the square of the sum of the roots of a quadratic equation E is 8 times the product of its roots. Find the value of the square of the sum of the rootsdivided by the product of the roots of the equation whose roots are reciprocals of those of E.
34692 (2 numbers) 23469 ( 2 numbers) 46923 69234 92346 there is a cyclicity of 5 digits in each case 2007 mod 5 = 2 now here we can make extra case by having last 2 digits as 17 or 51 which is only possible in 1st two cases so , in total 7 such numbers are possible @Logrhythm@ScareCrow28@RDN
@albiesriramIs it (c) 6 ?For first two no's 12 , difference is 1.for first four no's 1234, diff is 2,for first 6 no's 123456, diff is 3..for 100 no's diff is 5050/11 = 6.
if i calculate manually i am getting difference as 41..
sum of odd positioned digits 1+3+5+7+9+(0+1+2+...9)*9 =430 sum of even positioned digits 2+4+6+8+(1+1+...10times)+(2+2+...10times)+....+(9+9+..10times) + 1 =471
if i calculate manually i am getting difference as 41..sum of odd positioned digits 1+3+5+7+9+(0+1+2+...9)*9 =430sum of even positioned digits 2+4+6+8+(1+1+...10times)+(2+2+...10times)+....+(9+9+..10times) + 1=471so diff is 41where i m going wrong ?
correct hai.. now divide the 41 by 11.. remiander kya aayega?
but is method seFor first two no's 12 , difference is 1.for first four no's 1234, diff is 2,for first 6 no's 123456, diff is 3..for 100 no's diff is 50difference 50 aa raha hai..but i m getting 41..
is this the ques where all nos from 1 to 100 are written and we have to calculate mod 11?
yup it is, the answer provided by ever1 first was 6 but it is 8, chillfactor , me and 1 more guy gave 8 as answer which lead to confusion but later it was confirmed that the answer is 8 :)
yup it is, the answer provided by ever1 first was 6 but it is 8, chillfactor , me and 1 more guy gave 8 as answer which lead to confusion but later it was confirmed that the answer is 8
how is it 8
10^n=-1 if n is odd
+1 if n is even
tell me where m i wrong
12345......100 -1+2-3+4-5+6-7+8-9+(-10-11-12-....-99) +100 mod 11 -5-(45*109) +100 mod 11 -5 +1+1 -3 8
In the figure given below, ABCD is a rectangle, DE : EC = 5 : 4 and CF : FD = 8 : 1. If the area of the quadrilateral APFD is 49 square units, then find the area of the quadrilateral BPEC (in square units). a 86 b 87 c 88 d 85
