Official Quant thread for CAT 2013

MBA CAT 2024
6681
@kingsleyx said:
Two numbers are chosen randomly from the interval [0, 1]. What is the probability that they differ by more than their average?
|a - b| > (a + b)/2
When a > b, a > 3b
and when b > a, b > 3a

Plot it on the graph

Probability = 2*(1/2)*1*(1/3)/(1*1) = 1/3

In a triangle ABC, sides are a, b, c such that a³ + b³ + c³ = 3abc. Find the measure of angle A
a) 30º
b) 45º
c) 60º
d) 90º
6682
@chillfactor said:
|a - b| > (a + b)/2When a > b, a > 3band when b > a, b > 3aPlot it on the graphProbability = 2*(1/2)*1*(1/3)/(1*1) = 1/3In a triangle ABC, sides are a, b, c such that a³ + b³ + c³ = 3abc. Find the measure of angle Aa) 30ºb) 45ºc) 60ºd) 90º
60 deg?
6683
@chillfactor said:
|a - b| > (a + b)/2When a > b, a > 3band when b > a, b > 3aPlot it on the graphProbability = 2*(1/2)*1*(1/3)/(1*1) = 1/3In a triangle ABC, sides are a, b, c such that a³ + b³ + c³ = 3abc. Find the measure of angle Aa) 30ºb) 45ºc) 60ºd) 90º
is it 60..becuase if i replace a wid b or b wid c or c wid a ,,equation gonna remain same..so a b c shud be equal..so 60 degrees
6684
@chillfactor said:
|a - b| > (a + b)/2When a > b, a > 3band when b > a, b > 3aPlot it on the graphProbability = 2*(1/2)*1*(1/3)/(1*1) = 1/3In a triangle ABC, sides are a, b, c such that a³ + b³ + c³ = 3abc. Find the measure of angle Aa) 30ºb) 45ºc) 60ºd) 90º
(A+B+C)(A^2+B^2+C^2-AB-BC-CA)=0
(A^2+B^2+C^2-AB-BC-CA)=0 as A=B=C=!0
WHICH IS POSSIBLE FOR A=B=C
C) 60
6685
@chillfactor said:
|a - b| > (a + b)/2When a > b, a > 3band when b > a, b > 3aPlot it on the graphProbability = 2*(1/2)*1*(1/3)/(1*1) = 1/3In a triangle ABC, sides are a, b, c such that a³ + b³ + c³ = 3abc. Find the measure of angle Aa) 30ºb) 45ºc) 60ºd) 90º
When a³ + b³ + c³ = 3abc,
either, a+b+c=0 (not possible in this case)
or, a^2+b^2+c^2-ab-bc-ca=0

==> a=b=c

so, 60?

_/\_ Saar you're most welcome 😃 😁 :D
Aaj kaise darshan de diye? :splat:
6686
@chillfactor said:
|a - b| > (a + b)/2When a > b, a > 3band when b > a, b > 3aPlot it on the graphProbability = 2*(1/2)*1*(1/3)/(1*1) = 1/3In a triangle ABC, sides are a, b, c such that a³ + b³ + c³ = 3abc. Find the measure of angle Aa) 30ºb) 45ºc) 60ºd) 90º
60 😁
6687
@kingsleyx said:
Y=tan^2 X+ cot^2 X + sec^2 X + cosec^2 X , 0OA: 6
Y=tan^2+1+tan^2+cot^2+1+cot^2
Y=1+2*tan^X+1+2*cot^2X
Y=2+2*tan^X+2*cot^2X
X=45
Y=6
6688
@adills said:
log 2 is ?(here base is 5)a)an integerb)a rational numberc)a prime numberd)an irrational number
- log2/log2

integer
6689
Q. While Passing through a jungle, Fahim and nishant meet a lion. The lion jumps to attack
and also fahim and nishat aim at the lion. The probability of the lion catching its target is 0.25 and prob of nishat hitting is 0.33 & farhan is 0.5. If the lion is hit, what is the probability that it is hit by nishat and not fahim.
A.1/4
B.5/6
C.1/2
D.2/3
6690
@Anivesh90 1/4?
6691
@Anivesh90 said:
Q. While Passing through a jungle, Fahim and nishant meet a lion. The lion jumps to attack and also fahim and nishat aim at the lion. The probability of the lion catching its target is 0.25 and prob of nishat hitting is 0.33 & farhan is 0.5. If the lion is hit, what is the probability that it is hit by nishat and not fahim.A.1/4B.5/6C.1/2D.2/3
A. 1/4?

