@rkshtsurana said:@gs4890 q 1 . Dgeneral term = 1/ n^2 + 1/ (n+1)^2
@rkshtsurana said:@gs4890 q 1 . Dgeneral term = 1/ n^2 + 1/ (n+1)^2
term kaise nikali ???
@techsurge said:Q2 sum of squares of 5th and 11th term of an AP is 3. The product of 2nd and 14th term of progression is 14. what will be the product of first and 15th term
(116p- 39) / 90
(296p-39) /90
(116p- 39) / 180
8p(13-38p/90)
turn se pehle post karne ki liye sorry, but ab kar diya hai to solve kar do
@Brooklyn said:term kaise nikali ???
nth term can be wriiten as 2n+1 / n^2 * (n+1)^2 ------> 1/n^2 + 1/(n+1)^2
@techsurge said:Q2 sum of squares of 5th and 11th term of an AP is 3. The product of 2nd and 14th term of progression is 14. what will be the product of first and 15th term(116p- 39) / 90(296p-39) /90(116p- 39) / 1808p(13-38p/90)
what is p?
Q.2
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@techsurge said:Q2 sum of squares of 5th and 11th term of an AP is 3. The product of 2nd and 14th term of progression is 14. what will be the product of first and 15th term(116p- 39) / 90(296p-39) /90(116p- 39) / 1808p(13-38p/90)
p kya he...imainery ?
@wovfactorAPS said:what is p?
edited it :banghead:
it is product of 2nd and 14th term
jaldi mein likh diya tha
@Ashmukh said:@techsurge ans kya hai??
askmuk tumhare wale ques ka ans 135 nhi ho skta i can prove..135 se kam hi hga..vo baad me krnga..dnt want to interrupt dis session
@gs4890 said:Q.2
bhai image load nahi ho rahi, office IE sucks :banghead:, ek baar fir se post kar do