ABC is a right triangle with ∠ABC=90∘ with AB=30√3 and BC=30. D is a point on segment BCsuch that AD is the median. E is a point on segment ACsuch that BE is perpendicular to AC. AD and BEintersect at F. If EF=a√b/c, where a and c are positive, coprime integers and b is not divisible by the square of any prime, what is the value of a+b+c?
can anyone explain to me how to solve this problem?
What is the remainder when 25899 is divided by 99?
| OPTIONS | ||
| 1) | 4 | |
| 2) | 25 | |
| 3) | 26 | |
| 4) | 0 | |
| 5) | 1 | |
its 25^899/99
@avi11 said:can anyone explain to me how to solve this problem?What is the remainder when 25899 is divided by 99?OPTIONS 1) 4 2) 25 3) 26 4) 0 5) 1
25^889 / 99
E = 60 (Euler number)
E = 60 (Euler number)
hence , it's equivalent to 25^49 % 99
Using chinese reminder theorem,
it comes out to be
9p - 2 = 11q + 4
i.e; 70..! 😐
Please correct me..!
@blowcat13 said:in a quadrilateral ABCD, BC=10, CD=14, AD=12 and /_CBD = /_BAD =60. IF AB=a+root b. where a and b are a positive integers then a+b = Options 1) 193 2) 201 3) 204 4) 207 5) none of the above
none of these ?
@avi11 said:can anyone explain to me how to solve this problem?What is the remainder when 25899 is divided by 99?OPTIONS 1) 4 2) 25 3) 26 4) 0 5) 1
4?
@Tusharrr said:How many ordered triples (x,y,z) of integer solutions are there to the system of equationsx2+y2+z2=194x2z2+y2z2=194=4225? Here x2 means x sq and y2 means y sq and z2=z sq
second equation clearly likho bhai.
@sbharadwaj said:25^889 / 99 E = 60 (Euler number)hence , it's equivalent to 25^49 % 99Using chinese reminder theorem, it comes out to be 9p - 2 = 11q + 4i.e; 70..! Please correct me..!
bhai 49 nhi 
59 :P
59 :P
@avi11 said:its 25^899/99
70 ?
25^899 mod 99
99 = 3^2*11
E(3) = 2
25^2k mod 3 = 1
25 mod 3 = 1
E(11) = 10
25^10k mod 11 = 1
25^9 mod 11 = 3^9 mod 11 = 5^3 mod 9 = 4
so 3a + 1 = 11b + 4 = 70
distance PQ should have been given..
@Tusharrr
ABC is a right triangle with ∠ABC=90∘ with AB=30√3 and BC=30. D is a point on segment BCsuch that AD is the median. E is a point on segment ACsuch that BE is perpendicular to AC. AD and BEintersect at F. If EF=a√b/c, where a and c are positive, coprime integers and b is not divisible by the square of any prime, what is the value of a+b+c?
hey i just now solved it 55
ABC is a right triangle with ∠ABC=90∘ with AB=30√3 and BC=30. D is a point on segment BCsuch that AD is the median. E is a point on segment ACsuch that BE is perpendicular to AC. AD and BEintersect at F. If EF=a√b/c, where a and c are positive, coprime integers and b is not divisible by the square of any prime, what is the value of a+b+c?
hey i just now solved it 55
Number of factors divisible by 12 = 4 x 4 x 3 = 48
koi batao yaar ye 48 kaise aya...help..!
koi batao yaar ye 48 kaise aya...help..!