@adills said:log 2 is ?(here base is 5)a)an integerb)a rational numberc)a prime numberd)an irrational number
d
@adills said:log 2 is ?(here base is 5)a)an integerb)a rational numberc)a prime numberd)an irrational number
d?
@adills said:log 2 is ?(here base is 5)a)an integerb)a rational numberc)a prime numberd)an irrational number
irrational
@gautam22 said:sir c=2 leke hi mera 49 aa raha hai jaise jaise c ki value change karenge ye to aur aa jayega....dekhna ek minute main kahn galat kar raha hoon(a-b)(a+b)=2^100......a-b=2^1.......49, a+b=2^99.......51, isi se 49 values aa rahhi hain
meine toh stupid mistake kar diyi 
@Torque024 said:Let a, b, c be positive integers, with c > 1.How many solutions are there to the equation a^c ˆ' b^c = 2^100?
2^100 multiple of 4
=> 2^100/4 => 2^98
thus, 98/2 => 49 ?
thus, 98/2 => 49 ?
@adills said:log 2 is ?(here base is 5)a)an integerb)a rational numberc)a prime numberd)an irrational number
5^x = 2... has to be 4 
Two numbers are chosen randomly from the interval [0, 1]. What is the probability that they differ by more than their average?
@adills said:@gs4890 Can you please eplain , how did u choose between rational and irrational?
In mathematics, a rational number is any number that can be expressed as the quotient or fraction p/q of two integers, with the denominatorq not equal to zero. Since q may be equal to 1, every integer is a rational number.
In mathematics, an irrational number is any real number that cannot be expressed as a ratio a/b, where a and b are integers, with b non-zero, and is therefore not a rational number.
As by wiki
In mathematics, an irrational number is any real number that cannot be expressed as a ratio a/b, where a and b are integers, with b non-zero, and is therefore not a rational number.
As by wiki
@adills said:log 2 is ?(here base is 5)a)an integerb)a rational numberc)a prime numberd)an irrational number
log2=a/b
blog2=a
2^b=5^a , as one is even other is odd
D) irrational
blog2=a
2^b=5^a , as one is even other is odd
D) irrational
@kingsleyx said:Two numbers are chosen randomly from the interval [0, 1]. What is the probability that they differ by more than their average?
|a-b|>(a+b)/2
a>3b
0,(1,2..9) 9ways
1,(4,5..9) 5ways
2,(7,8,9) 3ways
P(E)=17/10c2 ?
a>3b
0,(1,2..9) 9ways
1,(4,5..9) 5ways
2,(7,8,9) 3ways
P(E)=17/10c2 ?
@Torque024 said:|a-b|>(a+b)/2 a>3b 0,(1,2..9) 9ways 1,(4,5..9) 5ways 2,(7,8,9) 3waysP(E)=17/10c2 ?
how can there be finite no to choose from??? 😲 its a range b/w 0 n 1 of real nos i thnk
@adills said:@Torque024 Thanks
just like the post 😃 no need write thanx etc, creates unnecessary posts
@kingsleyx said:Two numbers are chosen randomly from the interval [0, 1]. What is the probability that they differ by more than their average?
1/3 he kya ??
@kingsleyx ans toh bata do
Y=tan^2 X+ cot^2 X + sec^2 X + cosec^2 X , 0
OA: 6
OA: 6
@kingsleyx said:Y=tan^2 X+ cot^2 X + sec^2 X + cosec^2 X , 0OA: 6
y = 2 + 2 tan^2x + 2 cot^2x
y = 2 + 2( tan^2x + 1/tan^2x)
min value of tan^2x + 1/tan^2x = 2
so y = 2 + 2(2) = 6
@kingsleyx said:Y=tan^2 X+ cot^2 X + sec^2 X + cosec^2 X , 0OA: 6
use tan and cot identities.
And then, x+1/x>=2
@rkshtsurana _/\_ bhai Kahan rhte ho ajkl :P
@vijay_chandola said:use tan and cot identities.And then, x+1/x>=2@rkshtsurana _/\_ bhai Kahan rhte ho ajkl
bhai clg walo ne maari rkhi he ..seminar banao..IIFT ka kch padha nhi he..baaki aap toh 13 14 gante ..aur @Brooklyn toh 16 17 gante
@rkshtsurana said:bhai clg walo ne maari rkhi he ..seminar banao..IIFT ka kch padha nhi he..baaki aap toh 13 14 gante ..aur @Brooklyn toh 16 17 gante
16 17 !!!?? 😲 post my great NMAT result ive given up !! 