Official Quant thread for CAT 2013

If K is a perfect square, the root of the equation 4KX^2 + 4SQRTkX -K=0 are
real
complex
irrational
if the price of a book goes down by20 per dozen a person can buy 50 dozen books more for 30,000. Find the original price of the book.


@grkkrg said:
x = 5.5So 4.5 + 3.5 + 2.5 + 1.5 + 0.5 + 1.5 + 2.5 + 3.5 + 4.5 = 24.5?
you forgot 5.5-5 or 5.5-6 tabhi 0.5 missing hai, 5.5 pe bhi 25 aayega bhai

@2013IsMine
@vbhvgupta said:
If K is a perfect square, the root of the equation 4KX^2 + 4SQRTkX -K=0 arerealcomplexirrational
irrational ??
@Logrhythm said:
irrational ??
bhai ans nahi hai explain kar do.
@vbhvgupta said:
bhai ans nahi hai explain kar do.
i took k as 4

equation banayi - 16x^2 + 8x - 4 = 0

roots = 1/4*(sqrt(5) - 1) or 1/4*(-sqrt(5) - 1)

vbhvgupta

irrational
@MBAVichar said:
Wots the answer for this one ? I am getting 648 ? Question reference: reply no 27245 Page1363 ..
432
@vbhvgupta said:
if the price of a book goes down by20 per dozen a person can buy 50 dozen books more for 30,000. Find the original price of the book.
x dozen books
y per dozen price
xy=30000
(x+50)(y-20)=30000
50y-20x=1000
5y-2x=100
x=5y/2-50

(5y/2-50) y =30000
(y/2 -10)y=6000
price of a book be z

12z(6z-10)=6000
z(6z-10)=500
z(3z-5)=250
3z^2-5z-250=0
3z^2-30z+25z-250=0
(z-10)(3z+25)=0

z=10
@vbhvgupta Irrational
5 boys and 5 girls go to watch Mughleazam in PVR Saket. They are to sit in 10 adjacent chairs but every boy wish to have girls only as his neighbours. In how many ways they can be seated so that wish of every boy comes true?


Arrange boys first = 5! ways
Let the seating arrangement be : BXBXBXBXB
Now the wish to be true X has to be occupied by 4 girls , can de done in = 5C4 * 4!
The scene is BGBGBGBGB now one girl can be anywhere
XBXGXBXGXBXGXBXGXBX , in 10C1 way

so total ways = 5! * 5! * 10 ways

am I wrong ? should the ans be
5! * 5! * 2 ways ?
@amresh_maverick said:
5 boys and 5 girls go to watch Mughleazam in PVR Saket. They are to sit in 10 adjacent chairs but every boy wish to have girls only as his neighbours. In how many ways they can be seated so that wish of every boy comes true?Arrange boys first = 5! ways Let the seating arrangement be : BXBXBXBXBNow the wish to be true X has to be occupied by 4 girls , can de done in = 5C4 * 4! The scene is BGBGBGBGB now one girl can be anywhere XBXGXBXGXBXGXBXGXBX , in 10C1 wayso total ways = 5! * 5! * 10 waysam I wrong ? should the ans be 5! * 5! * 2 ways ?
_ B_B_B_B_B_
5 boys 6 spaces
6 spaces to be filled by 5 girls
a+b'+c'+d'+e'+f=5
b,c,d,e has to be 1
a+b+c+d+e+f=1
6 solutions

5!*5!*6
@Subhashdec2 said:
_ B_B_B_B_B_5 boys 6 spaces6 spaces to be filled by 5 girlsa+b+c+d+e+f=5b,c,d,e has to be 1a+b+c+d+e+f=16 solutions5!*5!*6
sir ji ,what is the error in my sol ?
@vbhvgupta said:
if the price of a book goes down by20 per dozen a person can buy 50 dozen books more for 30,000. Find the original price of the book.
10 ??

