@Asfakul said:A trader cheats by 10% while selling and cheats by 20% while purchasing .He also offers a discount of 25% at cost price.find his profit /loss percent?Please explain approach ----- in Detail .
What is the percentage change when 20/40 becomes 22/50 ???
@abhishek.2011 said:Find the least number of all equal weight pieces which can be cut from three cakes of weights; 484g, 308g and 253g.A. 90B. 95C. 100D. 105
@abhishek.2011 said:Find the least number of all equal weight pieces which can be cut from three cakes of weights; 484g, 308g and 253g.A. 90B. 95C. 100D. 105
@Logrhythm said:he buys 120 instead of 100 --> 20% profithe sells 108 instead of 120 and gives 25 disc on 120...so he sells 108 at 90here he incurs a loss of 1800/108 = 16.66so overall profit/loss = 20-16.66-(20*16.66/100) = 0.008% profit seems like i made a functional mistake somewhere....what is the OA??
@abhishek.2011 said:Find the least number of all equal weight pieces which can be cut from three cakes of weights; 484g, 308g and 253g.A. 90B. 95C. 100D. 105
@mohnish_khiani said:What is the percentage change when 20/40 becomes 22/50 ???
@next_big_thing said:This is a question from CAT 2010 paper. Can anyone plz solve it coz I am at a loss ??? -->A triangular garden is to be enclosed inside 3 straight fences. Raju started running at an uniform speed on the three sides of the proposed boundary of the garden & discovered that he was taking 48min, 102min, 90min to traverse the garden's three sides. However, in the latest colony meet, it was decided that the coverage area of the park should be reduced to accomodate a parking lot. Since the fence on the shortest boundary was already constructed, the length of the boundary covered by Raju in 90min was reduced by 60% & the longest was modified accordingly so that the park still remained triangular in shape.1) How much time will Raju take to run along the boundary of the garden thus formed? 120min, 148min, 128min, 160min, 144min2) If Raju's speed was 15metres/min, what is the approx area of the parking lot (in km^2)? 0.39, 0.28, 0.29, 0.45, 0.52Plz post the solution as well or else it wont be of any help.
@abhishek.2011 said:Find the least number of all equal weight pieces which can be cut from three cakes of weights; 484g, 308g and 253g.A. 90B. 95C. 100D. 105
@next_big_thing said:This is a question from CAT 2010 paper. Can anyone plz solve it coz I am at a loss ??? -->A triangular garden is to be enclosed inside 3 straight fences. Raju started running at an uniform speed on the three sides of the proposed boundary of the garden & discovered that he was taking 48min, 102min, 90min to traverse the garden's three sides. However, in the latest colony meet, it was decided that the coverage area of the park should be reduced to accomodate a parking lot. Since the fence on the shortest boundary was already constructed, the length of the boundary covered by Raju in 90min was reduced by 60% & the longest was modified accordingly so that the park still remained triangular in shape.1) How much time will Raju take to run along the boundary of the garden thus formed? 120min, 148min, 128min, 160min, 144min2) If Raju's speed was 15metres/min, what is the approx area of the parking lot (in km^2)? 0.39, 0.28, 0.29, 0.45, 0.52Plz post the solution as well or else it wont be of any help.
@Logrhythm said:he buys 120 instead of 100 --> 20% profithe sells 108 instead of 120 and gives 25 disc on 120...so he sells 108 at 90here he incurs a loss of 1800/108 = 16.66so overall profit/loss = 20-16.66-(20*16.66/100) = 0.008% profit seems like i made a functional mistake somewhere....what is the OA??
@Logrhythm said:@scrabbler ye wala dekhna...
@scrabbler said:A trader cheats by 10% while selling and cheats by 20% while purchasing .He also offers a discount of 25% at cost price.find his profit /loss percent?I interpreted the bold part above differently. Price instead of quantity. If quantity then your answer works.He has to cheat by 20% on hiscost price, I took (as we know nothing about the other person's CP) so he buys 100 ka worth stuff for 80. Then he raises the price from 100 to 110 and then gives a discount of 25% coming to 82.5. So what he bought for 80 he sold for 82.5 and hence profit is 3.125% .Answer however would be different for different interpretations. I find these questions mildly awkward and ambiguous generally, can never be sure if one's interpretation is what the question-setter intended!regardsscrabbler
I was getting diff answers for diff interpretations. Like If the quantity changes then answer is diff..OR if we apply (1+a%)(1+b%) then again ans changes...@ScareCrow28 said:Q. What is the ratio of number of divisors of N²º¹³ which lie in the range (1, 2013) to which lie in the range (N²º¹², N²º¹³) ?A. 1 : 1B. 1 : NC. 1 : N²º¹²D. 1 : N²º¹³Source: Bodhi_vriksha FB PageNo OA
CAT 2008 Number System question if anyone is interested :
@next_big_thing said:This is a question from CAT 2010 paper. Can anyone plz solve it coz I am at a loss ??? -->A triangular garden is to be enclosed inside 3 straight fences. Raju started running at an uniform speed on the three sides of the proposed boundary of the garden & discovered that he was taking 48min, 102min, 90min to traverse the garden's three sides. However, in the latest colony meet, it was decided that the coverage area of the park should be reduced to accomodate a parking lot. Since the fence on the shortest boundary was already constructed, the length of the boundary covered by Raju in 90min was reduced by 60% & the longest was modified accordingly so that the park still remained triangular in shape.1) How much time will Raju take to run along the boundary of the garden thus formed? 120min, 148min, 128min, 160min, 144min2) If Raju's speed was 15metres/min, what is the approx area of the parking lot (in km^2)? 0.39, 0.28, 0.29, 0.45, 0.52Plz post the solution as well or else it wont be of any help.
@Subhashdec2 said:since it is a general question i think we can take any value of n and solvelets take n=22^2013factors in the range of (1,2013)=2^0,2^1.....2^10=11 factorsin the range of [2^2012,2^2013]=2 factos only11:2no OA is matching here
@Subhashdec2 said:since it is a general question i think we can take any value of n and solvelets take n=22^2013factors in the range of (1,2013)=2^0,2^1.....2^10=11 factorsin the range of [2^2012,2^2013]=2 factos only11:2no OA is matching here