@scrabbler said:Here you go...attached file should give the answer.regardsscrabbler
@Ashmukh said:@Brooklyn yr kaisa aaya,mera 24 aa raha hai
Earlier he was short of space for 8, now he has space for 8 more. So the difference in the two cases is 16. But this increase (of 16) is 50% of original garage space, so original space must have been 32, and since there were 8 trucks left there must have been 40 trucks.
regards
scrabbler
If JUNK is written as B5C7B7A11 which word is written as B4C3B7B2
?
@amresh_maverick said:A contractor did not have space in his garage for 8 of his trucks. He, therefore, increased the size of his garage by 50% which gave him space for 8 more trucks than he owned altogether. How many trucks did he own?
OA:40
There are five consecutive integers a, b, c, d and e such that a a^2+ b^2+ c^2= d^2+ e^2
. What is/are the possible value(s) of b?
0
11
0 and -11
-1 and 11
There are five consecutive integers a, b, c, d and e such that a a^2+ b^2+ c^2= d^2+ e^2
. What is/are the possible value(s) of b?
0
11
0 and -11
-1 and 11
@scrabbler total area=x,are covered by a single truck=y,n be the no. of trucks
x=n*y
1.5x=(n+8)*y
dividing both eqns
n=16
after 8 trucks=24,where am i wrong??
@amresh_maverick said:OA:40There are five consecutive integers a, b, c, d and e such that a a^2+ b^2+ c^2= d^2+ e^2 . What is/are the possible value(s) of b?0110 and -11-1 and 11
-1 and 11
@amresh_maverick said:OA:40There are five consecutive integers a, b, c, d and e such that a a^2+ b^2+ c^2= d^2+ e^2 . What is/are the possible value(s) of b?0110 and -11-1 and 11
-1 and 11
@amresh_maverick said:OA:40There are five consecutive integers a, b, c, d and e such that a a^2+ b^2+ c^2= d^2+ e^2 . What is/are the possible value(s) of b?0110 and -11-1 and 11
x-2,x-1,x,x+1,x+2
=>a^2+ b^2+ c^2= d^2+ e^2
=>x^2+4-4x+x^2+1-2x+x^2=x^2+1+2x+x^2+4x+4
=>x^2-12x=0
=>x=12
so b=11
or x=0
=>b=-1
=>a^2+ b^2+ c^2= d^2+ e^2
=>x^2+4-4x+x^2+1-2x+x^2=x^2+1+2x+x^2+4x+4
=>x^2-12x=0
=>x=12
so b=11
or x=0
=>b=-1
@amresh_maverick said:OA:40There are five consecutive integers a, b, c, d and e such that a a^2+ b^2+ c^2= d^2+ e^2 . What is/are the possible value(s) of b?0110 and -11-1 and 11
D?
@Ashmukh said:@scrabbler total area=x,are covered by a single truck=y,n be the no. of trucks x=n*y
x = (n-8)y, since initially he has 8 trucks left out of the garage...
@Ashmukh said:1.5x=(n+8)*ydividing both eqnsn=16after 8 trucks=24,where am i wrong??
regards
scrabbler
@catter2011 said:TIME EXAM question.. see soln
Can you please post the solution ?
I don't have access to it.
@pankaj1988 said:bhai bata dijiye kaise...mai crack nhi kar paaya
Decoded :
see
JUNK , position of these =
J =10
U=21
N=14
K=11
B5C7B7A11
B=2
C=3
A=11
J=B*5 =2*5=10
N=B7=2*7=14
ab kar lo
see
JUNK , position of these =
J =10
U=21
N=14
K=11
B5C7B7A11
B=2
C=3
A=11
J=B*5 =2*5=10
N=B7=2*7=14
ab kar lo