@ScareCrow28 said:Ans is 33
bhai kaise... please explain...
@deedeedudu said:How come solution plzPS:@Brooklyn bhai sharingan develop kar liya
@chandrakant.k said:kaisa bhai??/ 22 hi hona chahiye na??
No solution.. agar aap jaise maharathio ka 22 ara hai to ans 22 he hoga! waise ek bar approach btado
@ScareCrow28 said:No solution.. agar aap jaise maharathio ka 22 ara hai to ans 22 he hoga! waise ek bar approach btado
Summation till 22
=22*23/2=253
253-198=55
Summation till 10 =10*11/2=55
Hence it starts eating from page 11
=22*23/2=253
253-198=55
Summation till 10 =10*11/2=55
Hence it starts eating from page 11
@ScareCrow28 said:No solution.. agar aap jaise maharathio ka 22 ara hai to ans 22 he hoga! waise ek bar approach btado
summation of 22 = 253
and the count of the insect = 198
so 55 kam hona hai...
summation of 10 = 55
so 11 se 22 tak karegi 😁
@deedeedudu said:Summation till 22=22*23/2=253253-198=55Summation till 10 =10*11/2=55Hence it starts eating from page 11
Any method without options?
@ScareCrow28 said:Any method without options?
Yaar better try with options only. Otherwise hit nd try with nos greater than 20. I do it this way. There r some other way but i find it faster :)
@ScareCrow28 said:Any method without options?
trial and erorr if no options :D
just check the nearest summation which gives you more than or equal to that number. if it is more keep subtracting from the that tiil you get your sum 😁
A positive three digit number X is such,when divided in two unequal three digit number,the larger part is the aritmetic mean of X and the smaller part.How many values can X take?
a)300 b)234 c)198 d)None
a)300 b)234 c)198 d)None
@ScareCrow28 said:A positive three digit number X is such,when divided in two unequal three digit number,the larger part is the aritmetic mean of X and the smaller part.How many values can X take?a)300 b)234 c)198 d)None
Let, X = pqr = abc + xyz
Now, abc = (pqr + xyz)/2
Solving, we get, pqr = 3*xyz
So, 100 So, 234 values
Now, abc = (pqr + xyz)/2
Solving, we get, pqr = 3*xyz
So, 100 So, 234 values
Please correct me if i am wrong
@ScareCrow28 said:A positive three digit number X is such,when divided in two unequal three digit number,the larger part is the aritmetic mean of X and the smaller part.How many values can X take?a)300 b)234 c)198 d)None
234 values it is
101 digit number 222.........2X3...333 is formed by repeating the digit 2,50 times followed by the digit X and then repeating the digit 3,50 times.The number is a multiple of 7.Find the value of X.?
a) 2
a) 2
b) 3
c) 4
d) 5
@ScareCrow28 said:A positive three digit number X is such,when divided in two unequal three digit number,the larger part is the aritmetic mean of X and the smaller part.How many values can X take?a)300 b)234 c)198 d)None
samjha nhn
@ScareCrow28 said:101 digit number 222.........2X3...333 is formed by repeating the digit 2,50 times followed by the digit X and then repeating the digit 3,50 times.The number is a multiple of 7.Find the value of X.?a) 2 b) 3 c) 4 d) 5
5
@ScareCrow28 said:101 digit number 222.........2X3...333 is formed by repeating the digit 2,50 times followed by the digit X and then repeating the digit 3,50 times.The number is a multiple of 7.Find the value of X.?a) 2 b) 3 c) 4 d) 5
4 it is
@ScareCrow28 said:101 digit number 222.........2X3...333 is formed by repeating the digit 2,50 times followed by the digit X and then repeating the digit 3,50 times.The number is a multiple of 7.Find the value of X.?a) 2 b) 3 c) 4 d) 5
5 ho sakta hai
Please share your approach as well..
