of N?
Total factors=18=2 * 3^2
(1+1)(2+1)(2+1)
Smallest will be 2^2*3^2*5=180
Sum 9
@Torque024
@techsurge
@krum
@19rsb bhai 9,18 mein se hi hai check for 180 else 18 nswere

Go for A

@19rsb options
@sauravd2001 said:
Let the roots of x3 + 3x2 + 4x €“ 11 = 0 be a, b, c and the roots of x3 + rx2 + sx + t = 0 are a + b, b + c, c + a the find the value of t?
a+b+c=-3
ab+bc+ac=4
abc=11



t=-(a+b)(b+c)(c+a)
t=-(ab+ac+b^2+bc)(c+a)=-(abc+a^2b+ac^2+a^2c+b^2c+b^2a+bc^2+abc)
t=-(a+b+c)(ab+bc+ac)+abc
t=3*4+11
t=23
@krum yesh i was right some stupid was contradicting me so i posted it over here to check whether m right or wrong
@sauravd2001 said:
@19rsb options
bhai options kaa toh bada chakkar hai mere pass jo pdf hai usmein quest aur OA hi diya hai bas....
@chillfactor said:
Let me reframe the questionP is a set of n consecutive integers such that sum of digits of any of these n numbers is not divisible by 9. Find the maximum possible value of n.@naga25frenchnothing was mentioned in the question (a1, a2, a3, ..., an can be equal or may be not). They can be equal unless mentioned in the question
Every 9th number whose sum of digits is divisible by 9.So,we can take maximum 8
Is it right?

ok an easy ques ....... don't know the OA ....with no options either .... :P


A container filled with milk holds 20 litres. 4 litres of milk is removed and replaced with water. Then 8 litres of the solution is replaced with water. Then 16 litres removed and replaced with water. Find the ratio of milk to water....
@gnehagarg why 7??why not 8 ?
10,11,12,13,14,15,16,17
@SNAPstER said:
ok an easy ques ....... don't know the OA ....with no options either ....A container filled with milk holds 20 litres. 4 litres of milk is removed and replaced with water. Then 8 litres of the solution is replaced with water. Then 16 litres removed and replaced with water. Find the ratio of milk to water....
1.92:18.08?

any formula ?? i don't have the ans ...... please tell me how did u do

@SNAPstER said:
ok an easy ques ....... don't know the OA ....A container filled with milk holds 20 litres. 4 litres of milk is removed and replaced with water. Then 8 litres of the solution is replaced with water. Then 16 litres removed and replaced with water. Find the ratio of milk to water....
after first - M=16, W=4
after 2nd - M=16-8*16/20=9.6, W=10.4
after 3rd - M=9.6-16*9.6/20=1.92, W=18.08

ratio = 12/113
@SNAPstER 16:4
then 4:1
ratio then 8 liters out means
16-4-2.25=9.75
then water4-1.75=2.25
now 8 liter added water
9.75:10.25
then 16 litre removed means
7.8 out of milk and 8.2 out of water
9.75-7.8=1.95
and water 10.25-8.2=2.05
then 16 litre added meanws
18.05
ratio
1.95:18.05

@SNAPstER said:
ok an easy ques ....... don't know the OA ....with no options either ....A container filled with milk holds 20 litres. 4 litres of milk is removed and replaced with water. Then 8 litres of the solution is replaced with water. Then 16 litres removed and replaced with water. Find the ratio of milk to water....
12/113?