Subhashdec2

acc to your arrangement xbxbxbbxbx...is also a valid solution...dreams of boys aren't coming true.
@amresh_maverick
bhai maan lo 2 ladki hai A aur B
to agar tum A ko alag kar ke 10C1 ways mein bithaoge...aur fir B ko alag kar ke 10c1 ways mein bithaoge to cases repeat honge
jaise ki aXbXcXdXeX koi arrangemnt hai
to jab a ko alag kar ke 10c1 ways mein bithaoge to ye arrangement aayega
aur fir b,c,d,e k saath bhi aayega.
i.e 5 cases for 1 case . divide by 5

@psk.becks said:
Subhashdec2acc to your arrangement xbxbxbbxbx...is also a valid solution...dreams of boys aren't coming true.@amresh_maverickbhai maan lo 2 ladki hai A aur Bto agar tum A ko alag kar ke 10C1 ways mein bithaoge...aur fir B ko alag kar ke 10c1 ways mein bithaoge to cases repeat hongejaise ki aXbXcXdXeX koi arrangemnt haito jab a ko alag kar ke 10c1 ways mein bithaoge to ye arrangement aayegaaur fir b,c,d,e k saath bhi aayega.i.e 5 cases for 1 case . divide by 5
bhai mere mein xbxbxbbxbx nahi true h
coz d has to be 1 atleast in mine
check again
@amresh_maverick said:
5 boys and 5 girls go to watch Mughleazam in PVR Saket. They are to sit in 10 adjacent chairs but every boy wish to have girls only as his neighbours. In how many ways they can be seated so that wish of every boy comes true?Arrange boys first = 5! ways Let the seating arrangement be : BXBXBXBXBNow the wish to be true X has to be occupied by 4 girls , can de done in = 5C4 * 4! The scene is BGBGBGBGB now one girl can be anywhere XBXGXBXGXBXGXBXGXBX , in 10C1 wayso total ways = 5! * 5! * 10 waysam I wrong ? should the ans be 5! * 5! * 2 ways ?
6C5 *5!*5! =6*5!*5!
@amresh_maverick said:
5 boys and 5 girls go to watch Mughleazam in PVR Saket. They are to sit in 10 adjacent chairs but every boy wish to have girls only as his neighbours. In how many ways they can be seated so that wish of every boy comes true?Arrange boys first = 5! ways Let the seating arrangement be : BXBXBXBXBNow the wish to be true X has to be occupied by 4 girls , can de done in = 5C4 * 4! The scene is BGBGBGBGB now one girl can be anywhere XBXGXBXGXBXGXBXGXBX , in 10C1 wayso total ways = 5! * 5! * 10 waysam I wrong ? should the ans be 5! * 5! * 2 ways ?
B G B G B G B G B G....or.....G B G B G B G B G B

5!*5! + 5!*5! = 2*5!*5! ?
@amresh_maverick said:
5 boys and 5 girls go to watch Mughleazam in PVR Saket. They are to sit in 10 adjacent chairs but every boy wish to have girls only as his neighbours. In how many ways they can be seated so that wish of every boy comes true?
5! x 5! x 2
@amresh_maverick said:
5 boys and 5 girls go to watch Mughleazam in PVR Saket. They are to sit in 10 adjacent chairs but every boy wish to have girls only as his neighbours. In how many ways they can be seated so that wish of every boy comes true?Arrange boys first = 5! ways Let the seating arrangement be : BXBXBXBXBNow the wish to be true X has to be occupied by 4 girls , can de done in = 5C4 * 4! The scene is BGBGBGBGB now one girl can be anywhere XBXGXBXGXBXGXBXGXBX , in 10C1 wayso total ways = 5! * 5! * 10 waysam I wrong ? should the ans be 5! * 5! * 2 ways ?
bhai in ur sol
u cannot create spaces between B and G

it can be like this
XBGXBGXBGXBGXBGX
6c1 hoga rather than 10c1