A long thin strip of paper is 256 units in length, 1 unit in width, and is divided into 256 unit squares. The strip of paper is kept in such a manner that the longer side is in the left-right orientation. The squares are numbered 1 through 256 starting from the left most square. The paper is folded into half repeatedly. For the first fold, the right end of the paper is folded over to coincide with and lie on top of the left end.
Then the paper is cut at the fold. There are now two strips of paper 1 — 128 in dimensions. Next, the right end of these two strips together is folded over to coincide with and lie on top of the left end, resulting in 4 strips of paper 1 — 64 in dimensions. The strip is again cut at the folds. This process is repeated till it becomes a stack of 256 unit squares. What is the number written on the square that is at the 128th position from the bottom?
a. 3
b. 4
c. 128
d. 129
@justanshul said:A long thin strip of paper is 256 units in length, 1 unit in width, and is divided into 256 unit squares. The strip of paper is kept in such a manner that the longer side is in the left-right orientation. The squares are numbered 1 through 256 starting from the left most square. The paper is folded into half repeatedly. For the first fold, the right end of the paper is folded over to coincide with and lie on top of the left end.Then the paper is cut at the fold. There are now two strips of paper 1 — 128 in dimensions. Next, the right end of these two strips together is folded over to coincide with and lie on top of the left end, resulting in 4 strips of paper 1 — 64 in dimensions. The strip is again cut at the folds. This process is repeated till it becomes a stack of 256 unit squares. What is the number written on the square that is at the 128th position from the bottom?a. 3b. 4c. 128d. 129
129?
why is the second para given?i dont think it has any relevance here..
why is the second para given?i dont think it has any relevance here..
@kumargaurav_bn said:An insect is crawling to climb a 20 metre long pipe of diameter 3.5 metres. If the insect take 4circular rounds to reach the top of the building, then what will be total distance (in nearermetres) traveled by insect to reach the top?(1) 47 m (2) 48 m (3) 49 m (4) 50 m
48 right?
sqrt(20^2 + (4*22/7*3.5)^2)..
sqrt(20^2 + (4*22/7*3.5)^2)..
IIFT Quantitative event ( Series 2 )
Date & Time - Tonight from 8:30pm to 2:30am
Place - Official Quant thread for CAT 2013
Objective - Discussion of IIFT kinda Q's seen in past papers
Request you all to show up.
p.s - Discussed some quality questions last night ; you can scroll back pages & have a look :)
ATB :)
Date & Time - Tonight from 8:30pm to 2:30am
Place - Official Quant thread for CAT 2013
Objective - Discussion of IIFT kinda Q's seen in past papers
Request you all to show up.
p.s - Discussed some quality questions last night ; you can scroll back pages & have a look :)
ATB :)
@Brooklyn said:@gs4890: on which pages?? i wasnt invited??
It should be around page 160-174 in this thread. You sleep early & wake up early :P
Most invited for series 2 :)
Most invited for series 2 :)
Mandeep and Jagdeep had gone to visit Ranpur, which is a seaside town and also known for the presence of the historical ruins of an ancient kingdom. They stayed in a hotel which is exactly 250 meters away from the railway station. At the hotel, Mandeep and Jagdeep learnt from a tourist information booklet that the distance between the sea-beach and the gate of the historical ruins is exactly 1 km. Next morning they visited the sea-beach to witness sunrise and afterwards decided to have a race from the beach to the gate of the ruins. Jagdeep defeated Mandeep in the race by 60 meters or 12 seconds. The following morning they had another round of race from the railway station to the hotel. How long did Jagdeep take to cover the distance on the second day?
A. 53 seconds
B. 47 seconds
C. 51 seconds
D. 45 seconds
B. 47 seconds
C. 51 seconds
D. 45 seconds
@maddy2807 said:Mandeep and Jagdeep had gone to visit Ranpur, which is a seaside town and also known for the presence of the historical ruins of an ancient kingdom. They stayed in a hotel which is exactly 250 meters away from the railway station. At the hotel, Mandeep and Jagdeep learnt from a tourist information booklet that the distance between the sea-beach and the gate of the historical ruins is exactly 1 km. Next morning they visited the sea-beach to witness sunrise and afterwards decided to have a race from the beach to the gate of the ruins. Jagdeep defeated Mandeep in the race by 60 meters or 12 seconds. The following morning they had another round of race from the railway station to the hotel. How long did Jagdeep take to cover the distance on the second day?A. 53 seconds B. 47 secondsC. 51 seconds D. 45 seconds
47 sec
A two digit number with non zero digits, has its units digit divisible by its tens digit. The number is divisible by the average of its digits. How many possible values can the ratio of units digit and tens digit assume?
@maddy2807 said:Mandeep and Jagdeep had gone to visit Ranpur, which is a seaside town and also known for the presence of the historical ruins of an ancient kingdom. They stayed in a hotel which is exactly 250 meters away from the railway station. At the hotel, Mandeep and Jagdeep learnt from a tourist information booklet that the distance between the sea-beach and the gate of the historical ruins is exactly 1 km. Next morning they visited the sea-beach to witness sunrise and afterwards decided to have a race from the beach to the gate of the ruins. Jagdeep defeated Mandeep in the race by 60 meters or 12 seconds. The following morning they had another round of race from the railway station to the hotel. How long did Jagdeep take to cover the distance on the second day?A. 53 seconds B. 47 secondsC. 51 seconds D. 45 seconds
47 seconds..
@Brooklyn said:: how yar ?? i dont get these defeated walla concept, explin it plz
_______J_______M
Dist____1000_____940
Time___t-12______t__
Speed of J be Sj and M be Sm
From 1st condition..Sj=100/94 * Sm (Time is same)
From 2nd condition... Sj(t-12) = Sm*t (Distance is same)
=> t=200 sec
Hence For covering 25o mtrs of dist
time= 250/Sj = 250/ 1000/(200-12) = 47 sec
A 4 digit perfect square ABCD, with non zero digits, is less than 3600. AB as well as CD are perfect squares. How many such no.s are possible?
1
2
3
0
4
@Messy_19 said:A two digit number with non zero digits, has its units digit divisible by its tens digit. The number is divisible by the average of its digits. How many possible values can the ratio of units digit and tens digit assume?
15?
@Messy_19 said:A 4 digit perfect square ABCD, with non zero digits, is less than 3600. AB as well as CD are perfect squares. How many such no.s are possible?12304
1
1681= 41^2
Options:
3
2
5
6
4
@maddy2807 said:15?
@Messy_19 said:A two digit number with non zero digits, has its units digit divisible by its tens digit. The number is divisible by the average of its digits. How many possible values can the ratio of units digit and tens digit assume?
@Messy_19 said:A 4 digit perfect square ABCD, with non zero digits, is less than 3600. AB as well as CD are perfect squares. How many such no.s are possible?12304
3?
..1600, 1681 and 2500 ...I don't know whether to include 00 at last or not