@Marchex said:Find the remainder when 55^104^297 divided by 17 ??
1??
euler of 17=16
55^16k mod 17
so remainder =1
euler of 17=16
55^16k mod 17
so remainder =1
Q2: find the sum= 1/2 + 1/6 + 1/12 + 1/20 + .........+ ......infinity
@viewpt said:Q:find R if 123456789101112..........484950 is div 16 ???
16 =2^4
check with last four digit only
4950 mod 16 = 6
check with last four digit only
4950 mod 16 = 6
@Marchex said:Find the remainder when 55^104^297 divided by 17 ??
55/17 = 4
55*55/17 = 16
55*55*55/17 = 13
55^4/17 = 1
55^5 = 4
and the pattern for the remainder repeats
since 104^297 = 4k
=> 55^(4k)/17 = 1 remainder
@viewpt said:Q2: find the sum= 1/2 + 1/6 + 1/12 + 1/20 + .........+ ......infinity
sum = 1-1/2 + 1/2-1/3 +1/3-1/4 +.....infinity
=> sum = 1 as all other terms cancel each other
@viewpt said:Q2: find the sum= 1/2 + 1/6 + 1/12 + 1/20 + .........+ ......infinity
1 hai kya iska??
1-1/2+1/2-1/3+1/3-1/4.....1/n - 1/(n+1)
1- 1/(n+1)
approximately 1???
1-1/2+1/2-1/3+1/3-1/4.....1/n - 1/(n+1)
1- 1/(n+1)
approximately 1???
@viewpt said:Q2: find the sum= 1/2 + 1/6 + 1/12 + 1/20 + .........+ ......infinity
we can expand this 1-1/2 + 1/2 -1/3 +1/3 -1/4 +1/4 -1/5 .....................infinity
everything will cancel except 1 so and is 1
everything will cancel except 1 so and is 1
@Marchex said:we can expand this 1-1/2 + 1/2 -1/3 +1/3 -1/4 +1/4 -1/5 .....................infinityeverything will cancel except 1 so and is 1
i guess all the terms will not cancel each other ,,the last term,,dat is 1/(n+1) remains,,
but it will be negligible when tends to infinity,,
so 1 - 1/(n+1) = 1,,i guess
but it will be negligible when tends to infinity,,
so 1 - 1/(n+1) = 1,,i guess
@viewpt said:Q: 6^99+ 8^99 div by 49, R???
14..
used binomial----6^99 = -1 + 99c1*7 + factors of 7^2
8^99 = 1 + 99c1*7 + factors of 7^2
hence 14
What is the number of non negative integer solution for the equation x^2-xy+Y^2 =X+Y ???
@chevy said:i guess all the terms will not cancel each other ,,the last term,,dat is 1/(n+1) remains,,but it will be negligible when tends to infinity,,so 1 - 1/(n+1) = 1,,i guess
:)
1/(infinity)= 0
so 1/(infinity+1) = 0
last term doesnt need cancellation ....
Q: if 653xy is divisible by 80 then the value of x+y is:???
@viewpt said:Q: if 653xy is divisible by 80 then the value of x+y is:???
80 =8*10
last digit should be 0 so y=0
and for 8 last three digit should be divisible by 8
53X should be divisible by 8
X can take 6
X+Y =6+0 =6
ABC is a 3 digit number with distinct digits. If it is known that 3 — ABC is equal to another 3 digit number CCC, then what is the value of B?
(a) 1 (b) 3 (c) 5 (d) 8
(a) 1 (b) 3 (c) 5 (d) 8