@vijay_chandola-bro mujhe yeh ques ek teacher ne diya hai and he says ki 210 aane ki ek specific condition hoti hai..this is not the answer..let others try..i don't have the oa
@falcao said:i have a question which covers a basic conceptwhat is the lcm of (15,1.5,1.5555555555......infinite times)hcf(15,1.5,1.55555555555555555.......infinite times)
210
1/18
Sum of first 'n' natural numbers is divisible by 5!. For the smallest possible value of 'n', which of the
following is the largest prime number that divides the sum of the squares of first 'n' natural numbers?
following is the largest prime number that divides the sum of the squares of first 'n' natural numbers?
@sujamait said:Sum of first 'n' natural numbers is divisible by 5!. For the smallest possible value of 'n', which of thefollowing is the largest prime number that divides the sum of the squares of first 'n' natural numbers?
Options??
@falcao said:@vijay_chandola-bro mujhe yeh ques ek teacher ne diya hai and he says ki 210 aane ki ek specific condition hoti hai..this is not the answer..let others try..i don't have the oa
we can use the formula that I have used in the previous post when denominator and numerator both are co-prime.
Here, 15 and 1 are co-prime.
3 and 2 are co-prime
14 and 9 are co-prime.
So, I guess the answer should be true! 
@sujamait said:Sum of first 'n' natural numbers is divisible by 5!. For the smallest possible value of 'n', which of thefollowing is the largest prime number that divides the sum of the squares of first 'n' natural numbers?
31?
@sujamait said:Sum of first 'n' natural numbers is divisible by 5!. For the smallest possible value of 'n', which of thefollowing is the largest prime number that divides the sum of the squares of first 'n' natural numbers?
n=15
15*16*31/6
31?
15*16*31/6
31?
@sujamait said:Sum of first 'n' natural numbers is divisible by 5!. For the smallest possible value of 'n', which of thefollowing is the largest prime number that divides the sum of the squares of first 'n' natural numbers?
smallest n = 15..
sum of squares = 15*16*31/6
so 31..
@sujamait
@sujamait said:Sum of first 'n' natural numbers is divisible by 5!. For the smallest possible value of 'n', which of thefollowing is the largest prime number that divides the sum of the squares of first 'n' natural numbers?
31??
@soumitrabengeri said:Options??
@SarayuSheshadri said:smallest n = 15..sum of squares = 15*16*31/6so 31..
31 is following...
bhai log sab kaha gayab rahte ho...jaise hee Q post karo..sab toot padte hein..but Q koi post nhn karta hai 
sahi hai..
sahi hai..A jewelry box, made of thin sheet of Brass, consists of two parts €“ a cubical box, in which a bangle
with outer circumference of 22 cm just fits in and a hollow cover in form of a right pyramid that
completely fits over the top of the cubical box. If the slant height of a face of the cover is 12.5 cm,
find the volume of the box.
A. 350 cm3 B. 392 cm3 C. 529 cm3 D. 539 cm3
with outer circumference of 22 cm just fits in and a hollow cover in form of a right pyramid that
completely fits over the top of the cubical box. If the slant height of a face of the cover is 12.5 cm,
find the volume of the box.
A. 350 cm3 B. 392 cm3 C. 529 cm3 D. 539 cm3
99) a, b, c and d are real positive numbers such that a + b = 5, c + d =
2 and ad = bc = 1. Then ac + bd + a
c
a) 11.5 b) 12.5 c) 10.5 d) 13 e) none of thes
2 and ad = bc = 1. Then ac + bd + a
c
a) 11.5 b) 12.5 c) 10.5 d) 13 e) none of thes
@sujamait said:31 is following...bhai log sab kaha gayab rahte ho...jaise hee Q post karo..sab toot padte hein..but Q koi post nhn karta hai sahi hai..A jewelry box, made of thin sheet of Brass, consists of two parts €“ a cubical box, in which a banglewith outer circumference of 22 cm just fits in and a hollow cover in form of a right pyramid thatcompletely fits over the top of the cubical box. If the slant height of a face of the cover is 12.5 cm,find the volume of the box.A. 350 cm3 B. 392 cm3 C. 529 cm3 D. 539 cm3
539.
Cube of side 7 = vol of 343
Pyramid of base 7 x 7 and height 12 = vol 1/3 x 7 x 7 x 12 = 196.
Total volume 343 + 196 = 539.
Technically though volume of box alone should be 343 :)
regards
scrabbler
Cube of side 7 = vol of 343
Pyramid of base 7 x 7 and height 12 = vol 1/3 x 7 x 7 x 12 = 196.
Total volume 343 + 196 = 539.
Technically though volume of box alone should be 343 :)
regards
scrabbler
Bhanu and Ria start running simultaneously on a linear track with same speeds and cover first
280 m in €˜t €™ seconds. After covering every 280 m, Bhanu decreases her speed by fraction of
1/2
and
Ria decreases her speed by fraction of
2/3
Bhanu takes 1.5t minutes less than the time taken by
Ria to cover the entire distance. Find the distance, which in metres is an integer multiple of 280?
A. 2800 B. 1680 C. 1400 D. 2240
280 m in €˜t €™ seconds. After covering every 280 m, Bhanu decreases her speed by fraction of
1/2
and
Ria decreases her speed by fraction of
2/3
Bhanu takes 1.5t minutes less than the time taken by
Ria to cover the entire distance. Find the distance, which in metres is an integer multiple of 280?
A. 2800 B. 1680 C. 1400 D. 2240
@sujamait said:31 is following...bhai log sab kaha gayab rahte ho...jaise hee Q post karo..sab toot padte hein..but Q koi post nhn karta hai sahi hai..A jewelry box, made of thin sheet of Brass, consists of two parts €“ a cubical box, in which a banglewith outer circumference of 22 cm just fits in and a hollow cover in form of a right pyramid thatcompletely fits over the top of the cubical box. If the slant height of a face of the cover is 12.5 cm,find the volume of the box.A. 350 cm3 B. 392 cm3 C. 529 cm3 D. 539 cm3
r=22/(2*pi)
s=22/pi=7
h=root(12.5^2-3.5^2)=12
volume=(7)^3+1/2*7*12*7=343+294=637
s=22/pi=7
h=root(12.5^2-3.5^2)=12
volume=(7)^3+1/2*7*12*7=343+294=637
there is a mistake it is ac+bd+a upon c