Official Quant thread for CAT 2013

@jain4444 said:
A cube has 8 vertices. For each pair of distinct vertices, we connect them up with a line segment. There are C(8 , 2) = 28 such line segments. For each of these 28 line segments, we mark the midpoint. How many distinct points have been marked as the midpoints ?
19.this question has been done before.
@KhannaiiM yes i have asked
@Subhashdec2 said:
28-6-3=19??
what's this 6 & 3 subtracted for.?
@The_Loser said:
what's this 6 & 3 subtracted for.?
on each of the 6 faces two diagonals will bisect each other so there is a common point, so minus 6.
now consider body diagonals... there will be 4 of them and all will meet at the same point . so minus 3
@The_Loser said:
what's this 6 & 3 subtracted for.?
3 for body diagnols(there will be 4 in total)

1 each for the face diagnol 1*6=6
ABCD is a square where M and N are midpoints of AD and CD, respectively. If sin ˆ MBN=a/b, where a and b are coprime positive integers, what is the value of a+b?
@jain4444 said:
ABCD is a square where M and N are midpoints of AD and CD, respectively. If sin ˆ MBN=a/b, where a and b are coprime positive integers, what is the value of a+b?
8? I get 3/5...

regards
scrabbler

@jain4444 said:
ABCD is a square where M and N are midpoints of AD and CD, respectively. If sin ˆ MBN=a/b, where a and b are coprime positive integers, what is the value of a+b?
8?
@jain4444 said:
ABCD is a square where M and N are midpoints of AD and CD, respectively. If sin ˆ MBN=a/b, where a and b are coprime positive integers, what is the value of a+b?
Let side of square be a

NB=rt(5)*a/2
MB=rt(5)*a/2
MN=rt(2)*a/2

Apply cosine law
cos/_MBN=4/5
Sin/_MBN=3/5

a+b=8
@jain4444 said:
ABCD is a square where M and N are midpoints of AD and CD, respectively. If sin ˆ MBN=a/b, where a and b are coprime positive integers, what is the value of a+b?
3/5
a+b=8
A speaks truth in 60% of the cases and b in 90% of the cases. In what percentage of cases are they likely to contradict each other in stating the same fact?
@albiesriram said:
A speaks truth in 60% of the cases and b in 90% of the cases. In what percentage of cases are they likely to contradict each other in stating the same fact?
42%?

.6 *.1 + .9 * .4

regards
scrabbler

@albiesriram said:
A speaks truth in 60% of the cases and b in 90% of the cases. In what percentage of cases are they likely to contradict each other in stating the same fact?
((60 * 10) + (40 * 90))/100 = 42% ?
@albiesriram said:
A speaks truth in 60% of the cases and b in 90% of the cases. In what percentage of cases are they likely to contradict each other in stating the same fact?
1 - (.6*.9 + .1 * .4)= .42
@albiesriram said:
D
@Dexian said:
D
OA says B.
@albiesriram said:
B.....

What is the approach to this problem???

@KaranGarcia said:
What is the approach to this problem???
9! / (6!)( 3!) = 84