Official Quant thread for CAT 2013

@techgeek2050 : cn u plzz explain the method u used?????
@techgeek2050 :can u plzz eplain the method u used?
Dear This quoestion can be solved by (summation(1/2^a)where a=1 to infinity) + (summation(1/3^b)where b=1 to infinity) + (summation(1/2^a*1/3^b)where a=1 to infinity & b=1 to infinity)
on solving above equation we will get approx 2 as an answer

@techgeek2050 said:
y=1/3 +3/18+15/162+........... find the value of y^2+2y
Can We not approx the answer from options ????
@amandeep2020 said:
Q. In the center of a square room with area 100 sq m, there is a square of turkey carpet, & the rest of the floor is covered with oil cloth. The carpet & the oil cloth costs respectively Rs 15 and Rs 6.50 per sq meter and the total cost of Carpet & oil cloth is Rs 1338.50. Find the width of oil cloth border. Ans is - 1/2 metre. Please guys explain this.
Just assume sides of inner square is a
so area of inner square will be a^2

area of rest will be (100-a^2)

now 15a^2+(100-a^2)6.5=1338.5
solving this
a^2=81
a=9
now side of the room is 10
so width of outer portion will be (10-9)/2
or 1/2
@AsihekAdhvaryu said:
Just assume sides of inner square is a so area of inner square will be a^2area of rest will be (100-a^2)now 15a^2+(100-a^2)6.5=1338.5solving this a^2=81a=9now side of the room is 10 so width of outer portion will be (10-9)/2or 1/2
My approach is similar to yours but why will it be divided by 2 ?

Width would be just the difference between the main square's and inner square's difference, right ?
@Preeti_L said:
My approach is similar to yours but why will it be divided by 2 ?Width would be just the difference between the main square's and inner square's difference, right ?
just see the attachment if total width of the oil cloth is 1 then for each side it will be 1/2
@AsihekAdhvaryu said:
just see the attachment if total width of the oil cloth is 1 then for each side it will be 1/2
I was taking it in the overall way. Got ur point now. Thanks !
@jaspunit said:
plz explain someone, total distance = (2n-1)D = 500, how to find distance travelled by X,Y?
If you had refered the persons P and Q,then their distance covered would be in the same ratio as that of their speed

So, Total distance covered = 500,in that Q covers 500*(3/4) = 375km
@jaspunit a.m>=g.m
add and subtract 4 on l.h.s side
(1+A)+1+B+1+C+1+D=5 so ans is 625/256
@mani0303 said:

I won't run on Sunday even if it's 100m event in Olympic games

But today is Sunday...
Sorry for spam
@prats92 said:
@jaspunit a.m>=g.madd and subtract 4 on l.h.s side (1+A)+1+B+1+C+1+D=5 so ans is 625/256
(1+a)(1+b)(1+c)(1+d)
but how can you say (1+a)(1+b)(1+c)(1+d)=625/256
@j.gayu said:
a certain number "C" when divided by N1 it leaves remainder of 13 and when it is divided by n2 it leaves the remainder 1 where N1 and N2 are the positive integers.then the value N1+N2 is i f N1/N2=5/4:
@j.gayu said:@techgeek2050 :can u plzz eplain the method u used?

We have got three equations: C = N1*a + 13 and C = N2*b + 1

N2 = (4/5)*N1

By using all these,we can say N1*(4b - 5a) = 60

As to get the positive integers,N1 has to take either of 15,20,30,60 and the corresponding values of (4b - 5a) are 4,3,2,1

So,you would get number of solutions as many as the values that are satisfying 4b - 5a

@AsihekAdhvaryu - Dude - It's figurative:P
@jaspunit if we take a=b=c=d=1/4 ans is (5/4)^4 which is 625/256..
@jaspunit said:
if a+b+c+d=1find (1+a)(1+b)(1+c)(1+d) = ?
there must be some limitation in the question. Can a,b,c,d, be negative also?
@jaspunit said:
@prats92 i am saying this is hit and trial method, which is wrong, correct answer is 123
But correct answer can not be greater than 625/256 or 2.4xxxxxxx

u should define a,b,c,d ..if they can be only positive or even negative.

Hi All,
I am facing a big time confusion here, Please help.

Q. B is of rs 1000/8 and C is of rs 1000/12.
How much percentage is C's goods cheaper / dearer than B's. ?

Ans.

( 12 - 8 )/ 8 * 100

OR

(12 - 8 )/12 * 100

Please explain with a small reason !! I really need to clarify this...
@ananyboss said:
Hi All,I am facing a big time confusion here, Please help.Q. B is of rs 1000/8 and C is of rs 1000/12.How much percentage is C's goods cheaper / dearer than B's. ?Ans. ( 12 - 8 )/ 8 * 100 OR (12 - 8 )/12 * 100Please explain with a small reason !! I really need to clarify this...
Here you are required to see by how much is C cheaper than B's price.. So C's price is the base.

As such, mathematically it would be --> [ (1000/12 - 1000/8) / 1000/12 ] * 100

That would come to - [ (8-12)/8 ] * 100 [A negative quantity - Quite obvious though].. Or C is cheaper by (12-8)/8 * 100.
@Preeti_L said:
Here you are required to see by how much is C cheaper than B's price.. So C's price is the base.As such, mathematically it would be --> [ (1000/12 - 1000/8) / 1000/12 ] * 100That would come to - [ (8-12)/8 ] * 100 [A negative quantity - Quite obvious though].. Or C is cheaper by (12-8)/8 * 100.
Thanks but ther is still a confusion !

Now we know C is cheaper !
What if the question is including both ---

Q1. How much %age C is cheaper than B and
Q2. How much %age B is dearer than C. ??