Official Quant thread for CAT 2013

MBA CAT 2024
29225
@albiesriram said:
draw a semicircle with dia =RQ, The area coming outside the semi circle will always form an acute angle. (as we know the angle formed by the dia is 90 deg.)
therefore, if "a" is the length of the side of the square.
Area of sq=a^2
area outside the semicircle= a^2-[(pi*a^2)/8]
therefore prob= [a^2-{(pi*a^2)/8}]/a^2= 1-(pi/8)
29226
@Subhashdec2 said:
is it 3/4 for the first one


bro, it will be obtuse for the region coming under the semicircle with dia RQ.
29227
@Zedai said:
bro, it will be obtuse for the region coming under the semicircle with dia RQ.
yea man u are correct...:)
nice work...:)
29228

The vertices of a regular 10-gon are labeled V1,V2,…Vn, which is a permutation of {1,2,…,10}. Define a neighboring sum to be the sum of 3 consecutive vertices Vi,Vi+1 and Vi+2 [whereV11=V1,V12=V2]. For each permutation σ, let Nσdenote the maximum neighboring sum. As σ ranges over all permutations, what is the minimum value of Nσ?


Details and assumptions

If the integers are written as 1,2,3,4,5,6,7,8,9,10 around the circle, then the neighboring sums are 6,9,12,15, 18,21,24, 27,20,13, and the maximum neighboring sum is 27.
29229
@Logrhythm said:
hahahah....i remember i did that in an interview when i asked "what is your fav subject" i replied "math" and uske baad it was a colossal fiasco.....pata nahi usko laga meine math bola toh mein Aryabhatt hun

ok, no spamming

q) what is the highest power of 12 that divides (5^36 - 1)
1,2,3,4
after binomial expansion, the highest it will have will be 2
29230
@Tusharrr said:
The vertices of a regular 10-gon are labeled V1,V2,…Vn, which is a permutation of {1,2,…,10}. Define a neighboring sum to be the sum of 3 consecutive vertices Vi,Vi+1 and Vi+2 [whereV11=V1,V12=V2]. For each permutation σ, let Nσdenote the maximum neighboring sum. As σ ranges over all permutations, what is the minimum value of Nσ?Details and assumptionsIf the integers are written as 1,2,3,4,5,6,7,8,9,10 around the circle, then the neighboring sums are 6,9,12,15, 18,21,24, 27,20,13, and the maximum neighboring sum is 27.

Has to be more than16.5 anyway (overall average of all permutations)...

I can manage 18, with trial and error...10, 6, 2, 9, 4, 5, 3, 8, 7, 1

17 check maarna hoga...:(

regards
scrabbler
29231
@Subhashdec2 said:
is it 3/4 for the first one
Bhai no oa available but zedai bhai's answer seems perfect.
29232
@Buck.up said:
What is the remainder when 72!/36! is divided by 73.
27
29234
5 PASSENGERS ARE ON A TRAIN AND 6 STATIONS are there continuously,what is the probability that 5 passengers step down at different stations?
29235

Find the highest power of 3 in the following expression:

( 58! - 38! )
a. 17 b. 18 c. 19 d. None of These

29236
@goldenbullet said:
Find the highest power of 3 in the following expression:( 58! - 38! )a. 17 b. 18 c. 19 d. None of These
i think we have to find the maximum power of 38! that is 17

29237
@goldenbullet said:
Find the highest power of 3 in the following expression:( 58! - 38! )a. 17 b. 18 c. 19 d. None of These
17 ..
38![****] /3
hence 17 ans
29238
@Marchex said:
5 PASSENGERS ARE ON A TRAIN AND 6 STATIONS are there continuously,what is the probability that 5 passengers step down at different stations?
6P5/6^5??
29239
@Marchex : is the answer 6P5/6^5??
29240
@viewpt said:
6^5?? or 30???
@goldenbullet said:
@Marchex : is the answer 6P5/6^5??
ans is 5/54


A watchmaker has 5 watches with him one day. He knows only 3 of the 5 watches are defected. So first he decided to identify all defected watches then to repair. He began to identify defective watches one by one. What is the probability that he will identify all 3 defected watches in exactly 3 attempts.
29241
@Marchex said:
ans is 5/54A watchmaker has 5 watches with him one day. He knows only 3 of the 5 watches are defected. So first he decided to identify all defected watches then to repair. He began to identify defective watches one by one. What is the probability that he will identify all 3 defected watches in exactly 3 attempts.
3/10
29242
Q: 6^99+ 8^99 div by 49, R???
29243
@viewpt said:
3/10
right
please explain it
29244
@viewpt said:
Q: 6^99+ 8^99 div by 49, R???
14 or 35, whatever comes in the option.
29245
@Marchex said:
right please explain it


jus find out the prob of the following O= OK; D=defected , please.
P(O,D,O) Or P(D,D,D) or P(D,O,O)