@scrabbler right bro...
@vijay_chandola said:Q.Two of the sides of a scalene triangle are 14 and 16. How many different integral values third side can take?a) 20b) 23c) 25d) 27
25 i.e option c)
Q2. In quadrilateral ABCD, area of triangle ABC and ACD are 100 and 200. Now mid-points P and Q of sides AB and CD are respectively joined to C and A. Find the area of triangles PBC and AQD.
a) 40 and 80
b) 50 and 100
c) 75 and 150
d) 100 and 200
a) 40 and 80
b) 50 and 100
c) 75 and 150
d) 100 and 200
@vijay_chandola said:Q2.In quadrilateral ABCD, area of triangle ABC and ACD are 100 and 200. Now mid-points P and Q of sides AB and CD are respectively joined to C and A. Find the area of triangles PBC and AQD.a) 40 and 80b) 50 and 100c) 75 and 150d) 100 and 200
50 and 100 ?
@vijay_chandola said:Q2. In quadrilateral ABCD, area of triangle ABC and ACD are 100 and 200. Now mid-points P and Q of sides AB and CD are respectively joined to C and A. Find the area of triangles PBC and AQD.a) 40 and 80b) 50 and 100c) 75 and 150d) 100 and 200
b
@fireatwill said:QUESTION 3 the total number of seven digit numbers, the sum of whose digits is even?
9*10^6 - (nC(7-n+1) * 5^(7-n+1) * 6^(n-1)) where n decreases 7 to 1.
weird solution it is 
@fireatwill said:QUESTION 3 the total number of seven digit numbers, the sum of whose digits is even?
4500000?
regards
scrabbler
regards
scrabbler
@fireatwill said:QUESTION 3 the total number of seven digit numbers, the sum of whose digits is even?
9*10^6/2
=45*10^5
=4500000
half of the numbers will have sum even and the other half will have sum odd.......
=45*10^5
=4500000
half of the numbers will have sum even and the other half will have sum odd.......
@vijay_chandola said:Q.Two of the sides of a scalene triangle are 14 and 16. How many different integral values third side can take?a) 20b) 23c) 25d) 27
27-2=25
@vijay_chandola said:Q2. In quadrilateral ABCD, area of triangle ABC and ACD are 100 and 200. Now mid-points P and Q of sides AB and CD are respectively joined to C and A. Find the area of triangles PBC and AQD.a) 40 and 80b) 50 and 100c) 75 and 150d) 100 and 200
b??
@erm said:What is the remainder if the sum 2012^2013+2013^2012 is divided by 2012.2013?
Edited
1 + 1 = 2 ?
@dushyantagarwal said:9*10^6 - (nC(7-n+1) * 5^(7-n+1) * 6^(n-1)) where n decreases 7 to 1.weird solution it is
please can u elaborate the solution. kuch samajh me nahi a raha.
@vijay_chandola said:Q2. In quadrilateral ABCD, area of triangle ABC and ACD are 100 and 200. Now mid-points P and Q of sides AB and CD are respectively joined to C and A. Find the area of triangles PBC and AQD.a) 40 and 80b) 50 and 100c) 75 and 150d) 100 and 200
option b) ?
Q. ABCD is a quadrilateral. Now AB is extended to P such that AB = BP, BC is extended to Q such that BC = CQ, CD to R such that CD = DR and DA to S such that DA = AS. Find the area of quadrilateral PQRS if area of ABCD is 100.
a) 400
b) 500
c) 600
d) 700
a) 400
b) 500
c) 600
d) 700
@vikky312 said:50 and 100 ?
P.S. Bhai ab bi quant? :neutral:
MBA ka jake pado :splat:
@vijay_chandola - ha ha, yaar office mei hu, bore ho raha hai. Aur ye colleges results bhi nahi de rahe :(
@PURITAN said:b??
@Dexian said:b
@vikky312 said:50 and 100 ?
Habit of not posting the solution . I wonder when will this change :|
@vijay_chandola said:Q. ABCD is a quadrilateral. Now AB is extended to P such that AB = BP, BC is extended to Q such that BC = CQ, CD to R such that CD = DR and DA to S such that DA = AS. Find the area of quadrilateral PQRS if area of ABCD is 100.a) 400b) 500c) 600d) 700 P.S. Bhai ab bi quant? MBA ka jake pado
b)500
assuming ABCD as a square, what is the answer?
@vijay_chandola said:Q. ABCD is a quadrilateral. Now AB is extended to P such that AB = BP, BC is extended to Q such that BC = CQ, CD to R such that CD = DR and DA to S such that DA = AS. Find the area of quadrilateral PQRS if area of ABCD is 100.a) 400b) 500c) 600d) 700 P.S. Bhai ab bi quant? MBA ka jake pado
B>500
@vijay_chandola said:Q. ABCD is a quadrilateral. Now AB is extended to P such that AB = BP, BC is extended to Q such that BC = CQ, CD to R such that CD = DR and DA to S such that DA = AS.
500?/
@PURITAN said:please can u elaborate the solution. kuch samajh me nahi a raha.
I did some mistake in previous solution 
Here it goes:
Total no's = 9 * 10^6
Cases for sum of digits to be odd:
1. when 1 digit is odd
if it is 1st place then 5 * 6^6 and for seven places 7C1 * 5 * 6^6
2. when 3 digits are odd
then 7C3 * 5^3 * 6^4
and so on
1. when 1 digit is odd
if it is 1st place then 5 * 6^6 and for seven places 7C1 * 5 * 6^6
2. when 3 digits are odd
then 7C3 * 5^3 * 6^4
and so on
We have to subtract all these from total which gives me
9*10^6 - (7C(7-n+1) * 5^(7-n+1) * 6^(n-1)) where n will be 7, 5, 3, 1 respectively