I did some mistake in previous solution Here it goes:Total no's = 9 * 10^6Cases for sum of digits to be odd:1. when 1 digit is oddif it is 1st place then 5 * 6^6 and for seven places 7C1 * 5 * 6^62. when 3 digits are oddthen 7C3 * 5^3 * 6^4and so onWe have to subtract all these from total which gives me9*10^6 - (7C(7-n+1) * 5^(7-n+1) * 6^(n-1)) where n will be 7, 5, 3, 1 respectively
I think position of 0 will be tricky as it cant be in 1st place but will be count as a even digit in any other place.
Q. ABCD is a quadrilateral. Now AB is extended to P such that AB = BP, BC is extended to Q such that BC = CQ, CD to R such that CD = DR and DA to S such that DA = AS. Find the area of quadrilateral PQRS if area of ABCD is 100.a) 400b) 500c) 600d) 700
QUESTION..4 maximum number of points of intersection of 6 circles? please explain the method.. QUESTION..5 MAXIMUM NUMBER WHEN POINT OF INTERSECTION OF 6 STRAIGHT LINES....
If remainder is 'r' when x is divided by y, then remainder will be 'nr' when nx is divided by nyHere 2012^2012 when divided by 2013 remainder will be 1=> 2012^2013 when divided by 2012*2013 remainder will be 2012Same way for the other partHence remainder will be 2013 + 2012 = 4025
It is already canceled in previous step naa i.e. giving remainder 1
Q. ABCD is a quadrilateral. Now AB is extended to P such that AB = BP, BC is extended to Q such that BC = CQ, CD to R such that CD = DR and DA to S such that DA = AS. Find the area of quadrilateral PQRS if area of ABCD is 100.a) 400b) 500c) 600d) 700 P.S. Bhai ab bi quant? MBA ka jake pado
It is already canceled in previous step naa i.e. giving remainder 1(2012^2013)/2012*2013 => 2012^2012/2013 => rem 1 same is with other case.Correct me if I am wrong
2 when divided by 6 remainder will be 2
2*6 when divided by 6*6 OR 12 when divided by 36 remainder will be 12 not 2
As per your method 12/36 = 2/6, so remainder will be 2 (but its incorrect)
While finding out remainders when you cancel something then you have to multiply it back to get the correct remainder
Lets take one more example:- What will be the remainder when 49 is divided by 42
Clearly answer is 7
But as you mentioned 49/42 = 7/6, so remainder 1 which is incorrect
Thats why you need to multiply back by the factor which you cancelled, hence answer will be 1*7 = 7
Solve this question:-
What will be the remainder when 2^96 is divided by 96
