@grkkrg said:d. 100?20 + 40 + 10 + 30 = 100
bhai, thoda explain kijiye.. nahi solve kar paya.
@nick_baba said:If a, b, c and d are positive quantities other than 1 such that a^2 = b^2 = c^5 = d^6, then logd (abc) equals.(d is base).??
36/5??
@nick_baba said:If a, b, c and d are positive quantities other than 1 such that a^2 = b^2 = c^5 = d^6, then logd (abc) equals.(d is base).??
36/5
a = d^3
b = d^3
c = d^6/5
logd(abc) = 3 + 3 + 6/5 = 36/5
a = d^3
b = d^3
c = d^6/5
logd(abc) = 3 + 3 + 6/5 = 36/5
@nick_baba said:If a, b, c and d are positive quantities other than 1 such that a^2 = b^2 = c^5 = d^6, then logd (abc) equals.(d is base).??
36/5
@sujamait said:a,b,c ko d ki form mein lao bus..uske baad put kardo..ho gaya.
@maddy2807 said:36/5?
@deedeedudu said:36/5
@Zedai said:36/5
@Ashmukh said:41/5??
haan bhai ans 36/5 hai...
....was getting bored..isliye ye post kara ..koi aur ques lao yaar plz...
....was getting bored..isliye ye post kara ..koi aur ques lao yaar plz...36/5.
@Zedai said:bhai, thoda explain kijiye.. nahi solve kar paya.
4 set venn diagram banana padega
In Madhubani, it was found that 90% of the people took coffee and 80% took tea. Also 70% of people drank whisky and 60% drank vodka. None of the people drank all four items, but they all did drink three of the four beverages. What percentage of people drank liquor? (Both vodka and whisky are liquors.)a. 70%
b. 80%
c. 90%
d. 100%
CWV = a
CTW = b
TVW = c
CTV = d
a + b + d = 90
b + c + d = 80
a + b + c = 70
a + c + d = 60
Solve and get a + b + c + d
a = 20
b = 40
c = 10
d = 30
In Madhubani, it was found that 90% of the people took coffee and 80% took tea. Also 70% of people drank whisky and 60% drank vodka. None of the people drank all four items, but they all did drink three of the four beverages. What percentage of people drank liquor? (Both vodka and whisky are liquors.)a. 70%
b. 80%
c. 90%
d. 100%
CWV = a
CTW = b
TVW = c
CTV = d
a + b + d = 90
b + c + d = 80
a + b + c = 70
a + c + d = 60
Solve and get a + b + c + d
a = 20
b = 40
c = 10
d = 30
@nick_baba said:If a, b, c and d are positive quantities other than 1 such that a^2 = b^2 = c^5 = d^6, then logd (abc) equals.(d is base).??
a^2 = b^2 = c^5 = d^6
=>abc = (d^(6/2))*(d^(6/2)*(d^(6/5)) = d^(36/5)
=>log(abc) = log(d^(36/5)) = (36/5)log(d)
=>log(abc) = 36/5
ATDH.
A leap year X has exactly the same calendar as another leap year Y. What can be the absolute difference between the values of X and Y?
a 12
b 28
c 40
d All of these
a 12
b 28
c 40
d All of these
@Torque024 said:A leap year X has exactly the same calendar as another leap year Y. What can be the absolute difference between the values of X and Y?a 12 b 28 c 40 d All of these
All of these?
@Torque024 said:A leap year X has exactly the same calendar as another leap year Y. What can be the absolute difference between the values of X and Y?a 12 b 28 c 40 d All of these
d All of these (EDITED)
leap year odd days = 2
2 + 1 + 1 + 1 = 5
5*3 = 15 => 1 odd day (can be compensated by a century year)
5*7 = 35 => 0 odd days
5*10 = 50 => 1 odd day (can be compensated by a century year)
leap year odd days = 2
2 + 1 + 1 + 1 = 5
5*3 = 15 => 1 odd day (can be compensated by a century year)
5*7 = 35 => 0 odd days
5*10 = 50 => 1 odd day (can be compensated by a century year)
@anytomdickandhary said:a^2 = b^2 = c^5 = d^6=>abc = (d^(6/2))*(d^(6/2)*(d^(6/5)) = d^(54/5)=>log(abc) = log(d^(54/5)) = (54/5)log(d)=>log(abc) = 54/5ATDH.
sir ek calc mistake ho gayi....6/2+6/2+6/5=36/5....so 36/5 ayega..
@grkkrg said:4 set venn diagram banana padegaIn Madhubani, it was found that 90% of the people took coffee and 80% took tea. Also 70% of people drank whisky and 60% drank vodka. None of the people drank all four items, but they all did drink three of the four beverages. What percentage of people drank liquor? (Both vodka and whisky are liquors.)a. 70% b. 80% c. 90% d. 100%CWV = aCTW = bTVW = cCTV = da + b + d = 90b + c + d = 80a + b + c = 70a + c + d = 60Solve and get a + b + c + da = 20b = 40 c = 10d = 30
oh...ok.
i thought, if everyone of them are drinking 3 of the 4 beverages.. tab toh sab ek na ek drink peeke talli hain!!
toh 100%
@Torque024 said:A leap year X has exactly the same calendar as another leap year Y. What can be the absolute difference between the values of X and Y?a 12 b 28 c 40 d All of these
All of these
@nick_baba said:sir ek calc mistake ho gayi....6/2+6/2+6/5=36/5....so 36/5 ayega..
yes mate..... thats my trade mark (my signature!)
Thanks for pointing, have corrected my post.
ATDH.
@Torque024 said:A leap year X has exactly the same calendar as another leap year Y. What can be the absolute difference between the values of X and Y?a 12 b 28 c 40 d All of these
@grkkrg said:d All of these (EDITED)leap year odd days = 22 + 1 + 1 + 1 = 55*3 = 15 => 1 odd day (can be compensated by a century year)5*7 = 35 => 0 odd days5*10 = 50 => 1 odd day (can be compensated by a century year)
@Torque024 said:A leap year X has exactly the same calendar as another leap year Y. What can be the absolute difference between the values of X and Y?a 12 b 28 c 40 d All of these
d?
Two cards are drawn at a random from a deck of cards. What is the probability that both the cards are of same number or honour?