@rkshtsurana no prob,just pm me when u get time
@techsurge said:bhai image load nahi ho rahi, office IE sucks , ek baar fir se post kar do
wats rationalized value of
:1/[rt(5) + rt(6) + rt(11) ]
how to solve this?
Two guns are fired from the same place at an interval of 10.5 mins but a person in the shatabdi express approaching the place hears the second shot 10mins after the first. the speed of the shatabdi express in kmph if the speed of sound is 330m/s is?
a)59.6kmph b)45.1kmph c)120.35kmph d)none of these e)cannot be determined
@techsurge Is it option 1? We can assume all the numbers in the AP to be [Root of (3/2)]. Only option 1 satisfies.
Q3
f(2x-1) = 3x +4 , what is the value of f(1) +f(2)+ f(3)......f(10)
a) 130
b) 137.5
c)145
d) 150
@airirm said:@techsurge Is it option 1? We can assume all the numbers in the AP to be [Root of (3/2)]. Only option 1 satisfies.
yes
@airirm said:@techsurge Is it option 1? We can assume all the numbers in the AP to be [Root of (3/2)]. Only option 1 satisfies.
ye kaise aaya ?? :/
@hxparam said:how to solve this?Two guns are fired from the same place at an interval of 10.5 mins but a person in the shatabdi express approaching the place hears the second shot 10mins after the first. the speed of the shatabdi express in kmph if the speed of sound is 330m/s is?a)59.6kmph b)45.1kmph c)120.35kmph d)none of these e)cannot be determined
Distance travelled by bullets in 30 secs=Distance travelled by Shatabdi express in 600 secs
Hence
Speed of Shatabdi Express/Speed of sound=Time taken by bullet/Time taken by Shatabdi
x/330=30/600
x=16.5 m/s
or 16.5*18/5=59.6 kmph
Hence
Speed of Shatabdi Express/Speed of sound=Time taken by bullet/Time taken by Shatabdi
x/330=30/600
x=16.5 m/s
or 16.5*18/5=59.6 kmph
@techsurge said:Q3f(2x-1) = 3x +4 , what is the value of f(1) +f(2)+ f(3)......f(10)a) 130b) 137.5c)145d) 150
137.5
f(x) = 3x+11/2
@techsurge said:Q3f(2x-1) = 3x +4 , what is the value of f(1) +f(2)+ f(3)......f(10)a) 130b) 137.5c)145d) 150
b
@techsurge said:Q3f(2x-1) = 3x +4 , what is the value of f(1) +f(2)+ f(3)......f(10)a) 130b) 137.5c)145d) 150
137.5
@Brooklyn Bro, we need to have sum of squares of 2 numbers to be 3. No natural number pair possible. Next best option is assuming them to be equal. So we get [Root of 3/2].