hey puys,
is anyone of you a Career launcher student??
plz reply, i need help ASAP..
Thanks.
A= Sum of the digits of the number 7^100,B= Sum of the digits of A, What is the sum of the digits of B?
Answers:a>7, b>16, c>10, d>Cannot be determined.
Answer and Approach pls.
can we reschedule IIFT test? I need to change my test center.
a fisherman caught 75 fishes from pond , tagged them and left into pond, aftr 75 days he caught 75 fishes, and identified 5 fishes as tagged one's,
now the no.f fishes in pond if the fraction of tagged fishes to untaged fishes in pond is equal to second caught ?
E=3+8+15+24+.............+195
what is the value of E?
CAT is just around the corner.
These videos can be helpful to both beginners as well as pros.
I am posting the link to the Youtube Channel. By the name Sleepy Classes.
I have an exam to write in December, so would be infrequent here.
So here is my warmest and sturdiest of wishes to alllll.
Be calm and rule the exam.
at an election there are 5 candidates and 3 members are to be elected and a voter is entitled to vote for any number to be elected . how many ways a voter can vote
What is the
maximum
sum you
cannot
pay using coins of denominations
6 and 7
.
You have been given that -
- there is a country where these denominations exist and only these two denominations exist, i.e. there is no other coin/note available in that country except of value 6 or value 7.
- that these coins/notes are available in plenty, i.e. you don't run out of money at all.
-there is no exchange of currencies allowed between two parties, for example if I have to pay someone value 1, I can't do this by giving him coin of value 7 and taking in return coin of value 6.
Example - Assuming I have to pay someone value 1 or 2 or 3 or 4 or 5, I can't do it. Or similarly if I have to pay someone lets say 11, I can't do this as well. Also, lets say if I have to pay value 94 I can do this by giving 10 coins of 7 and 4 coins of 6.
- Can't be determined
- 1143
- 1310
- 41
- 29
0 voters
What is the
maximum
sum you
cannot
pay using coins of denominations
6 and 7
.
You have been given that -
- there is a country where these denominations exist and only these two denominations exist, i.e. there is no other coin/note available in that country except of value 6 or value 7.
- that these coins/notes are available in plenty, i.e. you don't run out of money at all.
-there is no exchange of currencies allowed between two parties, for example if I have to pay someone value 1, I can't do this by giving him coin of value 7 and taking in return coin of value 6.
Example - Assuming I have to pay someone value 1 or 2 or 3 or 4 or 5, I can't do it. Or similarly if I have to pay someone lets say 11, I can't do this as well. Also, lets say if I have to pay value 94 I can do this by giving 10 coins of 7 and 4 coins of 6..
- 1143
- Can't be determined
- 41
- 29
- 1310
0 voters
What is the maximum sum you cannot pay using coins of denominations 6 and 7.
You have been given that -
- there is a country where these denominations exist and only these two denominations exist, i.e. there is no other coin/note available in that country except of value 6 or value 7.
- that these coins/notes are available in plenty, i.e. you don't run out of money at all.
-there is no exchange of currencies allowed between two parties, for example if I have to pay someone value 1, I can't do this by giving him coin of value 7 and taking in return coin of value 6.
Example - Assuming I have to pay someone value 1 or 2 or 3 or 4 or 5, I can't do it. Or similarly if I have to pay someone lets say 11, I can't do this as well. Also, lets say if I have to pay value 94 I can do this by giving 10 coins of 7 and 4 coins of 6..
- Can't be determined
- 1310
- 1143
- 29
- 41
0 voters
What is the maximum sum you cannot pay using coins of denominations 6 and 7.
You have been given -
- there is a country where these denominations exist and only these two denominations exist, i.e. there is no other coin/note available in that country except of value 6 or value 7.
- that these coins/notes are available in plenty, i.e. you don't run out of money at all.
-there is no exchange of currencies allowed between two parties, for example if I have to pay someone value 1, I can't do this by giving him coin of value 7 and taking in return coin of value 6.
Example - Assuming I have to pay someone value 1 or 2 or 3 or 4 or 5, I can't do it. Or similarly if I have to pay someone lets say 11, I can't do this as well. Also, lets say if I have to pay value 94 I can do this by giving 10 coins of 7 and 4 coins of 6..
- Can't be determined
- 1310
- 1143
- 29
- 41
0 voters
In an isosceles triangle ABC, AD is the median to the unequal side meeting BC at D. DP is the angle bisector of angle ADB and PQ is drawn parallel to BC meeting AC at Q. What is the measure of angle PDQ
In triangle ABC, DE is parallel to BC. If AD=5cm AE=6cm BC=12cm AB=15cm. Find AC and DE
log(base10)x^3-log(base10)x^1/2=5log(basex^2)10 find the value
P, Q, R and S are four statements. Relation between these statements is as follows.
I. If P is true, then Q must be true.
II. If Q is true, then R must be true.
III. If S is true, then either Q is false or R is false.
Which of the following must be true?
a. If P is true, then S is false
b. If S is false, then Q must be true
c. If Q is true, then P must be true
d. If R is true, then Q must be true
64log(base16)9+log(base5)x=log(base10)1000+log(base20)8000+26 x=?
A can beat B by 20 mts while C can beat B by 40 mts in a race of 100 mts. By how much can C beat A?
What is the remainder when 50 power (51 power 52) is divided by 11.
Also please provide the approach to solve such kinds of questions..
Log(base2)9-(2)^x= 10 log (base10)3-x solve for x
@shawshank26 @saketbanka
Here's the solution to it. The solution begins somewhere around 1:30 or 2:00 minutes into the video, prior to it is the question.
The solution emphasizes on the ways one will use in exam. Something which employs common sense more than anything else.
p.s. - pardon my coarse voice in the video.
