Ans- (10.9.8.7).4/(40.39.38.37)
@jain4444 said:The sum of absolute values of all real numbers x, such that both of the fractions (x^2+4x−17)/(x^2−6x−5) and (1−x)/(1+x) are integers, can be written as a/b, where a and b are coprime positive integers. What is the value of a+b ?
@jain4444 Can you provide solution for this question. Im getting it as 1 but im not sure.
If all 25 are Heads then we have 24 cases
If 24 are heads and one tail then we have to arrange in 24C1 ways and each case will have 22 sub cases(consecutive HH pairs) except 2 of those cases where the tails appears at the start and end. In those cases, there will be 23 consecutive pairs....
so on...this will take a LOT of time and will generate a lot of cases..
btw, what do you mean by expected number?
@Tusharrr@VJ12 said:@Subhashdec2 Pl share solutionThere is some method with n(n+1)/2.
area of the triangle is 1/2 *10sqrt(2)*10sqrt(2)=100
it is the same as area of a square with sides 10
draw a square with x=0 y=0 x=10 and y=10
no of integral points will be 11*11=121
@Tusharrr said:question Plse answer-25 independent, fair coins are tossed in a row. What is the expected number of consecutive HH pairs?DetailsIf 6 coin tosses in a row give HHTHHH, the number of consecutive HH pairs is 3.
WRONG SOLUTION
@Faruq said:For pairs there should be at least 2 heads2 consecutive heads and rest tails -> 24 ways3 consecutive heads and rest tails -> 23 ways *2 =46 ways4 consecutive heads and rest tails -> 22 ways *3 =66 ways5 consecutive heads and rest tails -> 21 ways *4 =84 ways6 consecutive heads and rest tails -> 20 ways *5 =100 ways.....................24 consecutive heads and rest tails -> 2 ways *23 =46 ways25 consecutive heads and no tails -> 1 ways *24 =24 waysTotal 24 terms-n^2 + 25n-(24*25*49)/6 + 25(24*25)/2 = 2600
i m not sure abt the ubderlined part
2 consecutive heads means 3 heads in total so 22 tails.........
correct me if i m wrong..
@Faruq The ans is within integer value of 1 to 999
And 2600 are different outcome we can divide by no of ways
@Faruq said:For pairs there should be at least 2 heads2 consecutive heads and rest tails -> 24 ways3 consecutive heads and rest tails -> 23 ways *2 =46 ways4 consecutive heads and rest tails -> 22 ways *3 =66 ways5 consecutive heads and rest tails -> 21 ways *4 =84 ways6 consecutive heads and rest tails -> 20 ways *5 =100 ways.....................24 consecutive heads and rest tails -> 2 ways *23 =46 ways25 consecutive heads and no tails -> 1 ways *24 =24 waysTotal 24 terms-n^2 + 25n-(24*25*49)/6 + 25(24*25)/2 = 2600
yaar isme wo case kaha aaya if there are two heads then a tail them 3 consecutive heads then all tails
as in if there is a combination of consecutive heads separated by tails
@Tusharrr said:@Faruq The ans is within integer value of 1 to 999 And 2600 are different outcome we can divide by no of ways
yes this is the different outcome or total no. of ways with the given condition
@Subhashdec2 said:yaar isme wo case kaha aaya if there are two heads then a tail them 3 consecutive heads then all tailsas in if there is a combination of consecutive heads separated by tails
nahin hai bhai 
EDIT KAR DIYA BHAI
EDIT KAR DIYA BHAIokk Try This
ABC is a triangle with ∠BAC=60∘,AB=5 and AC=25. D is a point on the internal angle bisector of ∠BAC such that BD=DC. What is AD^2?
Details and assumptions
It is not stated that D lies on BC. This assumption is not necessarily true
It is not stated that D lies on BC. This assumption is not necessarily true
@Faruq said:bilkul but pata nahin kaise ???
wahi to baat h...:P
tabhi to kisine hilaya nahi ab tak wo question..:D
If one of the root of the equation x^2-10x+16=0 is half of one of the root of the equation x^2-4Rx+16=0 Find R such that both the equation have integral roots