Official Quant thread for CAT 2013

@ScareCrow28 said:
Please share your approach as well..
X33-22 should either be 0 or a multiple of 7
x=5 satisfies
@ScareCrow28 said:
101 digit number 222.........2X3...333 is formed by repeating the digit 2,50 times followed by the digit X and then repeating the digit 3,50 times.The number is a multiple of 7.Find the value of X.?a) 2 b) 3 c) 4 d) 5
it is 5.
22X33 shud be divisible by 7
@ScareCrow28 -bhai 2(1111..50 times)x3(1111..50 times)..yeh assume kar le..ab 11111 is divisible by 7..aise groups banao toh 1111..48 times will be divisible by 7..similarly for the other group i.e(3(11111..50 times)..so 22x33 should be fully divisible by 7..the only option satisfying this is 5
@ScareCrow28 said:
101 digit number 222.........2X3...333 is formed by repeating the digit 2,50 times followed by the digit X and then repeating the digit 3,50 times.The number is a multiple of 7.Find the value of X.?
a) 2
b) 3
c) 4
d) 5
22x33 should be divisble by 7 so X should be 5
@falcao said:
@ScareCrow28 -bhai 2(1111..50 times)x3(1111..50 times)..yeh assume kar le..ab 11111 is divisible by 7..aise groups banao toh 1111..48 times will be divisible by 7..similarly for the other group i.e(3(11111..50 times)..so 22x33 should be fully divisible by 7..the only option satisfying this is 5
No need to group bhai... 11111 nahi sab numbers when repeated 6 times are divisble by 7 😁
222222/7 333333 divisible by 7 😁

111 111 =13*7*11*111

how many 8 digit no.s are there for which the sum of digits is 4?

@audiq7 said:
how many 8 digit no.s are there for which the sum of digits is 4?
a'+b+c+d+e+f+g+h = 3
10C7?

@audiq7 said:
how many 8 digit no.s are there for which the sum of digits is 4?
My take 120
sum of digits = 4
cases 1) 1+1+1+1
first number has to be 1 among the remainign 7 places, 7C3 = 35 numbers
case 2) 1+1+2
when first number is 1.. out of 7 places, you have to slect 2 7C2*2! = 7*6 =42
when first number is 2.. 21
case 3) 2+2 - 7 ways
case 4) 3+1 - 14 wyas
case 5) 4+0 - 1
so 35+42+21+7+14+1 = 120
kuch gadbad lag raha hai
@sujamait plz explain a bit
A grain dealer cheats to the extent of 10% while buying as well as selling by using false weights.His total profit percentage is:
1.20%
2.21%
3.23%
4.25%
@jain4444 said:
A grain dealer cheats to the extent of 10% while buying as well as selling by using false weights.His total profit percentage is:1.20%2.21%3.23%4.25%
21% ?
@audiq7 said:
how many 8 digit no.s are there for which the sum of digits is 4?
Edit: a+b+c+d+e+f+g+h = 4 but a cannot be 0... 1=> a' = a-1
=> a'+b+c+d+e+f+g+h = 3
10C7

@jain4444 said:
A grain dealer cheats to the extent of 10% while buying as well as selling by using false weights.His total profit percentage is:1.20%2.21%3.23%4.25%
21?
@sujamait said:
a'+b+c+d+e+f+g+h = 3
10C7?

@audiq7 said:
@sujamait plz explain a bit
This is a better approach
bhai 8 digits a b ... h
sum = 4
so a+b+c+d+e+f+g+h = 4 as sum of digits = 4
but a cannot be 0 so
sir has written as
a"+b+c+..h = 3
now find out solutions for this = 10C7 = 10C3 = 120
@audiq7 said:
@sujamait plz explain a bit


just made it sure that 1st digit is >0 ..rest is self explnatory i guess.. those variables represent 8 digits.

@jain4444 said:
A grain dealer cheats to the extent of 10% while buying as well as selling by using false weights.His total profit percentage is:1.20%2.21%3.23%4.25%

1.1*1.1 = 1.21
21% ?


@jain4444 said:
A grain dealer cheats to the extent of 10% while buying as well as selling by using false weights.His total profit percentage is:1.20%2.21%3.23%4.25%
21
@chandrakant.k said:
This is a better approach bhai 8 digits a b ... hsum = 4so a+b+c+d+e+f+g+h = 4 as sum of digits = 4but a cannot be 0 sosir has written as a"+b+c+..h = 3now find out solutions for this = 10C7 = 10C3 = 120
bhai explain karna yeh 10c7 kaise aaya....no. of +ve integral sol hai kya..ya non-negative??
@jain4444 21 ?
@mailtoankit said:
bhai explain karna yeh 10c7 kaise aaya....no. of +ve integral sol hai kya..ya non-negative??
Non negative hai bhai.. cos it can take 0 as well
@jain4444 said:
A grain dealer cheats to the extent of 10% while buying as well as selling by using false weights.His total profit percentage is:
1.20%
2.21%
3.23%
4.25%
21%