Lion is hit.
Nishat hits the target 1 out of 3 times.
Fahim hits the target 1 out of 2 times.
prob. of both hitting = 0.33*0.5
prob. of N hitting and F missing = 0.33*0.5
prob. of F hitting and N missing = 0.67*0.5

required probability = (0.33*0.5) / (0.33*0.5 + 0.33*0.5 + 0.67*0.5)
= (0.33*0.5)/(1.33*0.5)
= 1/4
6692
@chillfactor said:
|a - b| > (a + b)/2When a > b, a > 3band when b > a, b > 3aPlot it on the graphProbability = 2*(1/2)*1*(1/3)/(1*1) = 1/3In a triangle ABC, sides are a, b, c such that a³ + b³ + c³ = 3abc. Find the measure of angle Aa) 30ºb) 45ºc) 60ºd) 90º
(a+b+c)=0 or (a^2+b^2+c^2-ab-bc-ca)=0
2*a^2+2*b^2+2*c^2-2ab-2bc-2ca=0
(a-b)^2+(b-c)^2+(c-a)^2=0
a=b=c

angle 60
6693

soye huo ko neend se jagane k liye...


A contract is to be completed in 56 days and 104 men are set to work, each working 8 hours a day. After 30 days, 2/5th of the work in finished. How many additional men may be employed so that work may be completed on time, each man now working 9 hours per day?
A. 56 men
B. 65 men
C. 46 men
D. None of the above

6694
@maddy2807 said:
soye huo ko neend se jagane k liye...A contract is to be completed in 56 days and 104 men are set to work, each working 8 hours a day. After 30 days, 2/5th of the work in finished. How many additional men may be employed so that work may be completed on time, each man now working 9 hours per day? A. 56 men B. 65 men C. 46 men D. None of the above
30 * 8 * 104 = 2/5 * total work -- (1)
26 * 9 * (104+x) = 3/5* total work-- (2)

Solving the above 2 equations, we get that x=56
Please correct me if i am wrong

6695
@maddy2807 said:
soye huo ko neend se jagane k liye...A contract is to be completed in 56 days and 104 men are set to work, each working 8 hours a day. After 30 days, 2/5th of the work in finished. How many additional men may be employed so that work may be completed on time, each man now working 9 hours per day? A. 56 men B. 65 men C. 46 men D. None of the above
M1xD1xH1/W1=M2xD2xH2/W2
104x30x8/2=(104+x)x26x9/3
x=56?
6696
@soumitrabengeri said:
30 * 8 * 104 = 2/5 * total work -- (1)26 * 9 * (104+x) = 3/5* total work-- (2)Solving the above 2 equations, we get that x=56Please correct me if i am wrong
i will not correct u. u r already correct.
6697
@maddy2807 said:
soye huo ko neend se jagane k liye...A contract is to be completed in 56 days and 104 men are set to work, each working 8 hours a day. After 30 days, 2/5th of the work in finished. How many additional men may be employed so that work may be completed on time, each man now working 9 hours per day? A. 56 men B. 65 men C. 46 men D. None of the above
a.56
6698
The ratio of number of male and female journalists in a newspaper office is 5 : 4. The newspaper has two sections, political and sports. If 30 percent of the male journalists and 40 percent of the female journalists are covering political news, what percentage of the journalists (approx.) in the newspaper is currently involved in sports reporting?

A. 65 percent
B. 60 percent
C. 70 percent
D. None of the above
6699
@maddy2807 bhai 56 aa raha hai kya?
6700
@maddy2807 said:
The ratio of number of male and female journalists in a newspaper office is 5 : 4. The newspaper has two sections, political and sports. If 30 percent of the male journalists and 40 percent of the female journalists are covering political news, what percentage of the journalists (approx.) in the newspaper is currently involved in sports reporting?A. 65 percent B. 60 percentC. 70 percent D. None of the above
c,70 ??