no actuually u can see that difference between 36-8 and 64-36 is same as graph of this function is nothing but between 8 and 64 it must be symetrical between the two.had the difference between the roots not be same nothing could be said but here it must be symetrical
Symmetrical between 8 and 64 yes but not between 8 and 36....
It is (x-8)(x-36)(x-36)(x-64) ka root...
Check this link....also look at my solution on page 1477...reply 29525
@Buck.up@Logrhythm said:hahahah....i remember i did that in an interview when i asked "what is your fav subject" i replied "math" and uske baad it was a colossal fiasco.....pata nahi usko laga meine math bola toh mein Aryabhatt hunok, no spammingq) what is the highest power of 12 that divides (5^36 - 1)1,2,3,4 2?
@Buck.up@Logrhythm said:hahahah....i remember i did that in an interview when i asked "what is your fav subject" i replied "math" and uske baad it was a colossal fiasco.....pata nahi usko laga meine math bola toh mein Aryabhatt hunok, no spammingq) what is the highest power of 12 that divides (5^36 - 1)1,2,3,42?can u plz explain??
is this correct ?
12 is a factor of (5^36-1)
so, (5^36-1)=12^k
5^36=12^k+1
last digit of 5^36=5
so last digit of 12^k has to be 4 which is possible with k=2 (from options)
@Buck.up@Logrhythm said:hahahah....i remember i did that in an interview when i asked "what is your fav subject" i replied "math" and uske baad it was a colossal fiasco.....pata nahi usko laga meine math bola toh mein Aryabhatt hunok, no spammingq) what is the highest power of 12 that divides (5^36 - 1)1,2,3,42?can u plz explain??
is this correct ?12 is a factor of (5^36-1)so, (5^36-1)=12^k5^36=12^k+1last digit of 5^36=5so last digit of 12^k has to be 4 which is possible with k=2 (from options)
is this correct ?12 is a factor of (5^36-1)so, (5^36-1)=12^k5^36=12^k+1last digit of 5^36=5so last digit of 12^k has to be 4 which is possible with k=2 (from options)
@chillfactor@Tusharrr said:Suppose there are 10 coins laid out in front of you. All of the coins are fair (i.e. have an equal chance of heads or tails) except one, which flips to heads every time. You draw one coin at random and flip it 5 times. If each of the 5 flips results in heads, then the probability that this coin is fair can be written as a/b, where a and bare coprime positive integers. What is the value of a+b? probability of getting 5 heads = (1/10)(9*1/32 + 1) = 41/320 Probability that a fair coin is selected and we get 5 heads = (1/10){9*(1/32)} = 9/320 required prob = (9/320)/(41/320) = 9/41
is this correct ?12 is a factor of (5^36-1)so, (5^36-1)=12^k5^36=12^k+1last digit of 5^36=5so last digit of 12^k has to be 4 which is possible with k=2 (from options)
awesome, well played with the options....should have thrown in a 0 😛
meine saare bracket ko open kar kar kara, but your method dekh kar mazza aa gaya
Happy birthday Bhai. Today is your bday na.I know this is not a reliable. Thats why I was nt sure of my ans. but it seems (5^36-1) is a factor of 12 only
In a locality there are ten houses in a row. On a particular night a thief planned to steal from three houses of the locality. In how many ways can he plan such that no two of them are adjacent to each other.
@Buck.up@Logrhythm said:hahahah....i remember i did that in an interview when i asked "what is your fav subject" i replied "math" and uske baad it was a colossal fiasco.....pata nahi usko laga meine math bola toh mein Aryabhatt hunok, no spammingq) what is the highest power of 12 that divides (5^36 - 1)1,2,3,42?can u plz explain??
hahahah....i remember i did that in an interview when i asked "what is your fav subject" i replied "math" and uske baad it was a colossal fiasco.....pata nahi usko laga meine math bola toh mein Aryabhatt hun ok, no spammingq) what is the highest power of 12 that divides (5^36 - 1) 1,2,3,4
